Difference between revisions of "2019 AMC 8 Problems/Problem 12"
(→Solution 2) |
Holyangels (talk | contribs) m (→Solution 1) |
||
(7 intermediate revisions by 6 users not shown) | |||
Line 3: | Line 3: | ||
[[File:2019AMC8Prob12.png]] | [[File:2019AMC8Prob12.png]] | ||
− | |||
− | |||
==Solution 1== | ==Solution 1== | ||
− | <math>B</math> is on the top, and <math>R</math> is on the side, and <math>G</math> is on the right side. That means that (image <math>2</math>) <math>W</math> is on the left side. From the third image, you know that <math>P</math> must be on the bottom since <math>G</math> is sideways. That leaves us with the back, so the back must be <math>A</math>. The front is opposite of the back, so the answer is <math>\boxed{\textbf{(A)}\ R}</math>. | + | <math>B</math> is on the top, and <math>R</math> is on the side, and <math>G</math> is on the right side. That means that (image <math>2</math>) <math>W</math> is on the left side. From the third image, you know that <math>P</math> must be on the bottom since <math>G</math> is sideways. That leaves us with the back, so the back must be <math>A</math>. The front is opposite of the back, so the answer is <math>\boxed{\textbf{(A)}\ R}</math>. |
==Solution 2== | ==Solution 2== | ||
Looking closely we can see that all faces are connected with <math>R</math> except for <math>A</math>. Thus the answer is <math>\boxed{\textbf{(A)}\ R}</math>. | Looking closely we can see that all faces are connected with <math>R</math> except for <math>A</math>. Thus the answer is <math>\boxed{\textbf{(A)}\ R}</math>. | ||
− | + | It is A, just draw it out! | |
~phoenixfire | ~phoenixfire | ||
− | ==Solution | + | ==Solution 3== |
Associated video - https://www.youtube.com/watch?v=K5vaX_EzjEM | Associated video - https://www.youtube.com/watch?v=K5vaX_EzjEM | ||
− | == | + | ==See also== |
{{AMC8 box|year=2019|num-b=11|num-a=13}} | {{AMC8 box|year=2019|num-b=11|num-a=13}} | ||
Only two of the cubes are required to solve the problem. | Only two of the cubes are required to solve the problem. |
Latest revision as of 09:33, 25 February 2021
Problem
The faces of a cube are painted in six different colors: red , white , green , brown , aqua , and purple . Three views of the cube are shown below. What is the color of the face opposite the aqua face?
Solution 1
is on the top, and is on the side, and is on the right side. That means that (image ) is on the left side. From the third image, you know that must be on the bottom since is sideways. That leaves us with the back, so the back must be . The front is opposite of the back, so the answer is .
Solution 2
Looking closely we can see that all faces are connected with except for . Thus the answer is .
It is A, just draw it out! ~phoenixfire
Solution 3
Associated video - https://www.youtube.com/watch?v=K5vaX_EzjEM
See also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
Only two of the cubes are required to solve the problem.