Difference between revisions of "2007 Cyprus MO/Lyceum/Problem 24"

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[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]

Revision as of 00:27, 19 January 2024

Problem

Costas sold two televisions for €198 each. From the sale of the first one he made a profit of 10% on its value and from the sale of the second one, he had a loss of 10% on its value. After the sale of the two televisions Costas had in total

$\mathrm{(A) \ } \mathrm{profit\ }4\qquad \mathrm{(B) \ } \mathrm{neither\ profit\ nor\ loss}\qquad \mathrm{(C) \ } \mathrm{loss\ } 8\qquad \mathrm{(D) \ } \mathrm{profit\ }8\qquad \mathrm{(E) \ } \mathrm{loss\ } 4$

Solution

If the TV original prices are $x,\ y$, then $\frac{11}{10}x = 198$ and $\frac 9{10}y = 198$; $x = 180$ and $y = 220$ totaling $400$; he loses $2(198) - 400 = -4 \Longrightarrow \mathrm{E}$.

See also

2007 Cyprus MO, Lyceum (Problems)
Preceded by
Problem 23
Followed by
Problem 25
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