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k a My Retirement & New Leadership at AoPS
rrusczyk   1571
N Yesterday at 11:40 PM by SmartGroot
I write today to announce my retirement as CEO from Art of Problem Solving. When I founded AoPS 22 years ago, I never imagined that we would reach so many students and families, or that we would find so many channels through which we discover, inspire, and train the great problem solvers of the next generation. I am very proud of all we have accomplished and I’m thankful for the many supporters who provided inspiration and encouragement along the way. I'm particularly grateful to all of the wonderful members of the AoPS Community!

I’m delighted to introduce our new leaders - Ben Kornell and Andrew Sutherland. Ben has extensive experience in education and edtech prior to joining AoPS as my successor as CEO, including starting like I did as a classroom teacher. He has a deep understanding of the value of our work because he’s an AoPS parent! Meanwhile, Andrew and I have common roots as founders of education companies; he launched Quizlet at age 15! His journey from founder to MIT to technology and product leader as our Chief Product Officer traces a pathway many of our students will follow in the years to come.

Thank you again for your support for Art of Problem Solving and we look forward to working with millions more wonderful problem solvers in the years to come.

And special thanks to all of the amazing AoPS team members who have helped build AoPS. We’ve come a long way from here:IMAGE
1571 replies
1 viewing
rrusczyk
Mar 24, 2025
SmartGroot
Yesterday at 11:40 PM
k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

Are you ready to level up with Olympiad training? Registration is open with early bird pricing available for our WOOT programs: MathWOOT (Levels 1 and 2), CodeWOOT, PhysicsWOOT, and ChemWOOT. What is WOOT? WOOT stands for Worldwide Online Olympiad Training and is a 7-month high school math Olympiad preparation and testing program that brings together many of the best students from around the world to learn Olympiad problem solving skills. Classes begin in September!

Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
[*]March 6th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar on Math Competitions from elementary through high school. Join us for an enlightening session that demystifies the world of math competitions and helps you make informed decisions about your contest journey.
[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
[*]March 13th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar about Summer Camps at the Virtual Campus. Transform your summer into an unforgettable learning adventure! From elementary through high school, we offer dynamic summer camps featuring topics in mathematics, language arts, and competition preparation - all designed to fit your schedule and ignite your passion for learning.[/list]
Our full course list for upcoming classes is below:
All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
Mar 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
a truly remarkable problem
john0512   14
N a few seconds ago by OronSH
Consider the sequence of positive integers $$6,69,696,6969,69696\cdots.$$It is well known that $69696=264^2$. Prove that this is the only perfect square in the sequence.

Jiahe Liu, Vikram Sarkar, Allen Wang, Ritwin Narra, Carlos Rodriguez, Susie Lu, Jonathan He, Jordan Lefkowitz, Victor Chen, Luv Udeshi
14 replies
john0512
Feb 20, 2023
OronSH
a few seconds ago
Inequality
Tendo_Jakarta   1
N 4 minutes ago by Tendo_Jakarta
Let \(a,b,c\) be positive numbers such that \(a+b+c = 3\). Find the maximum value of
\[T = \dfrac{bc}{\sqrt{a}+3}+\dfrac{ca}{\sqrt{b}+3}+\dfrac{ab}{\sqrt{c}+3}  \]
1 reply
Tendo_Jakarta
Today at 7:24 AM
Tendo_Jakarta
4 minutes ago
2018 Peru Cono Sur TST P3
EmersonSoriano   1
N 8 minutes ago by kokcio
Let $ I $ be the incenter of a triangle $ ABC $ with $ AB \neq AC $, and let $ M $ be the midpoint of the arc $ BAC $ of the circumcircle of the triangle. The perpendicular line to $ AI $ passing through $ I $ intersects line $ BC $ at point $ D $. The line $ MI $ intersects the circumcircle of triangle $ BIC $ at point $ N $. Prove that line $ DN $ is tangent to the circumcircle of triangle $ BIC $.
1 reply
EmersonSoriano
5 hours ago
kokcio
8 minutes ago
Rational numbers
steven_zhang123   1
N 30 minutes ago by kokcio
Source: G635
Find all positive real numbers \( \alpha \) such that there exist infinitely many rational numbers \( \frac{p}{q} (p, q \in \mathbb{Z}, p > 0, \gcd(p, q) = 1 ) \) satisfying

\[
\left| \frac{q}{p} - \frac{\sqrt{5} - 1}{2} \right| < \frac{\alpha}{p^2}.
\]
1 reply
steven_zhang123
Today at 1:24 PM
kokcio
30 minutes ago
Find Triples of Integers
termas   39
N an hour ago by VideoCake
Source: IMO 2015 problem 2
Find all positive integers $(a,b,c)$ such that
$$ab-c,\quad bc-a,\quad ca-b$$are all powers of $2$.

