Difference between revisions of "2019 AMC 8 Problems/Problem 5"

(Problem 5)
(Solution 1)
Line 6: Line 6:
 
[[File:2019_AMC_8_-4_Image_2.png|600px]]
 
[[File:2019_AMC_8_-4_Image_2.png|600px]]
  
==Solution 1==
+
==Solution 1 (Using the answer choices)==
 
+
First, the tortoise walks at a constant rate, ruling out <math>(D)</math>
 +
Second, when the hare is resting, the distance will stay the same, ruling out <math>(E)</math> and <math>(C)</math>.
 +
Third, the tortoise wins the race, ruling out <math>(A)</math>.
 +
Therefore, the answer is the only one left, <math>(B)</math> QED
 +
-Lcz
  
 
==See Also==
 
==See Also==

Revision as of 15:30, 21 November 2019

Problem 5

A tortoise challenges a hare to a race. The hare eagerly agrees and quickly runs ahead, leaving the slow-moving tortoise behind. Confident that he will win, the hare stops to take a nap. Meanwhile, the tortoise walks at a slow steady pace for the entire race. The hare awakes and runs to the finish line, only to find the tortoise already there. Which of the following graphs matches the description of the race, showing the distance $d$ traveled by the two animals over time $t$ from start to finish?

2019 AMC 8 -4 Image 1.png

2019 AMC 8 -4 Image 2.png

Solution 1 (Using the answer choices)

First, the tortoise walks at a constant rate, ruling out $(D)$ Second, when the hare is resting, the distance will stay the same, ruling out $(E)$ and $(C)$. Third, the tortoise wins the race, ruling out $(A)$. Therefore, the answer is the only one left, $(B)$ QED -Lcz

See Also

2019 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS