Difference between revisions of "2010 AMC 12A Problems/Problem 1"
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<math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>. | <math>20-2010+201+2010-201+20=20+20=\boxed{\textbf{(C)}\,40}</math>. | ||
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{{AMC12 box|year=2010|before=First Problem|num-a=2|ab=A}} | {{AMC12 box|year=2010|before=First Problem|num-a=2|ab=A}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:48, 15 December 2018
Problem
What is 
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Solution
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See Also
| 2010 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by First Problem |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
