Y by Adventure10, Mango247
Given two points in a plane and a straightedge whose length is less than the distance between them (but no compass!), construct the line passing through the two points.
You may want to use a special case of Desargues' theorem:
Suppose we have two triangles,
and
positioned in such a way that
, and
intersect in a point. Let lines
and
meet at point
, lines
and
, meet at
, and
and
at
. Then, points
, and
are collinear (fig. ).

You may want to use a special case of Desargues' theorem:
Suppose we have two triangles,
















This post has been edited 1 time. Last edited by parmenides51, Aug 21, 2019, 1:14 AM