Create the page "Go 2a-6b" on this wiki! See also the search results found.

• 2006 AMC 12A Problems/Problem 20
  The bug then has only <math>1</math> way to go to a point <math>E</math> on the opposite face, therefore having a <math>\f
  5 KB (908 words) - 19:23, 22 September 2022
• 2006 AMC 12A Problems/Problem 24
  ...nt of <math>y</math> is <math>3</math>, the exponent of <math>z</math> can go up to <math>2002</math>, so there are <math>1002</math> terms.
  8 KB (1,332 words) - 17:37, 17 September 2023
• 2000 AIME I Problems/Problem 6
  ...y. Thus we get that <math>y</math> can go up to 999 and <math>x</math> can go down to <math>3</math>, leaving <math>997</math> possibilities for <math>x,
  6 KB (966 words) - 21:48, 29 January 2024
• 2001 AIME II Problems/Problem 6
  ...</math>. Let <math>DF</math> = <math>b</math> and diameter <math>HI</math> go through <math>J</math> the midpoint of <math>EF</math>. Since a diameter al
  4 KB (772 words) - 19:31, 6 December 2023
• System of equations
  ...is to graph them in the [[plane]] and observe where they intersect. We'll go back to our same example to illustrate this.
  5 KB (784 words) - 23:27, 30 July 2020
• Euler line
  <cmath>GO^2 = R^2 - \frac {a^2 + b^2 + c^2}{9}.</cmath> <cmath>HO^2 = 9R^2 - a^2 - b^2 - c^2, GO^2 = \frac {HO^2}{9} = R^2 - \frac {a^2 + b^2 + c^2}{9}.</cmath>
  59 KB (10,203 words) - 04:47, 30 August 2023
• 2003 AMC 12A Problems/Problem 25
  ...Complex numbers are a bit harder to address than real numbers, so I won't go into depth on complex domain/range (You don't need to, as this is a 2003 qu
  9 KB (1,606 words) - 11:34, 10 July 2020
• 2007 AIME I Problems/Problem 10
  ...ces, and another fixed empty square. The remaining shaded squares can only go in 4 places, so we get <math>{4\choose2} = 6</math>. We get <math>180 \cdot ...y need to choose 2, since 1 of the shaded squares in the third column must go to the unoccupied 2-row).
  13 KB (2,328 words) - 00:12, 29 November 2023
• 2007 AIME II Problems/Problem 12
  ...math>, from which we simplify to <math>2a+7n=77</math>. From here, we just go brute force using the second statement (that <math>3^{56}\leq 3^{a}+...+3^{
  5 KB (829 words) - 12:22, 8 January 2024
• 2001 USAMO Problems/Problem 2
  ...and <math>\mathbf{H}_2(B) = M_2</math>. Under the dilation, parallel lines go to parallel lines and the intersection of two lines goes to the intersectio
  11 KB (2,091 words) - 08:35, 16 November 2017
• De Longchamps point
  <math>2\vec {HG} = \vec GL_o, 2\vec {GO} = \vec HG \implies L_o = L</math> as desired. <cmath>OK = R, HK = 2R, HG = 2GO \implies GK^2 = 2(R^2 – GO^2), GO^2 = \frac {HO^2}{9} \implies</cmath>
  10 KB (1,780 words) - 09:23, 17 November 2022
• 2008 AIME II Problems/Problem 13
  ...artesian plane over the x-axis)! If you're familiar with inversion you can go plot the inverted figure's Cartesian Plane Equivalent. Then simply continue
  6 KB (894 words) - 18:56, 25 December 2022
• 2021 GMC 10B
  Ary wants to go to the park at afternoon. He walked to halfway, and he's pretty hungry. The
  11 KB (1,695 words) - 14:33, 7 March 2022
• 1988 AJHSME Problems/Problem 4
  ...the number of black squares in each row increases by 1 continuously as we go down the pyramid.
  2 KB (354 words) - 15:22, 17 January 2023
• 2010 AIME II Problems/Problem 11
  ...h>'s, then we have two <math>1</math>'s left to place. Clearly they cannot go in the same row, because then the other row is filled with <math>0</math>'s
  6 KB (1,057 words) - 01:58, 8 January 2023
• Barycentric coordinates
  <cmath>\frac{HO}{BO} = \frac {|a-c|}{b}; \frac{GO}{BO} = \frac {|b-c|}{a}.</cmath>
  25 KB (5,067 words) - 22:15, 31 March 2024
• 1953 AHSME Problems
  ...e diameter of <math>6</math> feet, required to cause a point on the rim to go one mile is:
  21 KB (3,123 words) - 14:24, 20 February 2020
• 1955 AHSME Problems
  The length of the shortest wire that will go around them is:
  22 KB (3,509 words) - 21:29, 31 December 2023
• Mock Geometry AIME 2011 Problems/Problem 12
  ...ath>4 \cos^2{X} - 1</math> since the solution, <math>60^\circ</math> would go out of range for the triangle sum of angles. ...for <math>\cos{X}</math>, and neglecting the negative root since it would go out of bounds too, we find <math>\cos{X} = \frac{1 + \sqrt{33}}{8}</math>.
  5 KB (831 words) - 17:55, 21 July 2018
• 2013 AIME II Problems/Problem 15
  Let's draw the triangle. Since the problem only deals with angles, we can go ahead and set one of the sides to a convenient value. Let <math>BC = \sin{A
  8 KB (1,411 words) - 23:48, 11 January 2023
• 2014 IMO Problems/Problem 4
  ...ra to Asymptote conversion, documentation at artofproblemsolving.com/Wiki, go to User:Azjps/geogebra */
  13 KB (1,801 words) - 07:29, 1 May 2024
• 2015 AMC 12A Problems/Problem 22
  ...n... in a row" are key phrases that indicate recursion is the right way to go. Let's go with finding the case of <math>S(n)</math> from previous cases.
