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FE solution too simple?
Yiyj1   9
N a minute ago by jasperE3
Source: 101 Algebra Problems from the AMSP
Find all functions $f: \mathbb{R} \rightarrow \mathbb{R}$ such that the equality $$f(f(x)+y) = f(x^2-y)+4f(x)y$$holds for all pairs of real numbers $(x,y)$.

My solution

I feel like my solution is too simple. Is there something I did wrong or something I missed?
9 replies
Yiyj1
Apr 9, 2025
jasperE3
a minute ago
interesting function equation (fe) in IR
skellyrah   2
N 2 minutes ago by jasperE3
Source: mine
find all function F: IR->IR such that $$ xf(f(y)) + yf(f(x)) = f(xf(y)) + f(xy) $$
2 replies
skellyrah
Today at 9:51 AM
jasperE3
2 minutes ago
Complicated FE
XAN4   1
N 4 minutes ago by jasperE3
Source: own
Find all solutions for the functional equation $f(xyz)+\sum_{cyc}f(\frac{yz}x)=f(x)\cdot f(y)\cdot f(z)$, in which $f$: $\mathbb R^+\rightarrow\mathbb R^+$
Note: the solution is actually quite obvious - $f(x)=x^n+\frac1{x^n}$, but the proof is important.
Note 2: it is likely that the result can be generalized into a more advanced questions, potentially involving more bash.
1 reply
XAN4
Today at 11:53 AM
jasperE3
4 minutes ago
IMO Shortlist 2011, G4
WakeUp   125
N 30 minutes ago by Davdav1232
Source: IMO Shortlist 2011, G4
Let $ABC$ be an acute triangle with circumcircle $\Omega$. Let $B_0$ be the midpoint of $AC$ and let $C_0$ be the midpoint of $AB$. Let $D$ be the foot of the altitude from $A$ and let $G$ be the centroid of the triangle $ABC$. Let $\omega$ be a circle through $B_0$ and $C_0$ that is tangent to the circle $\Omega$ at a point $X\not= A$. Prove that the points $D,G$ and $X$ are collinear.

Proposed by Ismail Isaev and Mikhail Isaev, Russia
125 replies
WakeUp
Jul 13, 2012
Davdav1232
30 minutes ago
Z[x], P(\sqrt[3]5+\sqrt[3]25)=5+\sqrt[3]5
jasperE3   5
N an hour ago by Assassino9931
Source: VJIMC 2013 2.3
Prove that there is no polynomial $P$ with integer coefficients such that $P\left(\sqrt[3]5+\sqrt[3]{25}\right)=5+\sqrt[3]5$.
5 replies
jasperE3
May 31, 2021
Assassino9931
an hour ago
IMO problem 1
iandrei   77
N an hour ago by YaoAOPS
Source: IMO ShortList 2003, combinatorics problem 1
Let $A$ be a $101$-element subset of the set $S=\{1,2,\ldots,1000000\}$. Prove that there exist numbers $t_1$, $t_2, \ldots, t_{100}$ in $S$ such that the sets \[ A_j=\{x+t_j\mid x\in A\},\qquad j=1,2,\ldots,100  \] are pairwise disjoint.
77 replies
iandrei
Jul 14, 2003
YaoAOPS
an hour ago
Divisibility on 101 integers
BR1F1SZ   4
N an hour ago by BR1F1SZ
Source: Argentina Cono Sur TST 2024 P2
There are $101$ positive integers $a_1, a_2, \ldots, a_{101}$ such that for every index $i$, with $1 \leqslant i \leqslant 101$, $a_i+1$ is a multiple of $a_{i+1}$. Determine the greatest possible value of the largest of the $101$ numbers.
4 replies
BR1F1SZ
Aug 9, 2024
BR1F1SZ
an hour ago
2^x+3^x = yx^2
truongphatt2668   2
N an hour ago by CM1910
Prove that the following equation has infinite integer solutions:
$$2^x+3^x = yx^2$$
2 replies
1 viewing
truongphatt2668
Yesterday at 3:38 PM
CM1910
an hour ago
Prove perpendicular
shobber   29
N 2 hours ago by zuat.e
Source: APMO 2000
Let $ABC$ be a triangle. Let $M$ and $N$ be the points in which the median and the angle bisector, respectively, at $A$ meet the side $BC$. Let $Q$ and $P$ be the points in which the perpendicular at $N$ to $NA$ meets $MA$ and $BA$, respectively. And $O$ the point in which the perpendicular at $P$ to $BA$ meets $AN$ produced.

