The Birthday Problem

by aoum, Mar 13, 2025, 11:48 PM

The Birthday Problem: Probability of Shared Birthdays

The Birthday Problem is a fascinating probability puzzle that asks: In a group of randomly chosen people, what is the probability that at least two people share the same birthday? The result is surprisingly counterintuitive—much higher than most people expect.

https://upload.wikimedia.org/wikipedia/commons/thumb/e/e7/Birthday_Paradox.svg/290px-Birthday_Paradox.svg.png

1. Understanding the Birthday Problem

If you randomly select people and record their birthdays (assuming 365 days in a year and ignoring leap years), the probability that at least two of them share a birthday grows rapidly as the group size increases.

Here are some key probability benchmarks:
  • With 23 people, the probability that at least two share a birthday is approximately 50.7%.
  • With 50 people, the probability exceeds 97%.
  • With 70 people, the probability is 99.9%, meaning it is almost certain that two people share a birthday.

These probabilities seem surprising because most people intuitively compare everyone’s birthday to their own. However, the correct approach compares every pair of people, which significantly increases the number of potential matches.

2. Why Does This Happen?

At the heart of the birthday problem lies the concept of combinatorial growth. With each new person added to the group, the number of potential birthday pairs grows rapidly.

In a group of \( n \) people, the number of unique pairs is given by the binomial coefficient:

\[
\binom{n}{2} = \frac{n(n - 1)}{2}.
\]
For 23 people:

\[
\binom{23}{2} = \frac{23 \times 22}{2} = 253 \text{ pairs.}
\]
The rapid growth of potential comparisons means the likelihood of a match increases quickly as the group size increases.

3. The Mathematics Behind the Birthday Problem

To calculate the probability that no one shares a birthday, we multiply the probabilities that each successive person has a unique birthday:
  • The first person has any birthday: \( \frac{365}{365} \).
  • The second person must avoid the first person's birthday: \( \frac{364}{365} \).
  • The third person must avoid the first two birthdays: \( \frac{363}{365} \).

For \( n \) people, the probability that no two share a birthday is:

\[
P(\text{No Match}) = \frac{365}{365} \times \frac{364}{365} \times \dots \times \frac{365 - n + 1}{365}.
\]
This can be rewritten using the product notation:

\[
P(\text{No Match}) = \prod_{k=0}^{n-1} \left( \frac{365 - k}{365} \right).
\]
The probability that at least two people share a birthday is the complement:

\[
P(\text{At Least One Match}) = 1 - P(\text{No Match}).
\]
4. Example Calculation (23 People)

If \( n = 23 \):

\[
P(\text{No Match}) = \frac{365}{365} \times \frac{364}{365} \times \dots \times \frac{343}{365} \approx 0.4927,
\]
Thus,

\[
P(\text{At Least One Match}) = 1 - 0.4927 = 0.5073 \approx 50.7\%.
\]
5. Python Code to Simulate the Birthday Problem

Here’s a Python script to estimate the probability using a Monte Carlo simulation:

import random

def birthday_simulation(num_people, trials=100000):
    matches = 0
    for _ in range(trials):
        birthdays = [random.randint(1, 365) for _ in range(num_people)]
        if len(birthdays) != len(set(birthdays)):
            matches += 1
    return matches / trials

for n in [10, 23, 30, 50, 70]:
    probability = birthday_simulation(n)
    print(f"For {n} people, the estimated probability of a shared birthday is {probability:.4f}")


6. Approximating with the Poisson Distribution

For larger groups, the product formula becomes computationally intensive. We can approximate the probability using the Poisson distribution:

\[
P(\text{At Least One Match}) \approx 1 - e^{-\frac{n^2}{2m}},
\]
where:
  • \( n \) = Number of people
  • \( m \) = Number of days in a year (365)

For \( n = 23 \):

\[
P(\text{At Least One Match}) \approx 1 - e^{-\frac{23^2}{2 \times 365}} \approx 0.507.
\]
7. Fun Facts About the Birthday Problem
  • The birthday problem generalizes to hash collisions in computer science, where the likelihood of two items mapping to the same hash value is calculated similarly.
  • This problem is an example of the pigeonhole principle: If you have more items than categories, at least one category must contain more than one item.
  • The distribution of real-world birthdays is not perfectly uniform—certain dates (e.g., September) have higher birth rates.
  • This paradox applies to various fields like DNA profiling, cryptographic security, and data science.

