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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
+1 w
jlacosta
Apr 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Rhombus EVAN
62861   71
N 11 minutes ago by ihategeo_1969
Source: USA January TST for IMO 2017, Problem 2
Let $ABC$ be a triangle with altitude $\overline{AE}$. The $A$-excircle touches $\overline{BC}$ at $D$, and intersects the circumcircle at two points $F$ and $G$. Prove that one can select points $V$ and $N$ on lines $DG$ and $DF$ such that quadrilateral $EVAN$ is a rhombus.

Danielle Wang and Evan Chen
71 replies
62861
Feb 23, 2017
ihategeo_1969
11 minutes ago
A and B play a game
EthanWYX2009   3
N 27 minutes ago by nitr4m
Source: 2025 TST 23
Let \( n \geq 2 \) be an integer. Two players, Alice and Bob, play the following game on the complete graph \( K_n \): They take turns to perform operations, where each operation consists of coloring one or two edges that have not been colored yet. The game terminates if at any point there exists a triangle whose three edges are all colored.

Prove that there exists a positive number \(\varepsilon\), Alice has a strategy such that, no matter how Bob colors the edges, the game terminates with the number of colored edges not exceeding
\[
\left( \frac{1}{4} - \varepsilon \right) n^2 + n.
\]
3 replies
EthanWYX2009
Mar 29, 2025
nitr4m
27 minutes ago
Problem 3
SlovEcience   1
N 34 minutes ago by kokcio
Find all real numbers \( k \) such that the following inequality holds for all \( a, b, c \geq 0 \):

\[
ab + bc + ca \leq \frac{(a + b + c)^2}{3} + k \cdot \max \{ (a - b)^2, (b - c)^2, (c - a)^2 \} \leq a^2 + b^2 + c^2
\]
1 reply
SlovEcience
Apr 9, 2025
kokcio
34 minutes ago
Inequality with a,b,c
GeoMorocco   8
N 34 minutes ago by GeoMorocco
Source: Morocco Training 2025
Let $   a,b,c   $ be positive real numbers such that : $   ab+bc+ca=3   $ . Prove that : $$\frac{a\sqrt{3+bc}}{b+c}+\frac{b\sqrt{3+ca}}{c+a}+\frac{c\sqrt{3+ab}}{a+b}\ge a+b+c $$
8 replies
GeoMorocco
Thursday at 9:51 PM
GeoMorocco
34 minutes ago
prove that any quadrilateral satisfying this inequality is a trapezoid
mqoi_KOLA   1
N 39 minutes ago by vgtcross
Prove that any quadrilateral satisfying this inequality is a Trapezoid/trapzium $$
|r - p| < q + s < r + p
$$where $p,r$ are lengths of parallel sides and $q,s$ are other two sides.
1 reply
mqoi_KOLA
Today at 3:48 AM
vgtcross
39 minutes ago
Prove that there exists a convex 1990-gon
orl   13
N an hour ago by akliu
Source: IMO 1990, Day 2, Problem 6, IMO ShortList 1990, Problem 16 (NET 1)
Prove that there exists a convex 1990-gon with the following two properties :

a.) All angles are equal.
b.) The lengths of the 1990 sides are the numbers $ 1^2$, $ 2^2$, $ 3^2$, $ \cdots$, $ 1990^2$ in some order.
13 replies
orl
Nov 11, 2005
akliu
an hour ago
cricket jumping in dominoes
YLG_123   2
N an hour ago by Bonime
Source: Brazil EGMO TST2 2023 #4
A cricket wants to move across a $2n \times 2n$ board that is entirely covered by dominoes, with no overlap. He jumps along the vertical lines of the board, always going from the midpoint of the vertical segment of a $1 \times 1$ square to another midpoint of the vertical segment, according to the rules:

$(i)$ When the domino is horizontal, the cricket jumps to the opposite vertical segment (such as from $P_2$ to $P_3$);

$(ii)$ When the domino is vertical downwards in relation to its position, the cricket jumps diagonally downwards (such as from $P_1$ to $P_2$);

$(iii)$ When the domino is vertically upwards relative to its position, the cricket jumps diagonally upwards (such as from $P_3$ to $P_4$).

