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• LaTeX:Symbols
  |<math>{\l}</math>||{\l}||<math>{\ss}</math>||{\ss}||<math>\text{!`}</math>||!` |<math>{\L}</math>||{\L}||<math>{\SS}</math>||{\SS}||
  16 KB (2,307 words) - 20:13, 5 July 2024
• 2006 AIME I Problems/Problem 10
  ...des <math> \mathcal{R} </math> into two regions of equal area. Line <math> l </math>'s equation can be expressed in the form <math> ax=by+c, </math> whe ...ork with whatever is remaining. By now you should have 4 circles making an L shape (waluigi style). Now the two biggest contenders for this method are t
  4 KB (731 words) - 17:59, 4 January 2022
• 2003 AMC 12A Problems
  Points <math>K, L, M,</math> and <math>N</math> lie in the plane of the square <math>ABCD</ma pair K=(0,1.366), L=(1.366,0), M=(0,-1.366), N=(-1.366,0);
  13 KB (1,955 words) - 21:06, 19 August 2023
• 2003 AMC 12B Problems
  real l = 5*sqrt(3); pair ab = (h+l)*dir(72), bc = (h+l)*dir(54); ...), BC = (bc.x,h+bc.y), CD = (-bc.x,h+bc.y), DE = (-ab.y, h-ab.x), EA = (0,-l);
  13 KB (1,987 words) - 18:53, 10 December 2022
• 2006 AMC 12B Problems/Problem 21
  real l=10, ang=asin(w/sqrt(l*l+w*w))*180/pi;
  2 KB (339 words) - 13:15, 12 July 2015
• Root (polynomial)
  ...then the [[Inverse of a function|inverse]] <math>L^{-1}(a)</math> of <math>L(x)</math> at <math>a</math> must be a rational root of <math>P(x)</math>.
  8 KB (1,427 words) - 21:37, 13 March 2022
• 2022 USAJMO Problems/Problem 1
  <cmath>(1)\iff g_l\not\equiv g_{l-1}\pmod{m}\text{ for any integer }l>1</cmath> <cmath>\iff g_{l-1}(r-1)\not\equiv 0\pmod{m}.\text{ (3)}</cmath>
  5 KB (883 words) - 01:05, 2 June 2024
• 2005 AIME I Problems/Problem 13
  ...range from <math>l = 5</math> to <math>9</math>; notice that <math>d = 10-l</math> gives the number of diagonals. Let <math>R</math> represent a move t
  5 KB (897 words) - 00:21, 29 July 2022
• 2005 AIME II Problems/Problem 15
  real l(real x) {return sqrt(69)*x/10;} path g=graph(l,-7,14);
  12 KB (2,000 words) - 13:17, 28 December 2020
• 2004 AIME I Problems/Problem 15
  <cmath>\begin{array}{c|l}
  9 KB (1,491 words) - 01:23, 26 December 2022
• 2004 AIME I Problems/Problem 14
  pair L = 8*expi(pi+0.05), R = 8*expi(-0.22); /* left and right cylinder lines, num draw((L.x,L.y,0)--(L.x,L.y,h)); draw((R.x,R.y,0)--(R.x,R.y,h));
  4 KB (729 words) - 01:00, 27 November 2022
• 2004 AIME I Problems/Problem 2
  <cmath>\frac{m(f + l)}{2} = 2m</cmath> Where <math>f</math> and <math>l</math> represent the first and last terms of <math>A</math>. This comes fr
  8 KB (1,437 words) - 21:53, 19 May 2023
• 2004 AIME II Problems/Problem 7
  ...4}</math>, and so the equation of <math>BB'</math> is <math>y -25 = \frac{-l}{14}x</math>. Let the point of intersection of <math>EF, BB'</math> be <mat \frac{14}{l}x &= y-8 = \frac{9}{2}\\
  9 KB (1,501 words) - 05:34, 30 October 2023
• 2004 AIME II Problems/Problem 3
  ...ear that the way to minimize <math>l\cdot m\cdot n</math> is to make <math>l</math> and <math>m</math> and <math>n</math> as close together as possible, ...es is <math>lmn-lm-mn-ln+l+m+n-1</math>, which can be factored into <math>(l-1)(m-1)(n-1)</math>.
  2 KB (377 words) - 11:53, 10 March 2014
• 1988 AIME Problems
  ...lled a mean line for the points <math>w_1, w_2, \dots, w_n</math> if <math>L</math> contains points (complex numbers) <math>z_1, z_2, \dots, z_n</math>
  6 KB (902 words) - 08:57, 19 June 2021
• 1992 AIME Problems
  ...smallest positive integer <math>m^{}_{}</math> for which <math>R^{(m)}(l)=l^{}_{}</math>.
  8 KB (1,117 words) - 05:32, 11 November 2023
• 1993 AIME Problems
  ...int, then <math>P_{n + 1}^{}</math> is the midpoint of <math>\overline{P_n L}</math>. Given that <math>P_7 = (14,92)\,</math>, what is <math>k + m\,</m
  8 KB (1,275 words) - 06:55, 2 September 2021
• 1983 AIME Problems/Problem 11
  ...en = black+linewidth(0.65); pointpen = black; pen d = linewidth(0.65); pen l = linewidth(0.5); draw(E--(E.x,E.y,0),dashed+l);
  6 KB (971 words) - 15:35, 27 May 2024
• 1983 AIME Problems/Problem 15
  ...h> to <math>KO</math> and call its intersection with <math>KO</math> <math>L</math>. Clearly, <math>KO = \sqrt{OC^2-KC^2} = \sqrt{5^2-3^2} = 4</math> an
  20 KB (3,497 words) - 15:37, 27 May 2024
• 1985 AIME Problems/Problem 4
  ...{2n^2 - 2n + 1}</math>, so the parallelogram has height <math>h = \frac{A}{l} = \frac{1}{\sqrt{2n^2 - 2n + 1}}</math>. But the height of the parallelog
  3 KB (484 words) - 21:40, 2 March 2020

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