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Page title matches
- ==Problem==1 KB (189 words) - 15:55, 21 January 2024
- #REDIRECT [[2016 AMC 10A Problems/Problem 9]]45 bytes (5 words) - 12:58, 4 February 2016
- == Problem == (B) <math>36-48x^2 + 14x^4-x^6</math>639 bytes (108 words) - 01:41, 14 January 2019
- ==Problem== ...that <math>5</math> and <math>4</math> work the best as we can't use <math>6</math> and <math>3</math>. Finally, we use <math>2</math> and <math>1</math2 KB (365 words) - 12:47, 2 July 2023
- ==Problem== <math>\textbf{(A)}\ 4\qquad\textbf{(B)}\ 6\qquad\textbf{(C)}\ 8\qquad\textbf{(D)}\ 10\qquad\textbf{(E)}\ 16</math>919 bytes (154 words) - 18:47, 4 August 2017
- ==Problem== real c=8.1,a=5*(c+sqrt(c^2-64))/6,b=5*(c-sqrt(c^2-64))/6;14 KB (2,397 words) - 20:04, 27 August 2023
- ==Problem== For polynomial <math>P(x)=1-\dfrac{1}{3}x+\dfrac{1}{6}x^{2}</math>, define2 KB (426 words) - 16:09, 21 July 2023
- ==Problem==4 KB (769 words) - 20:24, 16 March 2019
- #REDIRECT [[2011 USAMO Problems/Problem 4]]43 bytes (4 words) - 21:25, 16 April 2016
- #REDIRECT [[2016 USAMO Problems/Problem 4]]43 bytes (4 words) - 16:41, 21 April 2016
- ==Problem== {{USAMO newbox|year=2016|num-b=5|aftertext=|after=Last Problem}}8 KB (1,516 words) - 10:11, 8 April 2023
- == Problem 6==702 bytes (92 words) - 20:37, 17 February 2020
- ==Problem 6==875 bytes (130 words) - 20:34, 1 April 2017
- == Problem 6 == \textbf{(C)}\ 6\qquad781 bytes (123 words) - 00:43, 20 February 2019
- ==Problem== Then the problem is equivalent to that there exists a way to assign <math>a_1,a_2,\cdots,a_{3 KB (522 words) - 13:54, 30 January 2021
- ==Problem== {{USAMO newbox|year=1996|num-b=5|after=Last Problem}}3 KB (584 words) - 07:56, 16 April 2018
- == Problem 6 ==717 bytes (123 words) - 16:45, 4 August 2016
- == Problem ==974 bytes (151 words) - 04:03, 13 January 2019
- == Problem 6 == .../math>, which is <math>\frac{96+80+72+68+66+65}{64}-7 = \frac{447}{64}-7 = 6\frac{63}{64}-7 = \boxed{\textbf{(A) } -\frac{1}{64}}</math>.686 bytes (80 words) - 13:05, 5 January 2017
- == Problem == draw((-0.5,6)--(10,6));2 KB (300 words) - 11:46, 20 June 2024
Page text matches
- == Problem == ...mum we can get is <math>1+2+3 = 6</math>, so we only need to try the first 6 numbers.12 KB (1,859 words) - 18:16, 28 March 2022
- == Problem == {{AIME box|year=1985|num-b=6|num-a=8}}1 KB (222 words) - 11:04, 4 November 2022
- == Problem == ...r this point it must continue to repeat. Thus, in particular <math>a_{j + 6} = a_j</math> for all <math>j</math>, and so repeating this <math>n</math>2 KB (410 words) - 13:37, 1 May 2022
- == Problem == ...> (since we know <math>a</math> is positive). Thus <math>c = 6^3 - 3\cdot 6 = \boxed{198}</math>.1 KB (205 words) - 18:58, 10 March 2024
- == Problem == f.p=fontsize(6);11 KB (1,722 words) - 09:49, 13 September 2023
- == Problem == ...th>\dbinom{6}{0} + \dbinom{6}{1} + \dbinom{6}{2} + \dbinom{6}{3} + \dbinom{6}{4}=57</math> of its subsets have at most four elements (the number of subs2 KB (364 words) - 19:41, 1 September 2020
- == Problem == ...first 16 triangular numbers, which evaluates to <math>\frac{(16)(17)(18)}{6} = \boxed{816}</math>.6 KB (872 words) - 16:51, 9 June 2023
- == Problem == pathpen = black; pointpen = black +linewidth(0.6); pen s = fontsize(10);11 KB (1,850 words) - 18:07, 11 October 2023
- == Problem == ...ctorization]] of <math>1000000 = 2^65^6</math>, so there are <math>(6 + 1)(6 + 1) = 49</math> divisors, of which <math>48</math> are proper. The sum of3 KB (487 words) - 20:52, 16 September 2020
- == Problem == ...owever, we must change it back to base 10 for the answer, which is <math>3^6 + 3^5 + 3^2 = 729 + 243 + 9 = \boxed {981}</math>.5 KB (866 words) - 00:00, 22 December 2022
- == Problem == The key to this problem is to realize that <math>n+10 \mid n^3 +1000</math> for all <math>n</math>.2 KB (338 words) - 19:56, 15 October 2023
- == Problem == <center><math>2x_1+x_2+x_3+x_4+x_5=6</math></center>1 KB (212 words) - 16:25, 17 November 2019
- == Problem == ...tan x \cdot \tan y = \frac{\tan x + \tan y}{30} = \frac{25}{30} = \frac{5}{6}</math>3 KB (545 words) - 23:44, 12 October 2023
- == Problem == ...sqrt{7}\right)\left(\sqrt{5}-\sqrt{6}+\sqrt{7}\right)\left(-\sqrt{5}+\sqrt{6}+\sqrt{7}\right).</cmath>3 KB (460 words) - 00:44, 5 February 2022
- == Problem == &= (x(x-6) + 18)(x(x+6)+18),7 KB (965 words) - 10:42, 12 April 2024
- == Problem == ...that <math>(n + \frac{1}{1000})^3 = n^3 + \frac{3}{10^3} n^2 + \frac{3}{10^6} n + \frac{1}{10^9}</math>. For a given value of <math>n</math>, if <math>(4 KB (673 words) - 19:48, 28 December 2023
- == Problem == ...or large factors of <math>2\cdot 3^{11}</math> which are less than <math>3^6</math>. The largest such factor is clearly <math>2\cdot 3^5 = 486</math>;3 KB (418 words) - 18:30, 20 January 2024
- == Problem == ...ains a [[point]] <math>P</math> for which <math>PA = 10</math>, <math>PB = 6</math>, and <math>\angle APB = \angle BPC = \angle CPA</math>. Find <math>1 KB (200 words) - 18:44, 5 February 2024
- == Problem == Since <math>91n - 104k < n + k</math>, <math>k > \frac{6}{7}n</math>. Also, <math>0 < 91n - 104k</math>, so <math>k < \frac{7n}{8}</2 KB (393 words) - 16:59, 16 December 2020
- == Problem == {{AIME box|year=1987|num-b=6|num-a=8}}3 KB (547 words) - 10:00, 18 June 2024
