Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
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jlacosta
Apr 2, 2025
0 replies
Scanner on squarefree integers
Assassino9931   0
a few seconds ago
Source: Bulgaria National Olympiad 2025, Day 2, Problem 5
Let $n$ be a positive integer. Prove that there exists a positive integer $a$ such that exactly $\left \lfloor \frac{n}{4} \right \rfloor$ of the integers $a + 1, a + 2, \ldots, a + n$ are squarefree.
0 replies
Assassino9931
a few seconds ago
0 replies
Orthocenter config once again
Assassino9931   0
2 minutes ago
Source: Bulgaria National Olympiad 2025, Day 2, Problem 4
Let \( ABC \) be an acute triangle with \( AB < AC \), midpoint $M$ of side $BC$, altitude \( AD \) (\( D \in BC \)), and orthocenter \( H \). A circle passes through points \( B \) and \( D \), is tangent to line \( AB \), and intersects the circumcircle of triangle \( ABC \) at a second point \( Q \). The circumcircle of triangle \( QDH \) intersects line \( BC \) at a second point \( P \). Prove that the lines \( MH \) and \( AP \) are perpendicular.
0 replies
Assassino9931
2 minutes ago
0 replies
Poly with sequence give infinitely many prime divisors
Assassino9931   0
3 minutes ago
Source: Bulgaria National Olympiad 2025, Day 1, Problem 3
Let $P(x)$ be a non-constant monic polynomial with integer coefficients and let $a_1, a_2, \ldots$ be an infinite sequence. Prove that there are infinitely many primes, each of which divides at least one term of the sequence $b_n = P(n)^{a_n} + 1$.
0 replies
Assassino9931
3 minutes ago
0 replies
Number Theory Chain!
JetFire008   17
N 4 minutes ago by JetFire008
I will post a question and someone has to answer it. Then they have to post a question and someone else will answer it and so on. We can only post questions related to Number Theory and each problem should be more difficult than the previous. Let's start!

Question 1
17 replies
JetFire008
Yesterday at 7:14 AM
JetFire008
4 minutes ago
No more topics!
Poland 1
orl   5
N Aug 15, 2022 by peace09
Source: IMO LongList 1959-1966 Problem 4
Given $5$ points in the plane, no three of them being collinear. Show that among these $5$ points, we can always find $4$ points forming a convex quadrilateral.
5 replies
orl
Sep 7, 2004
peace09
Aug 15, 2022
Source: IMO LongList 1959-1966 Problem 4
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orl
3647 posts
#1 • 2 Y
Y by Adventure10, Mango247
Given $5$ points in the plane, no three of them being collinear. Show that among these $5$ points, we can always find $4$ points forming a convex quadrilateral.
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orl
3647 posts
#2 • 2 Y
Y by Adventure10, Mango247
Please post your solutions. This is just a solution template to write up your solutions in a nice way and formatted in LaTeX. But maybe your solution is so well written that this is not required finally. For more information and instructions regarding the ISL/ILL problems please look here: introduction for the IMO ShortList/LongList project and regardingsolutions
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pbornsztein
3004 posts
#3 • 2 Y
Y by Adventure10, Mango247
This is the famous result of Esther Klein which introduced Erds and Szekeres to Ramsay theory....

Clearly, there is nothing to prove if the convex hull of the five points is a quadrilateral or a pentagon. Since the points are not collinear, we only have to deal with the case that the convex hull is a triangle, say $ABC$, with two of the points, say $D,E$ in its interior.
Now, the line $DE$ meet two side of the triangle $ABC$ (recall that no three points are collinear), say $AB$ and $AC$. Thus $B,C,D,E$ are in some order the vertices of a convex quadrilateral, and we are done.

Pierre.
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Peter
3615 posts
#4 • 3 Y
Y by pengagumrahasiamu, Adventure10, Mango247
Isn't this rather combinatorics? I just can't believe I'd solve a Geometry longlisted question so easy :)

If point E is outside ABCD, the problem is trivially solved. If it's inside, draw the diagonal AC. Since no 3 are collinear, E is on one side of AB, say WLOG on the side towards D.

Then it follows immediately that ABCE is convex :)

Peter
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Peter
3615 posts
#5 • 3 Y
Y by pengagumrahasiamu, Adventure10, Mango247
Ah darn, Pierre is once again faster.

And this time with a <1 page solution this must be really easy! :D
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peace09
5417 posts
#6
Y by
Let the $5$ points be $A$, $B$, $C$, $D$, and $E$. We first consider $A$, $B$, $C$, and $D$. If each of these is in the exterior of the triangle determined by the other $3$ points, we are done by $ABCD$. If one of these is in the interior, however, WLOG let it be $A$. We now proceed with casework based on the position of $E$.

If $E$ is in the exterior of triangle $BCD$, the lines $AB$, $AC$, and $AD$ split the plane into $3$ regions. If $E$ is in the region determined by $AB$ and $AC$, then $ABEC$ is convex, and analogous reasoning applies to the other $2$ regions.

If $E$ is in the interior of triangle $BCD$, extend $BA$ bast $A$ to intersect $CD$ at $E$, and define $F$ and $G$ similarly. Then, if $E$ is in the interior of triangle $ACG$ or $ADF$, $AECD$ or $AEDC$ is convex respectively. Analogous reasoning applies to the other $2$ pairs of triangles. $\blacksquare$
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