2019 AMC 8 Problems/Problem 21
Contents
Problem 21
What is the area of the triangle formed by the lines , , and ?
Solution 1
You need to first find the coordinates where the graphs intersect. , and intersect at . , and intersect at . and intersect at . Using the Shoelace Theorem you get $$ (Error compiling LaTeX. Unknown error_msg)\left(\frac{(20-4)-(-20+4)}{2}\right)=.~heeeeeeheeeee
Solution 2
Graphing the lines, we can see that the height of the triangle is 4, and the base is 8. Using the formula for the area of a triangle, we get which is equal to . ~SmileKat32
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 20 |
Followed by Problem 22 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.