Difference between revisions of "2006 AIME I Problems"
(→Problem 2) |
|||
(32 intermediate revisions by 12 users not shown) | |||
Line 1: | Line 1: | ||
+ | {{AIME Problems|year=2006|n=I}} | ||
+ | |||
== Problem 1 == | == Problem 1 == | ||
− | In | + | In quadrilateral <math> ABCD , \angle B </math> is a right angle, diagonal <math> \overline{AC} </math> is perpendicular to <math> \overline{CD}, AB=18, BC=21, </math> and <math> CD=14. </math> Find the perimeter of <math> ABCD. </math> |
[[2006 AIME I Problems/Problem 1|Solution]] | [[2006 AIME I Problems/Problem 1|Solution]] | ||
== Problem 2 == | == Problem 2 == | ||
− | + | Let set <math> \mathcal{A} </math> be a 90-element subset of <math> \{1,2,3,\ldots,100\}, </math> and let <math> S </math> be the sum of the elements of <math> \mathcal{A}. </math> Find the number of possible values of <math> S. </math> | |
− | |||
[[2006 AIME I Problems/Problem 2|Solution]] | [[2006 AIME I Problems/Problem 2|Solution]] | ||
== Problem 3 == | == Problem 3 == | ||
− | Find the least positive integer such that when its leftmost digit is deleted, the resulting integer is 1/29 of the original integer. | + | Find the least positive integer such that when its leftmost digit is deleted, the resulting integer is <math>1/29</math> of the original integer. |
[[2006 AIME I Problems/Problem 3|Solution]] | [[2006 AIME I Problems/Problem 3|Solution]] | ||
Line 21: | Line 22: | ||
== Problem 5 == | == Problem 5 == | ||
− | The number <math> \sqrt{104\sqrt{6}+468\sqrt{10}+144\sqrt{15}+2006}</math> can be written as <math> a\sqrt{2}+b\sqrt{3}+c\sqrt{5}, </math> where <math> a, b, </math> and <math> c </math> are positive integers. Find <math> | + | The number <math> \sqrt{104\sqrt{6}+468\sqrt{10}+144\sqrt{15}+2006}</math> can be written as <math> a\sqrt{2}+b\sqrt{3}+c\sqrt{5}, </math> where <math> a, b, </math> and <math> c </math> are positive integers. Find <math> abc. </math> |
[[2006 AIME I Problems/Problem 5|Solution]] | [[2006 AIME I Problems/Problem 5|Solution]] | ||
Line 31: | Line 32: | ||
== Problem 7 == | == Problem 7 == | ||
− | An angle is drawn on a set of equally spaced parallel lines as shown. The ratio of the area of shaded region <math> | + | An angle is drawn on a set of equally spaced parallel lines as shown. The ratio of the area of shaded region <math>C</math> to the area of shaded region <math>B</math> is <math>\frac{11}{5}</math>. Find the ratio of shaded region <math>D</math> to the area of shaded region <math>A</math> |
[[Image:2006AimeA7.PNG]] | [[Image:2006AimeA7.PNG]] | ||
Line 38: | Line 39: | ||
== Problem 8 == | == Problem 8 == | ||
− | Hexagon <math> ABCDEF </math> is divided into five rhombuses, <math> | + | Hexagon <math> ABCDEF </math> is divided into five rhombuses, <math>P, Q, R, S,</math> and <math>T</math>, as shown. Rhombuses <math>P, Q, R,</math> and <math>S</math> are congruent, and each has area <math> \sqrt{2006}. </math> Let <math> K </math> be the area of rhombus <math>T</math>. Given that <math> K </math> is a positive integer, find the number of possible values for <math> K. </math> |
[[Image:2006AimeA8.PNG]] | [[Image:2006AimeA8.PNG]] | ||
Line 50: | Line 51: | ||
== Problem 10 == | == Problem 10 == | ||
− | Eight circles of diameter 1 are packed in the first quadrant of the | + | Eight circles of diameter 1 are packed in the first quadrant of the coordinate plane as shown. Let region <math> \mathcal{R} </math> be the union of the eight circular regions. Line <math> l, </math> with slope 3, divides <math> \mathcal{R} </math> into two regions of equal area. Line <math> l </math>'s equation can be expressed in the form <math> ax=by+c, </math> where <math> a, b, </math> and <math> c </math> are positive integers whose greatest common divisor is 1. Find <math> a^2+b^2+c^2. </math> |
− | + | <asy> | |
+ | unitsize(0.50cm); | ||
+ | draw((0,-1)--(0,6)); | ||
+ | draw((-1,0)--(6,0)); | ||
+ | draw(shift(1,1)*unitcircle); | ||
+ | draw(shift(1,3)*unitcircle); | ||
+ | draw(shift(1,5)*unitcircle); | ||
+ | draw(shift(3,1)*unitcircle); | ||
+ | draw(shift(3,3)*unitcircle); | ||
+ | draw(shift(3,5)*unitcircle); | ||
+ | draw(shift(5,1)*unitcircle); | ||
+ | draw(shift(5,3)*unitcircle); | ||
+ | </asy> | ||
[[2006 AIME I Problems/Problem 10|Solution]] | [[2006 AIME I Problems/Problem 10|Solution]] | ||
Line 77: | Line 90: | ||
== Problem 14 == | == Problem 14 == | ||
− | A tripod has three legs each of length 5 feet. When the tripod is set up, the angle between any pair of legs is equal to the angle between any other pair, and the top of the tripod is 4 feet from the ground In setting up the tripod, the lower 1 foot of one leg breaks off. Let <math> h </math> be the height in feet of the top of the tripod from the ground when the broken tripod is set up. Then <math> h </math> can be written in the form <math> \frac m{\sqrt{n}}, </math> where <math> m </math> and <math> n </math> are positive integers and <math> n </math> is not divisible by the square of any prime. Find <math> \lfloor m+\sqrt{n}\rfloor. </math> (The notation <math> \lfloor x\rfloor </math> denotes the greatest integer that is less than or equal to <math> x. </math>) | + | A