8. Applications of the Birthday Problem
  • Cryptography: Explains the vulnerability of hash functions to birthday attacks.
  • Data Science: Used in large datasets to calculate the likelihood of duplicates.
  • Networking: Analyzes packet collisions in communication protocols.
  • Probability Theory: Demonstrates how quickly probabilities compound with growing combinations.

9. Exploring the Generalized Birthday Problem

The birthday problem extends to other domains:
  • k-Matches Problem: What is the probability that at least k people share a birthday?
  • Non-Uniform Distribution: Real-life data, such as hospital records, show non-uniform birthday frequencies, requiring adjusted calculations.
  • Higher Dimensions: Similar probabilistic problems occur in multidimensional spaces, such as the collision probability of random vectors.

10. Conclusion

The birthday problem illustrates how quickly probabilities grow when considering combinations. Despite the vast number of possible birthdays, relatively small groups have a high likelihood of sharing one. This seemingly simple puzzle has profound implications across mathematics, computer science, and data security.

References

Comment

0 Comments

Fun with Math!

avatar

aoum
Archives
- March 2025
Shouts
Submit
  • I am now able to make clickable images in my posts! :)

    by aoum, 3 minutes ago

  • Am I doing enough? Are you all expecting more from me?

    by aoum, Today at 12:31 AM

  • That's all right.

    by aoum, Yesterday at 10:46 PM

  • sorry i couldn't contribute, was working on my own blog and was sick, i'll try to contribute more

    by HacheB2031, Yesterday at 2:41 AM

  • Nice blog!
    I found it through blogroll.

    by yaxuan, Mar 26, 2025, 5:26 AM

  • How are you guys finding my blog?

    by aoum, Mar 24, 2025, 4:50 PM

  • insanely high quality!

    by clarkculus, Mar 24, 2025, 3:20 AM

  • Thanks! Happy to hear that!

    by aoum, Mar 23, 2025, 7:26 PM

  • They look really nice!

    by kamuii, Mar 23, 2025, 1:50 AM

  • I've embedded images and videos in my posts now. How do they look? (Please refrain from using my code. :noo:)

    by aoum, Mar 20, 2025, 8:58 PM

  • This is a nice blog! :)

    by charking, Mar 18, 2025, 7:48 PM

  • Are you guys actually reading my posts? Am I doing too much?

    by aoum, Mar 17, 2025, 11:35 PM

  • Thanks! Glad to hear that!

    by aoum, Mar 17, 2025, 3:07 PM

  • This is a really nice blog! One of the best I've seen on AOPS so far

    by kamuii, Mar 17, 2025, 12:13 AM

  • What does everyone think of my blog?

    by aoum, Mar 16, 2025, 10:28 PM

  • Yes, you may.

    by aoum, Mar 16, 2025, 9:00 PM

  • Can I contribute???

    by rayliu985, Mar 16, 2025, 8:00 PM

  • I'm sorry, I cannot make a post about the "performance" you mentioned, ohiorizzler1434.

    by aoum, Mar 15, 2025, 4:00 PM

  • are you a chat gpt

    by amburger, Mar 15, 2025, 1:48 AM

  • Bruh! That's crazy. can you make a post about KSI's performance of 'thick of it' at the sidemen charity football match? Personally, I thought it was amazing! KSI's energy and singing ability really made my day!

    by ohiorizzler1434, Mar 15, 2025, 1:03 AM

  • I already have a post on the Collatz Conjecture, but I'll make another, better one soon.

    by aoum, Mar 14, 2025, 10:53 PM

  • Your blog looks skibidi ohio! Please make a post about the collatz conjecture next, with a full solution!

    by ohiorizzler1434, Mar 14, 2025, 10:26 PM

  • Thanks for subscribing!

    by aoum, Mar 14, 2025, 8:24 PM

  • I get emails every post you make. Also, third post!?

    by HacheB2031, Mar 13, 2025, 11:43 PM

  • I can hardly believe you are watching my blog so carefully.

    by aoum, Mar 13, 2025, 11:42 PM

  • woah what :O two posts in 4 minutes

    by HacheB2031, Mar 13, 2025, 11:35 PM

  • I'll try. With these advanced areas, it's more likely that I'll make a mistake somewhere, so please help me out. (I will make these as accurate as I can.)

    by aoum, Mar 10, 2025, 11:51 PM

  • Maybe conic sections?

    by HacheB2031, Mar 10, 2025, 2:53 PM

  • Does anyone have some ideas for me to write about?

    by aoum, Mar 9, 2025, 10:28 PM

  • That's nice to know. I'm also learning new, interesting things on here myself, too.