The image illustrates a possible covering and path on the $4 \times 4$ board.
Considering that the starting point is on the first vertical line and the finishing point is on the last vertical line, prove that, regardless of the covering of the board and the height at which the cricket starts its path, the path ends at the same initial height.
2 replies
YLG_123
Jan 29, 2024
Bonime
an hour ago
Inspired by Ruji2018252
sqing   3
N an hour ago by kokcio
Source: Own
Let $ a,b,c $ be reals such that $ a^2+b^2+c^2-2a-4b-4c=7. $ Prove that
$$ -4\leq 2a+b+2c\leq 20$$$$5-4\sqrt 3\leq a+b+c\leq 5+4\sqrt 3$$$$ 11-4\sqrt {14}\leq a+2b+3c\leq 11+4\sqrt {14}$$
3 replies
sqing
Apr 10, 2025
kokcio
an hour ago
Combinatorics game
VicKmath7   3
N an hour ago by Topiary
Source: First JBMO TST of France 2020, Problem 1
Players A and B play a game. They are given a box with $n=>1$ candies. A starts first. On a move, if in the box there are $k$ candies, the player chooses positive integer $l$ so that $l<=k$ and $(l, k) =1$, and eats $l$ candies from the box. The player who eats the last candy wins. Who has winning strategy, in terms of $n$.
3 replies
VicKmath7
Mar 4, 2020
Topiary
an hour ago
Find all such primes
Entrepreneur   2
N an hour ago by straight
Source: Own
Find all primes $p,q\;\&\;r$ such that $$\color{blue}{pq=r^2+r+1.}$$
2 replies
Entrepreneur
2 hours ago
straight
an hour ago
Inspired by giangtruong13
sqing   5
N 2 hours ago by kokcio
Source: Own
Let $ a,b,c,d\geq 0 ,a-b+d=21 $ and $ a+3b+4c=101 $. Prove that
$$ 61\leq  a+b+2c+d\leq \frac{265}{3}$$$$- \frac{2121}{2}\leq   ab+bc-2cd+da\leq \frac{14045}{12}$$$$\frac{519506-7471\sqrt{7471}}{27}\leq   ab+bc-2cd+3da\leq 33620$$
5 replies
sqing
Yesterday at 2:57 AM
kokcio
2 hours ago
four points lie on a circle
pohoatza   76
N 2 hours ago by Bonime
Source: IMO Shortlist 2006, Geometry 2, AIMO 2007, TST 1, P2
Let $ ABCD$ be a trapezoid with parallel sides $ AB > CD$. Points $ K$ and $ L$ lie on the line segments $ AB$ and $ CD$, respectively, so that $AK/KB=DL/LC$. Suppose that there are points $ P$ and $ Q$ on the line segment $ KL$ satisfying \[\angle{APB} = \angle{BCD}\qquad\text{and}\qquad \angle{CQD} = \angle{ABC}.\]Prove that the points $ P$, $ Q$, $ B$ and $ C$ are concyclic.

Proposed by Vyacheslev Yasinskiy, Ukraine
76 replies
pohoatza
Jun 28, 2007
Bonime
2 hours ago
TST Junior Romania 2025
ant_   7
N 2 hours ago by MR.1
Source: ssmr
Consider the isosceles triangle $ABC$, with $\angle BAC > 90^\circ$, and the circle $\omega$ with center $A$ and radius $AC$. Denote by $M$ the midpoint of side $AC$. The line $BM$ intersects the circle $\omega$ for the second time in $D$. Let $E$ be a point on the circle $\omega$ such that $BE \perp AC$ and $DE \cap AC = {N}$. Show that $AN = 2AB$.
7 replies
ant_
Yesterday at 5:01 PM
MR.1
2 hours ago
NEPAL TST 2025 DAY 2
Tony_stark0094   3
N 2 hours ago by ThatApollo777
Consider an acute triangle $\Delta ABC$. Let $D$ and $E$ be the feet of the altitudes from $A$ to $BC$ and from $B$ to $AC$ respectively.

