Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
Iran Team Selection Test 2016
MRF2017   6
N 10 minutes ago by amirhsz
Source: TST 2,day 1,P2
Let $a,b,c,d$ be positive real numbers such that $\frac{1}{a+1}+\frac{1}{b+1}+\frac{1}{c+1}+\frac{1}{d+1}=2$. Prove that $$\sum_{cyc} \sqrt{\frac{a^2+1}{2}} \geq (3.\sum_{cyc} \sqrt{a}) -8$$
6 replies
MRF2017
Jul 15, 2016
amirhsz
10 minutes ago
Hard problem
Tendo_Jakarta   1
N 11 minutes ago by wassupevery1
Let \(x,y,z,t\) be positive real numbers. Find the minimum value of
\[ T = (x+y+z+t)^2.\left[\dfrac{1}{x(y+z+t)}+\dfrac{1}{y(z+t+x)}+\dfrac{1}{z(t+x+y)}+\dfrac{1}{t(x+y+z)}\right] \]
1 reply
Tendo_Jakarta
3 hours ago
wassupevery1
11 minutes ago
Quadratic division
giangtruong13   1
N 12 minutes ago by MathsII-enjoy
Let $x,y,z$ be integer numbers satisfy that: $x^2-3y^2-z^2=xy+3xz-8yz$.Prove that: $$44|5x+19y+15z$$
1 reply
giangtruong13
2 hours ago
MathsII-enjoy
12 minutes ago
Symmedian line
April   89
N 14 minutes ago by Avron
Source: All Russian Olympiad - Problem 9.2, 10.2
Let be given a triangle $ ABC$ and its internal angle bisector $ BD$ $ (D\in BC)$. The line $ BD$ intersects the circumcircle $ \Omega$ of triangle $ ABC$ at $ B$ and $ E$. Circle $ \omega$ with diameter $ DE$ cuts $ \Omega$ again at $ F$. Prove that $ BF$ is the symmedian line of triangle $ ABC$.
89 replies
April
May 10, 2009
Avron
14 minutes ago
No more topics!
2009 JBMO Shortlist G5
parmenides51   6
N Oct 20, 2023 by Assassino9931
Source: 2009 JBMO Shortlist G5
Let ${A, B, C}$ and ${O}$ be four points in plane, such that $\angle ABC>{{90}^{{}^\circ }}$ and ${OA=OB=OC}$.Define the point ${D\in AB}$ and the line ${l}$ such that ${D\in l, AC\perp DC}$ and ${l\perp AO}$. Line ${l}$ cuts ${AC}$at ${E}$ and circumcircle of ${ABC}$ at ${F}$. Prove that the circumcircles of triangles ${BEF}$and ${CFD}$are tangent at ${F}$.
6 replies
parmenides51
Oct 8, 2017
Assassino9931
Oct 20, 2023
2009 JBMO Shortlist G5
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Source: 2009 JBMO Shortlist G5
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parmenides51
30630 posts
#1 • 2 Y
Y by Adventure10, Mango247
Let ${A, B, C}$ and ${O}$ be four points in plane, such that $\angle ABC>{{90}^{{}^\circ }}$ and ${OA=OB=OC}$.Define the point ${D\in AB}$ and the line ${l}$ such that ${D\in l, AC\perp DC}$ and ${l\perp AO}$. Line ${l}$ cuts ${AC}$at ${E}$ and circumcircle of ${ABC}$ at ${F}$. Prove that the circumcircles of triangles ${BEF}$and ${CFD}$are tangent at ${F}$.
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Davrbek
252 posts
#3 • 2 Y
Y by Adventure10, Mango247
So,It is easy to see $O$ circumcenter of $(ABC) \implies \angle OAC=B-90^\circ$.
If $l \cap (ABC)=F$ at arc $AC$ containing $B$ and $l \cap AO=K,I\cap AC=E$.
We need to show $\angle EBF+\angle FDC=\angle EFC \implies\angle EBF+\angle FDC+\angle FEC+\angle FCE=180^\circ$.
Given $\angle AKD=\angle ACD=90^\circ$.
So,quadrilateral $ADCK$ cyclic.
So,$\angle OAC=\angle KDC=B-90^\circ$.
In $\triangle ADK$ $\angle ADK=C$.
So,quadrilateral $BDCE$ cyclic.Then,$\angle EBC=B-90^\circ$.In triangle $EDC$ $\angle CED=180^\circ-B$.So,
$\angle EBF+\angle FDC+\angle FEC+\angle FCE=B-90^\circ+\angle CBF+B-90^\circ+180^\circ+C+\angle BCF=B+C+A=180^\circ$.
Proved.
This post has been edited 2 times. Last edited by Davrbek, Oct 8, 2017, 3:57 PM
Reason: Sorry
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claserken
1772 posts
#4 • 1 Y
Y by Adventure10
Any solution with inversion?
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MeineMeinung
68 posts
#5 • 2 Y
Y by claserken, Adventure10
claserken wrote:
Any solution with inversion?

Here it is
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MathematicalPhysicist
179 posts
#6 • 2 Y
Y by Adventure10, Mango247
Nothing... :blush:
This post has been edited 2 times. Last edited by MathematicalPhysicist, Oct 15, 2018, 6:07 PM
Reason: iq low
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math_pi_rate
1218 posts
#7 • 2 Y
Y by Adventure10, Mango247
This is just a restated problem. Anyway, here's my solution: Note that $O$ is the circumcenter of $\triangle ABC$. Let $A'$ be the antipode of $A$ in $\odot (ABC)$. Then $\angle A'CA=90^{\circ} \Rightarrow D,C,A'$ are collinear. Also, as $DE \perp AA'$ and $AE \perp A'D$, we get that $E$ is the orthocenter of $\triangle ADA'$. But $\angle A'BA=90^{\circ}$, giving $A',E,B$ are collinear. Thus $$\angle EFC=\angle CDF+\angle DCF=\angle CDF+\angle A'BF=\angle CDF+\angle EBF$$This easily gives that $\odot (CDF)$ and $\odot (BEF)$ are tangent to each other at $F$.

REMARK: If one states the problem in terms of $\triangle ADA'$, then the problem becomes quite well known.
This post has been edited 1 time. Last edited by math_pi_rate, Oct 16, 2018, 7:05 AM
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Assassino9931
1221 posts
#8
Y by
Fun fact, this is Balkan MO 2012/1
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