    by aoum, Mar 7, 2025, 11:35 PM

  • Reading the fun facts and all from this blog's material makes me feel so at ease when using formulas. like, I finally understand the backstory of it and all that even teachers don't teach :roll:

    by expiredcraker, Mar 7, 2025, 4:50 AM

  • Thanks! There are many interesting things about math out there, and I hope to share them with you all. I'll be posting more of these!

    by aoum, Mar 7, 2025, 12:56 AM

  • Wow. This is a very interesting blog! I could really use this advice!

    by rayliu985, Mar 7, 2025, 12:43 AM

  • Thanks! Nice to hear that!

    by aoum, Mar 6, 2025, 10:56 PM

  • blog is great :) :coolspeak:

    by HacheB2031, Mar 6, 2025, 5:45 AM

  • Yes, I'll be doing problems of the day every day.

    by aoum, Mar 5, 2025, 1:15 AM

  • I think it would also be cool if you did a problem of the day every day, as I see from today's problem.

    by jocaleby1, Mar 5, 2025, 1:13 AM

  • Do you guys like my "lectures" or would you like something else?

    by aoum, Mar 4, 2025, 10:37 PM

  • Yeah, keep on making these "lectures" :)

    by jocaleby1, Mar 4, 2025, 2:41 AM

  • Thanks! Glad to hear that!

    by aoum, Mar 3, 2025, 10:28 PM

  • ME ME ME OMG I need a math mentor like this your explanation is so easy to understand! also 3rd shout! :D

    by expiredcraker, Mar 3, 2025, 3:32 AM

  • Anyone wants to contribute to my blog? Shout or give me a friend request!

    by aoum, Mar 2, 2025, 3:22 PM

  • Nice blog! Contrib?

    by jocaleby1, Mar 1, 2025, 6:43 PM

43 shouts
Contributors
Tags
Problem of the Day
Fractals
geometry
poll
Collatz Conjecture
Millennium Prize Problems
pi
Riemann Hypothesis
Sir Issac Newton
AMC
Chudnovsky Algorithm
Gauss-Legendre Algorithm
Goldbach Conjecture
infinity
Koch snowflake
MAA
Mandelbrot Set
Mastering AMC 1012
MATHCOUNTS
Nilakantha Series
P vs NP Problem
Algorithmic Applications
AMC 10
AMC 8
angle bisector theorem
Angle trisection
Applications in Various Fields
Arc Sine Formula
Archimedes Method
Banach-Tarski Paradox
Basel Problem
Basic Reproduction Number
Bayes Theorem
Bernoulli numbers
Bertrand s Box Paradox
binomial theorem
calculus
Cantor s Infinite Sets
cardinality
Circumference
Coin Rotation Paradox
computer science
conditional probability
conic sections
Conjectures
Cyclic Numbers
Different Sizes of Infinity
Diseases
Drake Equation
epidemiology
Euler s Formula for Polyhedra
Euler s Identity
Euler s totient function
Euler-Lagrange Equation
Exponents
Factorials
Fermat s Factoring Method
fermat s last theorem
Fibonacci sequence
finite
four color theorem
Fractals and Chaos Theory
free books
Golden Ratio
graph theory
gravity
Gregory-Liebniz Series
Hailstone Problem
Heron s Formula
Hilbert s Hotel
Hodge Conjecture
Inclusion-exclusion
infinite
Irrational numbers
Law of Force and Acceleration
Leibniz Formula
logarithms
Mastering AMC 8
Menger Sponge
Minkowskis Theorem
modular arithmetic
Multinomial Theorem
Multiples of 24
National Science Bowl
Newton s First Law of Motion
Newton s Second Law of Motion
Newton s Third Law of Motion
P-adic Analysis
Parabolas
Paradox
paradoxes
Penrose Tilings
pie
prime numbers
probability
Pythagorean Theorem
Python
Reproduction Rate of Diseases
Sequences
Sets
Sierpinski Triangle
Simon s Factoring Trick
The Birthday Problem
The Book of Formulas
The Law of Action and Reaction
The Law of Inertia
Topological Insights
triangle inequality
trigonometry
twin prime conjecture
venn diagram
Wallis Product
Zeno s Paradoxes
About Owner
  • Posts: 0
  • Joined: Nov 2, 2024
Blog Stats
  • Blog created: Mar 1, 2025
  • Total entries: 65
  • Total visits: 531
  • Total comments: 25
Search Blog
a