Define $D_1$ and $D_2$ as the reflections of $D$ across lines $AB$ and $AC$, respectively. Let $\Gamma$ be the circumcircle of $\Delta AD_1D_2$. Denote by $P$ the second intersection of line $D_1B$ with $\Gamma$, and by $Q$ the intersection of ray $EB$ with $\Gamma$.

If $O$ is the circumcenter of $\Delta ABC$, prove that $O$, $D$, and $Q$ are collinear if and only if quadrilateral $BCQP$ can be inscribed within a circle.
3 replies
Tony_stark0094
Today at 8:40 AM
ThatApollo777
2 hours ago
AE = AC, if <ACP =<ABC, line reflection, circumcircle related
parmenides51   3
N Dec 23, 2022 by bin_sherlo
Source: 2018 Romania JBMO TST 1.3
Let $ABC$ be a triangle with $AB > AC$. Point $P \in (AB)$ is such that $\angle ACP = \angle ABC$. Let $D$ be the reflection of $P$ into the line $AC$ and let $E$ be the point in which the circumcircle of $BCD$ meets again the line $AC$. Prove that $AE = AC$.
3 replies
parmenides51
Jun 1, 2020
bin_sherlo
Dec 23, 2022
AE = AC, if <ACP =<ABC, line reflection, circumcircle related
G H J
Source: 2018 Romania JBMO TST 1.3
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parmenides51
30630 posts
#1
Y by
Let $ABC$ be a triangle with $AB > AC$. Point $P \in (AB)$ is such that $\angle ACP = \angle ABC$. Let $D$ be the reflection of $P$ into the line $AC$ and let $E$ be the point in which the circumcircle of $BCD$ meets again the line $AC$. Prove that $AE = AC$.
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RagvaloD
4900 posts
#2
Y by
$ \angle ACD= \angle ACP = \angle ABC$ and $\angle CAD= \angle CAB$ so $\triangle ABC \sim \triangle ACD \to AC^2=AD*AB$
$\angle EBD=\angle ACD=\angle ABC$ so $\angle EBA= \angle DBC= \angle DEC$ $\angle EAD= \angle EAB$ so $\triangle EAB \sim \triangle DAE \to AE^2=AB*AD$
So $AE=AC$
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Mahdi_Mashayekhi
689 posts
#3
Y by
Let AB meet circle at S.
∠ACD = ∠ACP = ∠ABC = ∠AES so SE = DC = PC.
∠CPA = ∠ACB = ∠ASE and ∠ACP = ∠ABC = ∠AES and SE = PC so triangles AES and APC are congruent so AE = AC.
we're Done.
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bin_sherlo
688 posts
#4 • 1 Y
Y by erkosfobiladol
$\angle ACP=\angle ABC$ So $AC^2=AP.AB$ We will show $AE^2=AP.AB$ This means we must show that $\angle ABE=\angle PEA$
If $\angle ACP=\alpha$ $\angle APD=\beta$ $\angle ADE=\theta$, we can say that $\angle PDC=90-\alpha$ so $\angle EDC=90+\beta+\theta-\alpha$. $EBCD$ is cyclic so $\angle EBC=90+\alpha+\beta-\theta$ We know that $\angle ABC=\alpha$ $\implies$ $\angle EBA=90-\beta-\theta$
$\beta=\angle ADP=\angle DPA$ and $\theta=\angle ADE=\angle APE$ $\implies$ $\angle PEA=90-\beta-\theta$
This post has been edited 4 times. Last edited by bin_sherlo, Dec 24, 2022, 7:21 PM
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