Irrational Numbers

by aoum, Mar 28, 2025, 12:30 AM

Irrational Numbers: Numbers That Defy Fractions

1. Introduction to Irrational Numbers

An irrational number is a real number that cannot be expressed as the ratio of two integers. That is, an irrational number is any number that is not of the form

\[
\frac{p}{q}
\]
where $p, q \in \mathbb{Z}$ and $q \neq 0$. The decimal expansion of an irrational number is non-terminating and non-repeating. Some famous examples of irrational numbers include:

Irrational numbers play a crucial role in mathematics, particularly in number theory, algebra, and analysis. They form an essential part of the real number system $\mathbb{R}$ but are distinct from rational numbers.
https://upload.wikimedia.org/wikipedia/commons/thumb/a/a6/Square_root_of_2_triangle.svg/250px-Square_root_of_2_triangle.svg.png

The number $\sqrt{2}$ is irrational.

2. Proof That $\sqrt{2}$ is Irrational

The irrationality of $\sqrt{2}$ is one of the oldest mathematical proofs, dating back to ancient Greece. We prove this by contradiction.

Proof:
  • Assume, for the sake of contradiction, that $\sqrt{2}$ is rational. This means there exist integers $p$ and $q$ such that

    \[
\sqrt{2} = \frac{p}{q}
\]
    where $p$ and $q$ are coprime (i.e., they share no common factors other than $1$).
  • Squaring both sides gives

    \[
2 = \frac{p^2}{q^2}
\]
    or equivalently,

    \[
p^2 = 2q^2.
\]
  • Since $p^2$ is divisible by $2$, this implies $p$ itself must be even (because the square of an odd number is odd). So we write $p = 2k$ for some integer $k$.
  • Substituting $p = 2k$ into the equation $p^2 = 2q^2$ gives

    \[
(2k)^2 = 2q^2 \quad \Rightarrow \quad 4k^2 = 2q^2 \quad \Rightarrow \quad 2k^2 = q^2.
\]
  • This means $q^2$ is also divisible by $2$, so $q$ must also be even.
  • Since both $p$ and $q$ are even, they share a common factor of $2$, contradicting our assumption that $\frac{p}{q}$ is in lowest terms.
  • Therefore, our assumption that $\sqrt{2}$ is rational must be false, so $\sqrt{2}$ is irrational.

3. The Set of Irrational Numbers

The set of irrational numbers is defined as

\[
\mathbb{I} = \mathbb{R} \setminus \mathbb{Q}
\]
where $\mathbb{R}$ is the set of real numbers and $\mathbb{Q}$ is the set of rational numbers. Since $\mathbb{Q}$ is countable and $\mathbb{R}$ is uncountable, it follows that the set of irrational numbers is uncountable.

4. Density of Irrational Numbers

Between any two distinct real numbers, there exists at least one irrational number. In fact, there exist infinitely many irrational numbers between any two real numbers. This follows from the fact that the rationals and irrationals are both dense in $\mathbb{R}$, meaning that for any two real numbers $a$ and $b$ with $a < b$, we can always find an irrational number $x$ such that $a < x < b$.

5. The Sum and Product of Irrational Numbers

The sum and product of irrational numbers can be rational or irrational, depending on the numbers involved. Some important results include:
  • The sum of two irrational numbers can be rational. For example,

    \[
(\sqrt{2} + 1) + (-\sqrt{2} + 1) = 2.
\]
  • The product of two irrational numbers can be rational. For example,

    \[
\sqrt{2} \cdot \frac{1}{\sqrt{2}} = 1.
\]
  • The sum of two irrational numbers is not always irrational. For instance, $\pi + (2 - \pi) = 2$.
  • The product of two irrational numbers is not always irrational. For instance, $\sqrt{2} \cdot \sqrt{2} = 2$.
  • However, some irrational sums and products always remain irrational, such as $\pi + \sqrt{2}$ and $\pi \cdot e$.

6. Transcendental Numbers: A Special Class of Irrationals

All transcendental numbers are irrational, but not all irrational numbers are transcendental. A number is transcendental if it is not a root of any nonzero polynomial equation with integer coefficients. Examples include:
  • $\pi$, proved transcendental by Lindemann in 1882.
  • $e$, proved transcendental by Hermite in 1873.

Algebraic numbers (roots of polynomials with integer coefficients) can be either rational or irrational. For example, $\sqrt{2}$ is irrational but algebraic, since it satisfies $x^2 - 2 = 0$.

7. Open Problems Related to Irrational Numbers

There are still many open questions about irrational numbers, such as:
  • Is $\pi + e$ irrational?
  • Is $\pi \cdot e$ irrational?
  • Are there infinitely many pairs of irrational numbers $(x, y)$ such that $x^y$ is rational?

8. Conclusion

Irrational numbers are a fascinating and fundamental part of mathematics. They are everywhere in the real number line and appear in geometry, algebra, calculus, and number theory. Their properties lead to deep mathematical questions that continue to be explored today.

References
  • Niven, I. Irrational Numbers. Mathematical Association of America, 1956.
  • Hardy, G. H., and Wright, E. M. An Introduction to the Theory of Numbers. Oxford University Press, 1979.
  • Wikipedia: Irrational Number.
  • AoPS Wiki: Irrational Numbers.

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  • The first few posts for April are out!

    by aoum, 3 hours ago

  • Sure! I understand that it would be quite a bit to take in.

    by aoum, 4 hours ago

  • No, but it is a lot to take in. Also, could you do the Gamma Function next?

    by HacheB2031, Yesterday at 3:04 AM

  • Am I going too fast? Would you like me to slow down?

    by aoum, Monday at 11:34 PM

  • Seriously, how do you make these so fast???

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  • I am now able to make clickable images in my posts! :)

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  • Am I doing enough? Are you all expecting more from me?

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  • That's all right.

    by aoum, Mar 28, 2025, 10:46 PM

  • sorry i couldn't contribute, was working on my own blog and was sick, i'll try to contribute more

    by HacheB2031, Mar 28, 2025, 2:41 AM

  • Nice blog!
    I found it through blogroll.

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  • How are you guys finding my blog?

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  • I've embedded images and videos in my posts now. How do they look? (Please refrain from using my code. :noo:)

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