2019 AMC 10B Problems/Problem 23
- The following problem is from both the 2019 AMC 10B #23 and 2019 AMC 12B #20, so both problems redirect to this page.
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[hide]Problem
Points and lie on circle in the plane. Suppose that the tangent lines to at and intersect at a point on the -axis. What is the area of ?
Solution 1
First, observe that the two tangent lines are of identical length. Therefore, suppose the intersection was . Using Pythagorean Theorem gives .
Notice (due to the right angles formed by a radius and its tangent line) that the quadrilateral (kite) defined by circle center, , , and form a cyclic quadrilateral. Therefore, we can use Ptolemy's theorem:
, where represents the distance between circle center and . Therefore, . Using Pythagorean Theorem on , either one of or , and the circle center, we realize that , at which point , so the answer is .
Solution 2
First, follow solution 1 and obtain . Label the point as point . The midpoint of segment is . Notice that the center of the circle must lie on the line that goes through the points and . Thus, the center of the circle lies on the line .
Line is . The perpendicular line must pass through and . The slope of the perpendicular line is . The line is hence . The point lies on this line. Therefore, . Solving this equation tells us that . So the center of the circle is . The distance between the center, , and point A is . Hence, the area is . The answer is .
Solution 3
The mid point of is . Let the tangent lines at and intersect at on the axis. Then would be the perpendicular bisector of . Let the center of circle be O. Then is similar to , that is The slope of is , therefore the slope of CD will be 3. The equation of is , that is . Let . Then we have , which is the coordinate of .
, , , Therefore , Consequently, the area of the circle is . (by Zhen Qin) (P.S. Will someone please Latex this?) (ed by a pewdiepie subscriber)
See Also
2019 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2019 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 19 |
Followed by Problem 21 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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