Create the page "Similar(geometry)" on this wiki! See also the search results found.

• 2022 AIME I Problems/Problem 14
  ==The Geometry Part - Solution 1== ...ath>C</math>, so the splitting line is also parallel to this bisector, and similar for the splitting line through <math>N</math>. Some simple angle chasing re
  16 KB (2,730 words) - 02:56, 4 January 2023
• 2020 CIME I Problems/Problem 9
  ...</math>, respectively. We want to find <math>\frac{BP}{CP}</math> which by similar triangles is also equal to <math>\frac{BX}{C'Y}</math> from <math>\triangle [[Category:Intermediate Geometry Problems]]
  5 KB (589 words) - 11:18, 3 September 2021
• 2021 Fall AMC 10A Problems/Problem 22
  ...\overline{AB}</math> at point <math>F</math>.<math>\triangle AEF</math> is similar to <math>\triangle ACB</math>. Also, <math>AO</math> is the angle bisector Hence, we only need to analyze the following 2-d geometry problem: In <math>\triangle VOA</math> with <math>\angle O = 90^\circ</math
  8 KB (1,314 words) - 03:54, 5 July 2022
• 2020 IMO Problems/Problem 1
  A similar reasoning can be done for <math>OF,</math> the perpendicular bisector of <m [[Category:Olympiad Geometry Problems]]
  3 KB (464 words) - 08:29, 28 September 2023
• 2004 Pan African MO Problems/Problem 6
  To prove that <math>E'\in\omega_{AKB}</math>, we make a similar angle chase: <math>\angle AE'N' = \angle ADN' = \angle DAN' = \angle DAB</m [[Category:Olympiad Geometry Problems]]
  3 KB (572 words) - 13:48, 27 May 2024
• 2021 AMC 12A Problems/Problem 10
  Furthermore, by similar triangles: ...h> and <math>6y</math> (for some <math>x,y>1</math>), respectively. By the similar triangles discussed above, their heights must be <math>h_1x</math> and <mat
  9 KB (1,503 words) - 15:09, 1 August 2023
• 2021 AMC 12A Problems/Problem 17
  == Solution 1 (Similar Triangles and Pythagorean Theorem) == ...C</math> and <math>\triangle BDA</math> are both right triangles, they are similar by AA.
  10 KB (1,548 words) - 00:08, 12 February 2024
• 2021 AMC 12A Problems/Problem 24
  ==Solution 3 (Weighted Averages and Similar Triangles)== ==Solution 4 (Similar Triangles)==
  16 KB (2,539 words) - 16:24, 15 June 2024
• 2021 AMC 10A Problems/Problem 13
  Here is a similar problem from another AMC test: [[2015_AMC_10A_Problems/Problem_21|2015 AMC == Video Solution by Omega Learn (Using Pythagorean Theorem, 3D Geometry: Tetrahedron) ==
  3 KB (496 words) - 19:12, 28 October 2022
• Two poles formula
  ==Proof using similar triangles== ==Coordinate/analytical geometry proof==
  3 KB (506 words) - 19:31, 17 August 2021
• 2021 AMC 12B Problems/Problem 11
  ==Solution 1 (Analytic Geometry)== Using Stewart's Theorem we find <math>BP = 8\sqrt{2}</math>. From the similar triangles <math>BPA\sim DPC</math> and <math>BPC\sim EPA</math>, we have
  7 KB (1,184 words) - 07:55, 1 October 2021
• CEMC Euclid
  The Euclid covers many topics similar to the AMC 10. These include [[geometry]], [[trigonometry]], [[algebra]], [[number theory]], [[counting]], [[probab
  2 KB (273 words) - 15:09, 4 February 2024
• 2022 AIME II Problems/Problem 9
  import geometry; ...se one, let this point <math>P</math> be on line <math>\ell_B</math>. With similar reasoning, we see that the idea remains the same, except <math>s+1</math> l
  12 KB (2,025 words) - 14:56, 25 January 2024
• 2021 IMO Problems/Problem 4
  ...ath> are reflections of each other. Hence <cmath>XP = XJ = YM</cmath> By a similar argument on the reflection of <math>T</math> and <math>Z</math> we get <mat [[Category:Olympiad Geometry Problems]]
  7 KB (1,196 words) - 10:30, 18 June 2023
• 2023 AIME I Problems/Problem 5
  ==Solution 3 (Similar Triangles)== ==Solution 5 (Analytic Geometry)==
  19 KB (3,107 words) - 23:31, 17 January 2024
• AoPSWiki:Sandbox
  ...color I'll use an example from Week 3 Problem 5 in AoPS's Introduction to Geometry course. This is similar to #6 but it labels the angle with the arc.
  28 KB (4,808 words) - 19:43, 3 June 2022
• Vector analysis
  ...sis is often taken to be sub-field of [[Differential geometry|differential geometry]]. In terms of university course listings, it is common to use the word "ve ...ich <math>f</math> is increasing. As such, we can define the gradient in a similar way to divergence and curls as below:
  7 KB (1,189 words) - 06:00, 21 December 2022
• 2022 AMC 10A Problems/Problem 23
  ...Notice that <math>\frac{BC}{AD} = \frac{QC}{QD} = \frac{a}{a+b}</math> by similar triangles. [[Category:Intermediate Geometry Problems]]
  12 KB (1,806 words) - 12:52, 26 March 2024
• 2022 AMC 12A Problems/Problem 22
  .../math>, <math>\frac{1}{z_1}=B_1</math>. Notice how <math>OA_1B_1</math> is similar to <math>OA_2B_2</math>. Thus, the area of <math>A_1B_1B_2B_1</math> is <m [[Category:Intermediate Geometry Problems]]
  7 KB (1,164 words) - 11:20, 1 January 2024
• 2022 AMC 10B Problems/Problem 22
  import geometry; ...oning for certain statements made. Also an additional twist on a potential similar alternate problem at the end.
  7 KB (1,202 words) - 01:15, 10 June 2023

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