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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Wednesday at 3:18 PM
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Wednesday at 3:18 PM
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Answer is Year
solasky   2
N 8 minutes ago by AshAuktober
Source: Japan MO Preliminary 2021/1
For all relatively prime positive integers $m$, $n$ satisfying $m + n = 90$, what is the maximum possible value of $mn$?
2 replies
solasky
Jun 15, 2024
AshAuktober
8 minutes ago
series and factorials?
jenishmalla   8
N 19 minutes ago by Maximilian113
Source: 2025 Nepal ptst p4 of 4
Find all pairs of positive integers \( n \) and \( x \) such that
\[
1^n + 2^n + 3^n + \cdots + n^n = x!
\]
(Petko Lazarov, Bulgaria)
8 replies
+1 w
jenishmalla
Mar 15, 2025
Maximilian113
19 minutes ago
Collinear Centers and Midarcs
Miku3D   34
N 20 minutes ago by lelouchvigeo
Source: 2021 APMO P3
Let $ABCD$ be a cyclic convex quadrilateral and $\Gamma$ be its circumcircle. Let $E$ be the intersection of the diagonals of $AC$ and $BD$. Let $L$ be the center of the circle tangent to sides $AB$, $BC$, and $CD$, and let $M$ be the midpoint of the arc $BC$ of $\Gamma$ not containing $A$ and $D$. Prove that the excenter of triangle $BCE$ opposite $E$ lies on the line $LM$.
34 replies
Miku3D
Jun 9, 2021
lelouchvigeo
20 minutes ago
Bashing??
John_Mgr   0
32 minutes ago
I have learned little about what bashing mean as i am planning to start geo, feels like its less effort required and doesnt need much knowledge about the synthetic solutions?
what do you guys recommend ? also state the major difference of them... especially of bashing pros and cons..
0 replies
John_Mgr
32 minutes ago
0 replies
1 area = 2025 points
giangtruong13   1
N 36 minutes ago by kiyoras_2001
In a plane give a set $H$ that has 8097 distinct points with area of a triangle that has 3 points belong to $H$ all $ \leq 1$. Prove that there exists a triangle $G$ that has the area $\leq 1 $ contains at least 2025 points that belong to $H$( each of that 2025 points can be inside the triangle or lie on the edge of triangle $G$)X
1 reply
giangtruong13
6 hours ago
kiyoras_2001
36 minutes ago
A board with crosses that we color
nAalniaOMliO   2
N 39 minutes ago by CHESSR1DER
Source: Belarusian National Olympiad 2025
In some cells of the table $2025 \times 2025$ crosses are placed. A set of 2025 cells we will call balanced if no two of them are in the same row or column. It is known that any balanced set has at least $k$ crosses.
Find the minimal $k$ for which it is always possible to color crosses in two colors such that any balanced set has crosses of both colors.
2 replies
nAalniaOMliO
Mar 28, 2025
CHESSR1DER
39 minutes ago
Geometry Finale: Incircles and concurrency
lminsl   173
N an hour ago by Parsia--
Source: IMO 2019 Problem 6
Let $I$ be the incentre of acute triangle $ABC$ with $AB\neq AC$. The incircle $\omega$ of $ABC$ is tangent to sides $BC, CA$, and $AB$ at $D, E,$ and $F$, respectively. The line through $D$ perpendicular to $EF$ meets $\omega$ at $R$. Line $AR$ meets $\omega$ again at $P$. The circumcircles of triangle $PCE$ and $PBF$ meet again at $Q$.

Prove that lines $DI$ and $PQ$ meet on the line through $A$ perpendicular to $AI$.

