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- {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #6]] and [[2001 AMC 10 Problems|2001 AMC 10 #13]]}} == Problem ==2 KB (340 words) - 03:02, 28 June 2023
- ...cate|[[2008 AMC 12A Problems|2008 AMC 12A #6]] and [[2008 AMC 10A Problems/Problem 8|2008 AMC 10A #8]]}} ==Problem ==2 KB (240 words) - 19:53, 4 June 2021
- ==Problem==1 KB (165 words) - 14:18, 16 February 2021
- == Problem == ...ffect divisibility by <math>67</math>). The second row will be <math>2, 4, 6, \cdots , 98</math>, the third row will be <math>3, 5, \cdots, 97</math>, a3 KB (509 words) - 17:21, 22 March 2018
- 2 KB (288 words) - 17:35, 6 May 2024
- == Problem ==1 KB (223 words) - 23:34, 4 July 2013
- ==Problem== ...loor x \rfloor+\{y\} +z+\{x\}+y +\lfloor z \rfloor=x+x+y+y+z+z=2(x+y+z)=45.6</math>862 bytes (139 words) - 12:13, 20 January 2018
- ==Problem==2 KB (317 words) - 18:09, 12 April 2024
- ==Problem== ...athrm{(A)}\ 3\qquad\mathrm{(B)}\ 4\qquad\mathrm{(C)}\ 5\qquad\mathrm{(D)}\ 6\qquad\mathrm{(E)}\ 7</math>1 KB (209 words) - 22:01, 2 September 2020
- == Problem == ...ion]] and <math>f(v) = 1</math> otherwise (this corresponds, in the actual problem, to putting a mathematician in the first or second room). Then look at <mat13 KB (2,414 words) - 14:37, 11 July 2016
- == Problem == AP &= \frac{8\sqrt{5} \pm \sqrt{20}}{6} = \boxed{\frac{5\sqrt{5}}{3}}, \sqrt{5}.2 KB (283 words) - 22:51, 13 April 2015
- == Problem ==5 KB (739 words) - 13:39, 4 July 2013
- {{duplicate|[[2002 AMC 12A Problems|2002 AMC 12A #6]] and [[2002 AMC 10A Problems|2002 AMC 10A #4]]}} ==Problem==2 KB (258 words) - 04:58, 21 July 2022
- == Problem 6 == {{IMO box|num-b=5|after=Last Problem|year=2001}}1 KB (273 words) - 00:23, 19 November 2023
- == Problem == <cmath>b(n)\geq\frac{1}{6}n^2 - \frac{2}{3}n.</cmath>5 KB (940 words) - 17:33, 16 July 2014
- == Problem ==2 KB (302 words) - 18:11, 22 February 2016
- #REDIRECT[[2002 AMC 12B Problems/Problem 3]]44 bytes (5 words) - 17:36, 28 July 2011
- ==Problem==2 KB (308 words) - 06:29, 16 December 2023
- ==Problem==2 KB (249 words) - 14:28, 31 July 2016
- {{duplicate|[[2004 AMC 12B Problems|2004 AMC 12B #6]] and [[2004 AMC 10B Problems|2004 AMC 10B #8]]}} == Problem ==1 KB (154 words) - 19:23, 22 October 2022
Page text matches
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME I Problems/Problem 1]]1 KB (135 words) - 12:31, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME II Problems/Problem 1]]1 KB (135 words) - 12:30, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AMC 12B Problems/Problem 1 | Problem 1]]2 KB (210 words) - 00:06, 7 October 2014
- ...on &4 &6 & 4 \\ \hline Cube/Hexahedron & 8 & 12 & 6\\ \hline Octahedron & 6 & 12 & 8\\ \hline Dodecahedron & 20 & 30 & 12\\ \hline Icosahedron & 12 & 3 ==Problem==1,006 bytes (134 words) - 14:15, 6 March 2022
- ...A number of '''Mock AMC''' competitions have been hosted on the [[Art of Problem Solving]] message boards. They are generally made by one community member ...amous theorems and formulas and see if there's any way you can make a good problem out of them.51 KB (6,175 words) - 20:58, 6 December 2023
- <math>1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 0, \ldots </math> ...\not\equiv 18 \pmod{6}</math> because <math>\frac{91 - 18}{6} = \frac{73}{6}</math>, which is not an integer.15 KB (2,396 words) - 20:24, 21 February 2024
- <math>\{ \ldots, -6, -3, 0, 3, 6, \ldots \}</math> <math>\overline{6} \cdot \overline{6} = \overline{6 \cdot 6} = \overline{36} = \overline{1}</math>14 KB (2,317 words) - 19:01, 29 October 2021
- label("$45^{\circ}$", A, 6*dir(290)); [[2007 AMC 12A Problems/Problem 10 | 2007 AMC 12A Problem 10]]3 KB (499 words) - 23:41, 11 June 2022
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AMC 10A Problems/Problem 1]]2 KB (180 words) - 18:06, 6 October 2014
- == Problem 1 == [[2006 AIME I Problems/Problem 1|Solution]]7 KB (1,173 words) - 03:31, 4 January 2023
- == Problem == ...sequence. The only thing that will be left will be a sequence <math>\{0,3,6,9,\cdots,3k\}</math> for some even <math>k</math>. Since we started with 206 KB (910 words) - 19:31, 24 October 2023
- == Problem == ...1000</math>, we have five choices for <math>k</math>, namely <math>k=0,2,4,6,8</math>.10 KB (1,702 words) - 00:45, 16 November 2023
- == Problem == ...e 2 towers which use blocks <math>1, 2</math>, so there are <math>2\cdot 3^6 = 1458</math> towers using blocks <math>1, 2, \ldots, 8</math>, so the answ3 KB (436 words) - 05:40, 4 November 2022
- == Problem == draw((6.5,0)--origin--(0,6.5), Arrows(5));4 KB (731 words) - 17:59, 4 January 2022
- == Problem == ...th> [[positive integer]]s. <math>a^{12}r^{66}=8^{2006} = (2^3)^{2006} = (2^6)^{1003}</math> so <math>a^{2}r^{11}=2^{1003}</math>.4 KB (651 words) - 18:27, 22 May 2021
- == Problem == fill((2*i,0)--(2*i+1,0)--(2*i+1,6)--(2*i,6)--cycle, mediumgray);4 KB (709 words) - 01:50, 10 January 2022
- == Problem == The number <math> \sqrt{104\sqrt{6}+468\sqrt{10}+144\sqrt{15}+2006}</math> can be written as <math> a\sqrt{2}+3 KB (439 words) - 18:24, 10 March 2015
- ==Problem 1== [[2021 JMC 10 Problems/Problem 1|Solution]]12 KB (1,784 words) - 16:49, 1 April 2021
- == Problem 1 == [[2006 AMC 12B Problems/Problem 1|Solution]]13 KB (2,058 words) - 12:36, 4 July 2023
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AMC 12A Problems/Problem 1]]1 KB (168 words) - 21:51, 6 October 2014