2019 AMC 8 Problems/Problem 22
Contents
[hide]Problem 22
A store increased the original price of a shirt by a certain percent and then lowered the new price by the same amount. Given that the resulting price was of the original price, by what percent was the price increased and decreased?
Solution 1
Suppose the fraction of discount is . That means ; so , and , obtaining . Therefore, the price was increased and decreased by %, or .
Solution 2 (Answer options)
Let the price be 100. Then multiply by 40/100 to get 140. Then, when you subtract by 40 percent, you will end up at .
~Gr8
Solution 3
Let x be the discount. We can also work in reverse such as () = .
Thus = . Solving for gives us . But has to be positive. Thus = .
~phoenixfire
Solution 4 ~ using the answer choices
Let our original cost be We are looking for a result of then. We try 16% and see it gets us higher than 84. We try 20% and see it gets us lower than 16 but still higher than 84. We know that the higher the percent, the less the value. We try 36, as we are not progressing much, and we are close! We try , and we have the answer; it worked.
Video explaining solution
https://www.youtube.com/watch?v=_TheVi-6LWE
https://www.youtube.com/watch?v=RcBDdB35Whk&list=PLLCzevlMcsWNBsdpItBT4r7Pa8cZb6Viu&index=4 ~ MathEx
https://www.youtube.com/watch?v=aStuVhoD8wc- Also includes other problems from 21-25
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 21 |
Followed by Problem 23 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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