Proposed by Serbia
39 replies
1 viewing
termas
Jul 10, 2015
VideoCake
an hour ago
Convex quadrilateral and midpoints [RMO2-2011, India]
Potla   14
N an hour ago by mqoi_KOLA
Let $ABCD$ be a convex quadrilateral. Let $E,F,G,H$ be the midpoints of $AB,BC,CD,DA$ respectively. If $AC,BD,EG,FH$ concur at a point $O,$ prove that $ABCD$ is a parallelogram.
14 replies
Potla
Dec 31, 2011
mqoi_KOLA
an hour ago
inequality marathon
EthanWYX2009   191
N an hour ago by Martin.s
There is an inequality marathon now, but the problem is too hard for me to solve, let's start a new one here, please post problems that is not too difficult.
------
P1.
Find the maximum value of ${M}$, such that for $\forall a,b,c\in\mathbb R_+,$
$$a^3+b^3+c^3-3abc\geqslant M(a^2b+b^2c+c^2a-3abc).$$
191 replies
EthanWYX2009
May 21, 2023
Martin.s
an hour ago
2025 Caucasus MO Juniors P2
BR1F1SZ   1
N an hour ago by GreekIdiot
Source: Caucasus MO
There are $30$ children standing in a circle. For each girl, it turns out that among the five people following her clockwise, there are more boys than girls. Find the greatest number of girls that can stand in a circle.
1 reply
BR1F1SZ
Yesterday at 12:55 AM
GreekIdiot
an hour ago
Unique solution
USJL   0
an hour ago
Source: 2025 Taiwan TST Round 2 Independent Study 1-N
Find all $g:\mathbb{R}\to\mathbb{R}$ so that there exists a unique $f:\mathbb{R}\to\mathbb{R}$ satisfying $f(0)=g(0)$ and
\[f(x+g(y))+f(-x-g(-y))=g(x+f(y))+g(-x-f(-y))\]for all $x,y\in\mathbb{R}$.

Proposed by usjl
0 replies
USJL
an hour ago
0 replies
Show that XD and AM meet on Gamma
MathStudent2002   90
N an hour ago by ErTeeEs06
Source: IMO Shortlist 2016, Geometry 2
Let $ABC$ be a triangle with circumcircle $\Gamma$ and incenter $I$ and let $M$ be the midpoint of $\overline{BC}$. The points $D$, $E$, $F$ are selected on sides $\overline{BC}$, $\overline{CA}$, $\overline{AB}$ such that $\overline{ID} \perp \overline{BC}$, $\overline{IE}\perp \overline{AI}$, and $\overline{IF}\perp \overline{AI}$. Suppose that the circumcircle of $\triangle AEF$ intersects $\Gamma$ at a point $X$ other than $A$. Prove that lines $XD$ and $AM$ meet on $\Gamma$.

Proposed by Evan Chen, Taiwan
90 replies
MathStudent2002
Jul 19, 2017
ErTeeEs06
an hour ago
A number theory about divisors which no one fully solved at the contest
nAalniaOMliO   7
N 2 hours ago by CHESSR1DER
Source: Belarusian national olympiad 2024
Let's call a pair of positive integers $(k,n)$ interesting if $n$ is composite and for every divisor $d<n$ of $n$ at least one of $d-k$ and $d+k$ is also a divisor of $n$
Find the number of interesting pairs $(k,n)$ with $k \leq 100$
M. Karpuk
7 replies
nAalniaOMliO
Jul 24, 2024
CHESSR1DER
2 hours ago
Modified Fermat's last theorem
Euler8038   0
2 hours ago
Source: Own
Prove that, for any n, there is an infinite number of sequences composed by n pairwise coprime positive integers such that the sum of the n-th powers of the term in the sequence gives you an n-th power.

To be clear, if n=2 the conjecture is just about Pythagorean triples.