Proposed by Anant Mudgal, India
173 replies
lminsl
Jul 17, 2019
Parsia--
an hour ago
Inspired by JK1603JK
sqing   8
N an hour ago by SunnyEvan
Source: Own
Let $ a,b,c\geq 0 $ and $ab+bc+ca=1.$ Prove that$$\frac{abc-2}{abc-1}\ge \frac{4(a^2b+b^2c+c^2a)}{a^3b+b^3c+c^3a+1} $$
8 replies
sqing
Today at 3:31 AM
SunnyEvan
an hour ago
Problem 1
blug   2
N an hour ago by kjhgyuio
Source: Polish Math Olympiad 2025 Finals P1
Find all $(a, b, c, d)\in \mathbb{R}$ satisfying
\[\begin{aligned}
\begin{cases}
    a+b+c+d=0,\\
    a^2+b^2+c^2+d^2=12,\\
    abcd=-3.\\
\end{cases}
\end{aligned}\]
2 replies
blug
2 hours ago
kjhgyuio
an hour ago
Proper sitting of Delegates
Math-Problem-Solving   1
N 2 hours ago by XAN4
Source: 2002 British Mathematical Olympiad Round 2
Solve this.
1 reply
Math-Problem-Solving
Yesterday at 10:13 AM
XAN4
2 hours ago
2 var inquality
sqing   2
N 2 hours ago by sqing
Source: Own
Let $ a,b \ge  0 $ and $ a+b=2. $ Prove that
$$\sqrt{ a^2+b+6}+\sqrt{ b^2+a+6}\leq 8\sqrt{\frac{2- ab}{ab+1}} $$$$\sqrt{2a^2+b+1}+\sqrt{2b^2+a+1}\leq 4\sqrt{\frac{5-2ab}{ab+2}} $$$$\sqrt{2a^2+b}+\sqrt{2b^2+a}\leq 2\sqrt{\frac{3(5-2ab)}{ab+2}} $$
2 replies
sqing
Apr 2, 2025
sqing
2 hours ago
Problem 2
blug   1
N 2 hours ago by Parsia--
Source: Polish Math Olympiad 2025 Finals P2
Positive integers $k, m, n ,p $ integers are such that $p=2^{2^n}+1$ is prime and $p\mid 2^k-m$. Prove that there exists a positive integer $l$ such that $p^2\mid 2^l-m$.
1 reply
blug
2 hours ago
Parsia--
2 hours ago
Problem 6
blug   0
2 hours ago
Source: Polish Math Olympiad 2025 Finals P6
A strictly decreasing function $f:(0, \infty)\Rightarrow (0, \infty)$ attaining all positive values and positive numbers $a_1\ne b_1$ are given. Numbers $a_2, b_2, a_3, b_3, ...$ satisfy
$$a_{n+1}=a_n+f(b_n),\;\;\;\;\;\;\;b_{n+1}=b_n+f(a_n)$$for every $n\geq 1$. Prove that there exists a positive integer $n$ satisfying $|a_n-b_n| >2025$.
0 replies
blug
2 hours ago
0 replies
Problem 5
blug   0
2 hours ago
Source: Polish Math Olympiad 2025 Finals P5
Convex quadrilateral $ABCD$ is described on a circle $\omega$, and is not a trapezius inscribed in a circle. Let the tangency points of $\omega$ and $AB, BC, CD, DA$ be $K, L, M, N$ respectively. A circle with a center $I_K$, different from $\omega$ is tangent to the segement $AB$ and lines $AD, BC$. A circle with center $I_L$, different from $\omega$ is tangent to segment $BC$ and lines $AB, CD$. A circle with center $I_M$, different from $\omega$ is tangent to segment $CD$ and lines $AD, BC$. A circle with center $I_N$, different from $\omega$ is tangent to segment $AD$ and lines $AB, CD$. Prove that the lines $I_KK, I_LL, I_MM, I_NN$ are concurrent.
0 replies
blug
2 hours ago
0 replies
Cyclic Quadrilateral, bisectors, points lie on perpendicular line
mruczek   5
N Sep 12, 2024 by War-Hammer
Source: 54 Polish MO 2003 Second Round - First Day Problem 2
The quadrilateral $ABCD$ is inscribed in the circle $o$. Bisectors of angles $DAB$ and $ABC$ intersect at point $P$, and bisectors of angles $BCD$ and $CDA$ intersect in point $Q$. Point $M$ is the center of this arc $BC$ of the circle $o$ which does not contain points $D$ and $A$. Point $N$ is the center of the arc $DA$ of the circle $o$, which does not contain points $B$ and $C$. Prove that the points $P$ and $Q$ lie on the line perpendicular to $MN$.
5 replies
mruczek
Feb 19, 2018
War-Hammer
Sep 12, 2024
Cyclic Quadrilateral, bisectors, points lie on perpendicular line
G H J
Source: 54 Polish MO 2003 Second Round - First Day Problem 2
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mruczek
67 posts
#1 • 2 Y
Y by Adventure10, Rounak_iitr
The quadrilateral $ABCD$ is inscribed in the circle $o$. Bisectors of angles $DAB$ and $ABC$ intersect at point $P$, and bisectors of angles $BCD$ and $CDA$ intersect in point $Q$. Point $M$ is the center of this arc $BC$ of the circle $o$ which does not contain points $D$ and $A$. Point $N$ is the center of the arc $DA$ of the circle $o$, which does not contain points $B$ and $C$. Prove that the points $P$ and $Q$ lie on the line perpendicular to $MN$.
This post has been edited 4 times. Last edited by mruczek, Apr 21, 2018, 4:38 PM
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mruczek
67 posts
#2 • 2 Y
Y by Adventure10, Mango247
Bump, Bump
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coldheart361
26 posts
#3 • 1 Y
Y by Adventure10
Can you give me hint?
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Radical_Axis
66 posts
#4 • 2 Y
Y by coldheart361, Adventure10
coldheart361 wrote:
Can you give me hint?

Let $AD$ and $BC$ meet at $R$ .Then it's easy to see that $R,P,Q$ are collinear.
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coldheart361
26 posts
#5 • 2 Y
Y by Mango247, Mango247
Thanks for the clue! I finally got it.
Let AD and BC meet at R, then P is be the incenter of $\triangle{ABR}$ and Q is the excenter of $\triangle{CDR}$, hence P, Q, and R lie on the bisector of $\angle{R}$.
Now let the tangent of circle at $M$ hit $PQ$ at $X$ and tangent of circle at $N$ hit $PQ$ at $Y$,
since $M$ and $N$ are midpoints of arc, we get $MX//AR$ and $NY//BR$,
Let $MX$ and $NY$ intersect at $Z$, then the bisector of $\angle{Z}$ is parallel to $PQR$, which is perpendicular to $MN$
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War-Hammer
670 posts
#6
Y by
Also check Poland Second Round 2003 - Day 1 - Problem 2.
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