  5 KB (925 words) - 13:08, 5 May 2024
• 2015 AMC 12B Problems/Problem 23
  Now go through cases for <math>a</math> and you end up with the same result. Howev
  5 KB (832 words) - 17:50, 18 October 2022
• 2015 AMC 10B Problems/Problem 21
  ...(because Dash had to take another jump when Cozy didn't). We don't need to go any further because the difference will stay above <math>19</math> onward.
  6 KB (983 words) - 01:51, 16 June 2022
• 2015 AIME II Problems/Problem 11
  ...bra to Asymptote conversion, documentation at artofproblemsolving.com/Wiki go to User:Azjps/geogebra */
  9 KB (1,249 words) - 21:59, 26 November 2023
• 2016 AIME I Problems/Problem 10
  ...he other squares in the sequence don't have enough elements before them to go all the way back to <math>a_1</math> while still staying as positive intege
  5 KB (883 words) - 15:24, 6 January 2024
• Mock Geometry AIME 2011 Problems/Problem 14
  Finally, we compute the locus of the centers. We could go through a slight coordinate bash (and it isn't that hard to do), but here w
  4 KB (657 words) - 11:40, 6 November 2016
• 2019 USAJMO Problems/Problem 4
  ...bra to Asymptote conversion, documentation at artofproblemsolving.com/Wiki go to User:Azjps/geogebra */
  10 KB (1,536 words) - 20:27, 12 April 2021
• Proof of Quadratic Theorem
  ...function to output <math>0</math>. The possible <math>x</math> values that go into a function is referred to as the domain, and the possible <math>y</mat
  1 KB (264 words) - 17:45, 28 April 2019
• 2019 AIME I Problems/Problem 7
  ~North America math Contest Go Go Go
  8 KB (1,351 words) - 16:07, 3 January 2024
• What is the definition of Pure Mathematics?
  ...trigonometry, and calculus? And what is the definition of numbers? Now you go to the dictionary and say ''The relationship between measurements and quant ...maller and smaller fraction going infinitely long. Pi or <math>\pi</math> (go to the geometry part of this article) is the limit <math>\frac{1}{1}-\frac{
  35 KB (5,882 words) - 18:08, 28 June 2021
• 2020 AIME II Problems/Problem 1
  ~ North America Math Contest Go Go Go
  2 KB (346 words) - 13:59, 25 February 2024
• Sieve of Sundaram
  ...h>a,b</math> get back prime we have at least 4 prime factors, and this can go to any depth you choose.
  5 KB (580 words) - 18:10, 27 February 2020
• 2020 AMC 8 Problems/Problem 4
  ...on has <math>1+6+12</math> dots, and so on. The pattern continues since to go from hexagon <math>n</math> to hexagon <math>(n+1),</math> we add a new ban == Video Solution by North America Math Contest Go Go Go ==
  5 KB (865 words) - 07:14, 24 January 2024
• 2020 AMC 8 Problems/Problem 16
  == Video Solution by North America Math Contest Go Go Go == ~North America Math Contest Go Go Go
  3 KB (550 words) - 16:35, 26 January 2024
• 2021 AIME II Problems/Problem 13
  ...equiv n \pmod{5}</math> is necessary; it shouldn't take too long for us to go through the <math>20</math> possible LHS-RHS combinations, considering that
  16 KB (2,240 words) - 23:16, 26 January 2024
• 2021 Fall AMC 12A Problems/Problem 23
  ...s slope <math>1</math>. It can be written as <math>y = x+d</math> and must go through <math>\left(-\frac{1}{2}, \frac{1}{2}\right)</math> so <math>d = 1<
  26 KB (4,697 words) - 22:19, 2 January 2024
• 2022 AMC 10B Problems/Problem 14
  ...t. So, <math>\boxed{\textbf{(B) }13}</math> elements is the highest we can go.
  6 KB (959 words) - 11:46, 13 November 2023
• Kimberling’s point X(20)
  <math>2\vec {HG} = \vec GL_o, 2\vec {GO} = \vec HG \implies L_o = L</math> as desired. <cmath>OK = R, HK = 2R, HG = 2GO \implies GK^2 = 2(R^2 – GO^2), GO^2 = \frac {HO^2}{9} \implies</cmath>
  7 KB (1,164 words) - 11:37, 26 November 2022
• 2022 SSMO Team Round Problems
  A frog is at <math>0</math> on a number line and wants to go to <math>9</math>. On each turn, if the frog is at <math>n</math>, the frog
  9 KB (1,537 words) - 11:13, 25 December 2023
• DVI exam
  <cmath>\frac {SL}{LC} = \frac{KB + CB} {CK}= \frac{3+5} {2} = 4. \frac{GO}{OH} = \frac{CK}{CD} = \frac{2}{5}.</cmath> <cmath>AB = 5 \implies OH = \frac {5 \sqrt{3}}{2} \implies GO = \sqrt{3}.</cmath>
  32 KB (5,375 words) - 11:43, 5 May 2024
• Problems Collection
  ...e at the bottom of the second peg, or the largest peg will have nowhere to go. In order for the largest ring to be at the bottom, we must first move the
  43 KB (7,006 words) - 14:24, 19 February 2024
• 2005 iTest Problems
  ...ked those iTest problems, solving question after question, almost made him go insane sitting there that day. He never felt the same way when she worked o ...want the answer, and be so impressed with Joe’s brilliance that she’d go out with him on Friday night.
  25 KB (3,738 words) - 10:53, 23 April 2024