If n=3, you have to show that there exist an infinite number of triplets such that a³+b³+c³ is a cube, with a, b, c pairwise coprime positive integers.
0 replies
Euler8038
2 hours ago
0 replies
Infinite cube triplets
Euler8038   0
2 hours ago
Let a, b, x be positive coprime integers. Prove that there exist an infinite number of triplets (a, b, x) such that x³=3ab(a+b), or disprove the conjecture.
0 replies
Euler8038
2 hours ago
0 replies
find the value of an angles
AlanLG   4
N 3 hours ago by sunken rock
Source: 1st National Women´s Contest of Mexican Mathematics Olympiad 2022, problem 2 teams
Consider $\triangle ABC$ an isosceles triangle such that $AB = BC$. Let $P$ be a point satisfying

$$\angle ABP = 80^\circ, \angle CBP = 20^\circ, \textrm{and}  \hspace{0.17cm} AC = BP$$
Find all possible values of $\angle BCP$.
4 replies
AlanLG
Jul 23, 2023
sunken rock
3 hours ago
x and o game, in an infinite grid of regular triangles
parmenides51   5
N Mar 19, 2025 by Lil_flip38
Source: Norwegian Mathematical Olympiad 2017 - Abel Competition p3b
In an infinite grid of regular triangles, Niels and Henrik are playing a game they made up.
Every other time, Niels picks a triangle and writes $\times$ in it, and every other time, Henrik picks a triangle where he writes a $o$. If one of the players gets four in a row in some direction (see figure), he wins the game.
Determine whether one of the players can force a victory.
IMAGE
5 replies
parmenides51
Sep 3, 2019
Lil_flip38
Mar 19, 2025
x and o game, in an infinite grid of regular triangles
G H J
G H BBookmark kLocked kLocked NReply
Source: Norwegian Mathematical Olympiad 2017 - Abel Competition p3b
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parmenides51
30628 posts
#1 • 2 Y
Y by Adventure10, Mango247
In an infinite grid of regular triangles, Niels and Henrik are playing a game they made up.
Every other time, Niels picks a triangle and writes $\times$ in it, and every other time, Henrik picks a triangle where he writes a $o$. If one of the players gets four in a row in some direction (see figure), he wins the game.
Determine whether one of the players can force a victory.
https://cdn.artofproblemsolving.com/attachments/6/e/5e80f60f110a81a74268fded7fd75a71e07d3a.png
This post has been edited 1 time. Last edited by parmenides51, Sep 3, 2019, 9:33 AM
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parmenides51
30628 posts
#2 • 2 Y
Y by Adventure10, Mango247
posted for the figure link
Attachments:
This post has been edited 1 time. Last edited by parmenides51, Sep 3, 2019, 9:33 AM
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RayThroughSpace
426 posts
#3 • 1 Y
Y by Adventure10
First player can win.
Click to reveal hidden text
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Lil_flip38
45 posts
#4
Y by
The game will always end in a draw.
Partition the grid into hexagons consisting of \(6\) regular triangles, and observe that every triangle contributes to exactly \(1\) edge in a hexagon. The strategy for player Henrik is to always play in the triangle sharing an edge with the triangle placed by Niels. This implies that Niels will never get multiple in a row across \(2\) hexagons, so he can never get \(4\) in a row. This is a strategy for Henrik to always draw.

Its obvious why Henrik also never wins, as it is strictly better to start the game.
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GreekIdiot
133 posts
#5
Y by
Lil_flip38 wrote:
The game will always end in a draw.
Partition the grid into hexagons consisting of \(6\) regular triangles, and observe that every triangle contributes to exactly \(1\) edge in a hexagon. The strategy for player Henrik is to always play in the triangle sharing an edge with the triangle placed by Niels. This implies that Niels will never get multiple in a row across \(2\) hexagons, so he can never get \(4\) in a row. This is a strategy for Henrik to always draw.

Its obvious why Henrik also never wins, as it is strictly better to start the game.

Well your argument is wrong. Henrik is indeed always able to play in the triangle sharing an edge with the one marked by Niels the turn before his, but note that there are multiple candidates (namely 3, as a triangle has 3 edges) for said triangle. Then in the following turns Niels can just mark one of those two unmarked triangles, inevitably putting Henrik in a lose-lose position, where there is a double threat of connect-four, much like how it is in a tic-tac-toe game. This was pointed out by the answer above yours, and that person is ultimately right. :D
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Lil_flip38
45 posts
#6
Y by
I should have clarified in my solution that you place in the unique triangle that is NOT in the same hexagon as the previous triangle. Thus i do not understand your point about there being multiple candidates. Its easy to see that this strategy implies Niels never makes a connection that passes through multiple hexagons.
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