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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
problem interesting
Cobedangiu   6
N 17 minutes ago by Cobedangiu
Let $a=3k^2+3k+1 (a,k \in N)$
$i)$ Prove that: $a^2$ is the sum of $3$ square numbers
$ii)$ Let $b \vdots a$ and $b$ is the sum of $3$ square numbers. Prove that: $b^n$ is the sum of $3$ square numbers
6 replies
Cobedangiu
Yesterday at 5:06 AM
Cobedangiu
17 minutes ago
another problem
kjhgyuio   1
N 19 minutes ago by lpieleanu
........
1 reply
kjhgyuio
an hour ago
lpieleanu
19 minutes ago
2^x+3^x = yx^2
truongphatt2668   9
N 19 minutes ago by Jackson0423
Prove that the following equation has infinite integer solutions:
$$2^x+3^x = yx^2$$
9 replies
truongphatt2668
Apr 22, 2025
Jackson0423
19 minutes ago
Show that XD and AM meet on Gamma
MathStudent2002   92
N 22 minutes ago by Ilikeminecraft
Source: IMO Shortlist 2016, Geometry 2
Let $ABC$ be a triangle with circumcircle $\Gamma$ and incenter $I$ and let $M$ be the midpoint of $\overline{BC}$. The points $D$, $E$, $F$ are selected on sides $\overline{BC}$, $\overline{CA}$, $\overline{AB}$ such that $\overline{ID} \perp \overline{BC}$, $\overline{IE}\perp \overline{AI}$, and $\overline{IF}\perp \overline{AI}$. Suppose that the circumcircle of $\triangle AEF$ intersects $\Gamma$ at a point $X$ other than $A$. Prove that lines $XD$ and $AM$ meet on $\Gamma$.

Proposed by Evan Chen, Taiwan
92 replies
MathStudent2002
Jul 19, 2017
Ilikeminecraft
22 minutes ago
IMO 2010 Problem 5
mavropnevma   54
N an hour ago by shanelin-sigma
Each of the six boxes $B_1$, $B_2$, $B_3$, $B_4$, $B_5$, $B_6$ initially contains one coin. The following operations are allowed

Type 1) Choose a non-empty box $B_j$, $1\leq j \leq 5$, remove one coin from $B_j$ and add two coins to $B_{j+1}$;

Type 2) Choose a non-empty box $B_k$, $1\leq k \leq 4$, remove one coin from $B_k$ and swap the contents (maybe empty) of the boxes $B_{k+1}$ and $B_{k+2}$.

Determine if there exists a finite sequence of operations of the allowed types, such that the five boxes $B_1$, $B_2$, $B_3$, $B_4$, $B_5$ become empty, while box $B_6$ contains exactly $2010^{2010^{2010}}$ coins.

Proposed by Hans Zantema, Netherlands
54 replies
mavropnevma
Jul 8, 2010
shanelin-sigma
an hour ago
3 var inequality
sqing   0
an hour ago
Source: Own
Let $ a,b,c>0 . $ Prove that
$$ \left(1 +\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right )\geq  \frac{8}{3}\left(1+\frac{a+b}{b+c}+ \frac{b+c}{a+b}\right)$$$$ \left(1 +\frac{a^2}{b^2}\right)\left(1+\frac{b^2}{c^2}\right)\left(1+\frac{c^2}{a^2}\right )\geq \frac{8}{3}\left( 1+\frac{a^2+bc}{b^2+ca}+\frac{b^2+ca  }{a^2+bc}\right)$$
0 replies
sqing
an hour ago
0 replies
IMO ShortList 1998, geometry problem 5
nttu   32
N an hour ago by lpieleanu
Source: IMO ShortList 1998, geometry problem 5
Let $ABC$ be a triangle, $H$ its orthocenter, $O$ its circumcenter, and $R$ its circumradius. Let $D$ be the reflection of the point $A$ across the line $BC$, let $E$ be the reflection of the point $B$ across the line $CA$, and let $F$ be the reflection of the point $C$ across the line $AB$. Prove that the points $D$, $E$ and $F$ are collinear if and only if $OH=2R$.
32 replies
1 viewing
nttu
Oct 14, 2004
lpieleanu
an hour ago
a_n < b_n for large n
tastymath75025   11
N 2 hours ago by torch
Source: 2017 ELMO Shortlist A1
Let $0<k<\frac{1}{2}$ be a real number and let $a_0, b_0$ be arbitrary real numbers in $(0,1)$. The sequences $(a_n)_{n\ge 0}$ and $(b_n)_{n\ge 0}$ are then defined recursively by

$$a_{n+1} = \dfrac{a_n+1}{2} \text{ and } b_{n+1} = b_n^k$$
for $n\ge 0$. Prove that $a_n<b_n$ for all sufficiently large $n$.

