Difference between revisions of "2018 AMC 10B Problems/Problem 1"
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Suppose we write down the smallest (positive) <math>2</math>-digit, <math>3</math>-digit, and <math>4</math>-digit multiples of <math>8</math>. | Suppose we write down the smallest (positive) <math>2</math>-digit, <math>3</math>-digit, and <math>4</math>-digit multiples of <math>8</math>. | ||
− | + | Problem: | |
+ | Suppose we write down the smallest (positive) <math>2</math>-digit, <math>3</math>-digit, and <math>4</math>-digit multiples of <math>8</math>. | ||
− | + | What is the sum of these three numbers? | |
== Solution 2 == | == Solution 2 == |
Revision as of 18:45, 22 December 2020
Problem: Suppose we write down the smallest (positive) -digit, -digit, and -digit multiples of .
Problem: Suppose we write down the smallest (positive) -digit, -digit, and -digit multiples of .
What is the sum of these three numbers?
Solution 2
By dividing each of the dimensions by , we get a grid which makes pieces. Thus, the answer is .
Video Solution
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See Also
2018 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2018 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by First Problem |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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