Prove that $QO$ is perpendicular to $BC$.
29 replies
shobber
Apr 1, 2006
zuat.e
2 hours ago
The smallest of sum of elements
hlminh   1
N 2 hours ago by nguyenhuybao_06
Let $S=\{1,2,...,2014\}$ and $X\subset S$ such that for all $a,b\in X,$ if $a+b\leq 2014$ then $a+b\in X.$ Find the smallest of sum of all elements of $X.$
1 reply
hlminh
2 hours ago
nguyenhuybao_06
2 hours ago
Inequalities
Scientist10   0
2 hours ago
If $x, y, z \in \mathbb{R}$, then prove that the following inequality holds:
\[
\sum_{\text{cyc}} \sqrt{1 + \left(x\sqrt{1 + y^2} + y\sqrt{1 + x^2}\right)^2} \geq \sum_{\text{cyc}} xy + 2\sum_{\text{cyc}} x
\]
0 replies
+1 w
Scientist10
2 hours ago
0 replies
NT from ukr contest
mshtand1   3
N 2 hours ago by ravengsd
Source: Ukrainian TST for RMM 2021(2) and EGMO 2022 P2
Find the greatest positive integer $n$ such that there exist positive integers $a_1, a_2, ..., a_n$ for which the following holds $a_{k+2} = \dfrac{(a_{k+1}+a_k)(a_{k+1}+1)}{a_k}$ for all $1 \le k \le n-2$.
Proposed by Mykhailo Shtandenko and Oleksii Masalitin
3 replies
mshtand1
Oct 2, 2021
ravengsd
2 hours ago
Posted before ,but no solution
Nuran2010   1
N 2 hours ago by Nuran2010
Source: 1220 Number Theory Problems
Find all positive integers $n$ where $49n^3+42n^2+11n+1$ is a perfect cube
1 reply
Nuran2010
Apr 11, 2025
Nuran2010
2 hours ago
Not so common problem
m4thbl3nd3r   1
N Apr 15, 2025 by lbh_qys
With each $x\ne -2,-3$, define $f_1(x)=-\frac{3x+7}{x+2},f_2(x)=f_1(f_1(x))=-\frac{3f_1(x)+7}{f_1(x)+2},f_3(x)=f_1(f_2(x))=-\frac{3f_2(x)+7}{f_2(x)+2},\dots$ Find all integers $x$ such that $f_{269}(x)$ is an integer.
1 reply
m4thbl3nd3r
Apr 15, 2025
lbh_qys
Apr 15, 2025
Not so common problem
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m4thbl3nd3r
282 posts
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With each $x\ne -2,-3$, define $f_1(x)=-\frac{3x+7}{x+2},f_2(x)=f_1(f_1(x))=-\frac{3f_1(x)+7}{f_1(x)+2},f_3(x)=f_1(f_2(x))=-\frac{3f_2(x)+7}{f_2(x)+2},\dots$ Find all integers $x$ such that $f_{269}(x)$ is an integer.
This post has been edited 1 time. Last edited by m4thbl3nd3r, Apr 15, 2025, 6:17 AM
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lbh_qys
549 posts
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hint
This post has been edited 1 time. Last edited by lbh_qys, Apr 15, 2025, 7:24 AM
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