Proposed by Michael Ma
11 replies
tastymath75025
Jul 3, 2017
torch
2 hours ago
primes,exponentials,factorials
skellyrah   4
N 2 hours ago by aaravdodhia
find all primes p,q such that $$ \frac{p^q+q^p-p-q}{p!-q!} $$is a prime number
4 replies
skellyrah
Yesterday at 6:31 PM
aaravdodhia
2 hours ago
Special line through antipodal
Phorphyrion   9
N 2 hours ago by ihategeo_1969
Source: 2025 Israel TST Test 1 P2
Triangle $\triangle ABC$ is inscribed in circle $\Omega$. Let $I$ denote its incenter and $I_A$ its $A$-excenter. Let $N$ denote the midpoint of arc $BAC$. Line $NI_A$ meets $\Omega$ a second time at $T$. The perpendicular to $AI$ at $I$ meets sides $AC$ and $AB$ at $E$ and $F$ respectively. The circumcircle of $\triangle BFT$ meets $BI_A$ a second time at $P$, and the circumcircle of $\triangle CET$ meets $CI_A$ a second time at $Q$. Prove that $PQ$ passes through the antipodal to $A$ on $\Omega$.
9 replies
Phorphyrion
Oct 28, 2024
ihategeo_1969
2 hours ago
Triangle form by perpendicular bisector
psi241   50
N 3 hours ago by Ilikeminecraft
Source: IMO Shortlist 2018 G5
Let $ABC$ be a triangle with circumcircle $\Omega$ and incentre $I$. A line $\ell$ intersects the lines $AI$, $BI$, and $CI$ at points $D$, $E$, and $F$, respectively, distinct from the points $A$, $B$, $C$, and $I$. The perpendicular bisectors $x$, $y$, and $z$ of the segments $AD$, $BE$, and $CF$, respectively determine a triangle $\Theta$. Show that the circumcircle of the triangle $\Theta$ is tangent to $\Omega$.
50 replies
psi241
Jul 17, 2019
Ilikeminecraft
3 hours ago
Sequence with infinite primes which we see again and again and again
Assassino9931   3
N 3 hours ago by grupyorum
Source: Balkan MO Shortlist 2024 N6
Let $c$ be a positive integer. Prove that there are infinitely many primes, each of which divides at least one term of the sequence $a_1 = c$, $a_{n+1} = a_n^3 + c$.
3 replies
Assassino9931
Apr 27, 2025
grupyorum
3 hours ago
Integer roots preserved under linear function of polynomial
alifenix-   23
N 3 hours ago by Mathandski
Source: USEMO 2019/2
Let $\mathbb{Z}[x]$ denote the set of single-variable polynomials in $x$ with integer coefficients. Find all functions $\theta : \mathbb{Z}[x] \to \mathbb{Z}[x]$ (i.e. functions taking polynomials to polynomials)
such that
[list]
[*] for any polynomials $p, q \in \mathbb{Z}[x]$, $\theta(p + q) = \theta(p) + \theta(q)$;
[*] for any polynomial $p \in \mathbb{Z}[x]$, $p$ has an integer root if and only if $\theta(p)$ does.
[/list]

Carl Schildkraut
23 replies
alifenix-
May 23, 2020
Mathandski
3 hours ago
BMO 2024 SL A3
MuradSafarli   5
N 4 hours ago by Nuran2010

A3.
Find all triples \((a, b, c)\) of positive real numbers that satisfy the system:
\[
\begin{aligned}
11bc - 36b - 15c &= abc \\
12ca - 10c - 28a &= abc \\
13ab - 21a - 6b &= abc.
\end{aligned}
\]
5 replies
MuradSafarli
Apr 27, 2025
Nuran2010
4 hours ago
<OBC =<ODC wanted, inside #, perp. bisectors, angle bisector
parmenides51   3
N Jun 16, 2021 by zuss77
Source: 2021 JWO Flanders Juniors MO p2
In a parallelogram $ABCD$, the bisector of obtuse angle $\angle A$ intersects the side $[BC]$ at the point $P$ and the line $CD$ at the point $Q$. The perpendicular bisectors of triangle $\vartriangle PCQ$ intersect at point $O$. Prove that $\angle OBC = \angle ODC$ .
3 replies
parmenides51
May 29, 2021
zuss77
Jun 16, 2021
<OBC =<ODC wanted, inside #, perp. bisectors, angle bisector
G H J
Source: 2021 JWO Flanders Juniors MO p2
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parmenides51
30650 posts
#1
Y by
In a parallelogram $ABCD$, the bisector of obtuse angle $\angle A$ intersects the side $[BC]$ at the point $P$ and the line $CD$ at the point $Q$. The perpendicular bisectors of triangle $\vartriangle PCQ$ intersect at point $O$. Prove that $\angle OBC = \angle ODC$ .
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EmilXM
378 posts
#2
Y by
parmenides51 wrote:
In a parallelogram $ABCD$, the bisector of obtuse angle $\angle A$ intersects the side $[BC]$ at the point $P$ and the line $CD$ at the point $Q$. The perpendicular bisectors of triangle $\vartriangle PCQ$ intersect at point $O$. Prove that $\angle OBC = \angle ODC$ .
Let $\angle DAB = 2 \alpha$.
$DQ || AB \Longrightarrow \angle CQP = \alpha$, $\angle QCP = 180^0 - 2\alpha$.
$O$ is circumcircle of $\triangle PCQ \Longrightarrow \angle OCP = \angle OQC = \angle OCQ = 90^0 - \alpha$, $OC = OQ$.
$ABCD$ is parallelogram $\Longrightarrow \angle DCB = 2\alpha$.
$ADQ$ is isosceles $\Longrightarrow DQ = AD = BC$.
$OC = OQ$, $DQ = BC$, $\angle DOQ = 90^0-\alpha = \angle BOC \Longrightarrow \triangle DOQ \cong \triangle BOC \Longrightarrow \angle OBC = \angle ODC \blacksquare$.
Z K Y
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celilcelil
164 posts
#3
Y by
Sketch of solution
$\bullet$ Find $AB=BP$ and $CP=CQ$ with easy angle chasing.
$\bullet$ Find that $\angle OPC = \angle OCQ$ using that $O$ is circumcenter of $\triangle CPQ$ and $CP=CQ$
Then find that $\triangle BPO \cong\triangle DCO$ and get desired result.
This post has been edited 1 time. Last edited by celilcelil, May 29, 2021, 8:35 AM
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zuss77
520 posts
#4
Y by
It goes way back, even before IMO 2007 P2 it was at least at St.Petersburg 1986.
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N Quick Reply
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