2007 Cyprus MO/Lyceum/Problem 14
Revision as of 23:02, 8 May 2007 by I_like_pie (talk | contribs)
Problem
In square the segment
equals a side of the square. The ratio of areas
is
Solution
and
have the same heights (
), so the ratio of their areas is simply the ratio of
.
Let the length of be
. Then
, and the ratio of
is
, or
.
See also
2007 Cyprus MO, Lyceum (Problems) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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