2010 AMC 12A Problems/Problem 10

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Problem

The first four terms of an arithmetic sequence are $p$, $9$, $3p-q$, and $3p+q$. What is the $2010^\text{th}$ term of this sequence?

$\textbf{(A)}\ 8041 \qquad \textbf{(B)}\ 8043 \qquad \textbf{(C)}\ 8045 \qquad \textbf{(D)}\ 8047 \qquad \textbf{(E)}\ 8049$

Solution

$3p-q$ and $3p+q$ are consecutive terms, so the common difference is $(3p+q)-(3p-q) = 2q$.

\begin{align*}&p+2q = 9\\  &9+2q = 3p-q\\  &q=2\\  &p=5\end{align*}


The common difference is $4$. The first term is $5$ and the $2010^\text{th}$ term is

\[5+4(2009) = \boxed{8041\ \textbf{(A)}}\]

See also

2010 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AMC 12 Problems and Solutions