tripod has three legs each of length 5 feet. When the tripod is set up, the angle between any pair of legs is equal to the angle between any other pair, and the top of the tripod is 4 feet from the ground. In setting up the tripod, the lower 1 foot of one leg breaks off. Let <math> h </math> be the height in feet of the top of the tripod from the ground when the broken tripod is set up. Then <math> h </math> can be written in the form <math> \frac m{\sqrt{n}}, </math> where <math> m </math> and <math> n </math> are positive integers and <math> n </math> is not divisible by the square of any prime. Find <math> \lfloor m+\sqrt{n}\rfloor. </math> (The notation <math> \lfloor x\rfloor </math> denotes the greatest integer that is less than or equal to <math> x. </math>) |
[[2006 AIME I Problems/Problem 14|Solution]] | [[2006 AIME I Problems/Problem 14|Solution]] | ||
Line 87: | Line 100: | ||
== See also == | == See also == | ||
+ | |||
+ | {{AIME box|year = 2006|n=I|before=[[2005 AIME II Problems]]|after=[[2006 AIME II Problems]]}} | ||
+ | |||
* [[American Invitational Mathematics Examination]] | * [[American Invitational Mathematics Examination]] | ||
* [[AIME Problems and Solutions]] | * [[AIME Problems and Solutions]] | ||
* [http://www.artofproblemsolving.com/Community/AoPS_Y_MJ_Transcripts.php?mj_id=144 2006 AIME I Math Jam Transcript] | * [http://www.artofproblemsolving.com/Community/AoPS_Y_MJ_Transcripts.php?mj_id=144 2006 AIME I Math Jam Transcript] | ||
* [[Mathematics competition resources]] | * [[Mathematics competition resources]] | ||
+ | {{MAA Notice}} |
Latest revision as of 17:19, 13 August 2020
2006 AIME I (Answer Key) | AoPS Contest Collections | ||
Instructions
| ||
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 |
Contents
Problem 1
In quadrilateral is a right angle, diagonal is perpendicular to and Find the perimeter of
Problem 2
Let set be a 90-element subset of and let be the sum of the elements of Find the number of possible values of
Problem 3
Find the least positive integer such that when its leftmost digit is deleted, the resulting integer is of the original integer.
Problem 4
Let be the number of consecutive 0's at the right end of the decimal representation of the product Find the remainder when is divided by 1000.
Problem 5
The number can be written as where and are positive integers. Find
Problem 6
Let be the set of real numbers that can be represented as repeating decimals of the form where are distinct digits. Find the sum of the elements of
Problem 7
An angle is drawn on a set of equally spaced parallel lines as shown. The ratio of the area of shaded region to the area of shaded region is . Find the ratio of shaded region to the area of shaded region
Problem 8
Hexagon is divided into five rhombuses, and , as shown. Rhombuses and are congruent, and each has area Let be the area of rhombus . Given that is a positive integer, find the number of possible values for
Problem 9
The sequence is geometric with and common ratio where and are positive integers. Given that find the number of possible ordered pairs
Problem 10
Eight circles of diameter 1 are packed in the first quadrant of the coordinate plane as shown. Let region be the union of the eight circular regions. Line with slope 3, divides into two regions of equal area. Line 's equation can be expressed in the form where and are positive integers whose greatest common divisor is 1. Find
Problem 11
A collection of 8 cubes consists of one cube with edge-length for each integer A tower is to be built using all 8 cubes according to the rules:
- Any cube may be the bottom cube in the tower.
- The cube immediately on top of a cube with edge-length must have edge-length at most
Let be the number of different towers than can be constructed. What is the remainder when is divided by 1000?
Problem 12
Find the sum of the values of such that where is measured in degrees and
Problem 13
For each even positive integer let denote the greatest power of 2 that divides For example, and For each positive integer let Find the greatest integer less than 1000 such that is a perfect square.
Problem 14
A tripod has three legs each of length 5 feet. When the tripod is set up, the angle between any pair of legs is equal to the angle between any other pair, and the top of the tripod is 4 feet from the ground. In setting up the tripod, the lower 1 foot of one leg breaks off. Let be the height in feet of the top of the tripod from the ground when the broken tripod is set up. Then can be written in the form where and are positive integers and is not divisible by the square of any prime. Find (The notation denotes the greatest integer that is less than or equal to )
Problem 15
Given that a sequence satisfies and for all integers find the minimum possible value of
See also
2006 AIME I (Problems • Answer Key • Resources) | ||
Preceded by 2005 AIME II Problems |
Followed by 2006 AIME II Problems | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
- American Invitational Mathematics Examination
- AIME Problems and Solutions
- 2006 AIME I Math Jam Transcript
- Mathematics competition resources
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.