Difference between revisions of "2023 AMC 12B Problems/Problem 4"
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<math>\textbf{(A) } 162,500 \qquad\textbf{(B) } 162.5 \qquad\textbf{(C) }1,625 \qquad\textbf{(D) }1,625,000 \qquad\textbf{(E) } 16,250</math> | <math>\textbf{(A) } 162,500 \qquad\textbf{(B) } 162.5 \qquad\textbf{(C) }1,625 \qquad\textbf{(D) }1,625,000 \qquad\textbf{(E) } 16,250</math> | ||
| − | ==Solution== | + | ==Solution 1== |
6.5 millimeters is equal to 0.65 centimeters. 25 meters is 2500 centimeters. The answer is <math>0.65 \times 2500</math>, so the answer is <math>\boxed{\textbf{(C) 1,625}}</math>. | 6.5 millimeters is equal to 0.65 centimeters. 25 meters is 2500 centimeters. The answer is <math>0.65 \times 2500</math>, so the answer is <math>\boxed{\textbf{(C) 1,625}}</math>. | ||
~Failure.net | ~Failure.net | ||
~Mintylemon66 | ~Mintylemon66 | ||
| + | |||
| + | ==Solution 2(Standard Form)== | ||
| + | 6.5 millimeters can be represented as 65 \times 10^{-2} centimeters. 25 meters is 25 \times 10^{2} centimeters. Multiplying out these results in (65 \times 10^{-2}) \times (25 \times 10^{2}) which is 65 \times 25 , so the answer is <math>\boxed{\textbf{(C) 1,625}}</math>. | ||
| + | |||
| + | ~darrenn.cp | ||
| + | |||
| + | |||
==Video Solution 1 by SpreadTheMathLove== | ==Video Solution 1 by SpreadTheMathLove== | ||
Revision as of 06:27, 16 November 2023
- The following problem is from both the 2023 AMC 10B #4 and 2023 AMC 12B #4, so both problems redirect to this page.
Contents
Problem
Jackson's paintbrush makes a narrow strip with a width of 6.5 millimeters. Jackson has enough paint to make a strip 25 meters long. How many square centimeters of paper could Jackson cover with paint?
Solution 1
6.5 millimeters is equal to 0.65 centimeters. 25 meters is 2500 centimeters. The answer is 
, so the answer is 
.
~Failure.net ~Mintylemon66
Solution 2(Standard Form)
6.5 millimeters can be represented as 65 \times 10^{-2} centimeters. 25 meters is 25 \times 10^{2} centimeters. Multiplying out these results in (65 \times 10^{-2}) \times (25 \times 10^{2}) which is 65 \times 25 , so the answer is .
~darrenn.cp
Video Solution 1 by SpreadTheMathLove
https://www.youtube.com/watch?v=SUnhwbA5_So
See also
| 2023 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2023 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 3 |
Followed by Problem 5 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
