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what actually happens after the usamo
bubby617   1
N 3 hours ago by Indpsolver
i keep getting different answers for how the selection process gets down from the usamo winners to the IMO team so can someone set the record straight for me
1 reply
bubby617
Today at 2:47 AM
Indpsolver
3 hours ago
Inequalities
sqing   4
N 4 hours ago by DAVROS
Let $ a,b,c\geq 0 $ and $a+b+c=1$. Prove that$$a^3b+b^3c+c^3a+\frac{473}{256}abc\le\frac{27}{256}$$Equality holds when $ a=b=c=\frac{1}{3} $ or $ a=0,b=\frac{3}{4},c=\frac{1}{4} $ or $ a=\frac{1}{4} ,b=0,c=\frac{3}{4} $
or $ a=\frac{3}{4} ,b=\frac{1}{4},c=0. $
4 replies
sqing
Yesterday at 3:55 PM
DAVROS
4 hours ago
Geometry Problem
JetFire008   1
N 4 hours ago by JetFire008
Equilateral $\triangle ADC$ is drawn externally on side $AC$ of $\triangle ABC$. Point $P$ is taken on $BD$. Find $\angle APC$ if $BD=PA+PB+PC$.
1 reply
JetFire008
5 hours ago
JetFire008
4 hours ago
k Discord Server
mathprodigy2011   14
N Today at 3:00 AM by KF329
Theres a server where we are all like discussing problems+helping each other practice. Hopefully you guys can join.

https://discord.gg/6hN3w4eK
14 replies
mathprodigy2011
Friday at 11:00 PM
KF329
Today at 3:00 AM
USAMO question
bubby617   2
N Today at 2:44 AM by Andyluo
if i had qualified for the usa(j)mo (i wish), would i have been flown out for free like mathcounts nationals or do you have to plan your own trip for going to the usamo
2 replies
bubby617
Today at 2:32 AM
Andyluo
Today at 2:44 AM
A hard inequality
JK1603JK   2
N Today at 2:25 AM by sqing
Let a,b,c\ge 0: a+b+c=3. Prove \frac{1}{abc}+\frac{12}{a^2b+b^2c+c^2a}\ge 5.
2 replies
JK1603JK
Today at 1:40 AM
sqing
Today at 2:25 AM
Number theory question with many (confusing) variables
urfinalopp   2
N Today at 2:07 AM by urfinalopp
Given m,n,p,q \in \mathbb{N+}, find all solutions to 2^{m}3^{n}+5^{p}=7^{q}$

One of the paths I've found is to boil it down to solving two non-simultaneous equations 2^{m_1}+5^{n_1}=7^{q_1} and
7^{m_1}+5^{n_1}=2^{q_1} but its too hard. Any other approaches/solutions or a continuation of this path?
2 replies
urfinalopp
Yesterday at 4:06 PM
urfinalopp
Today at 2:07 AM
Number theory national Olympiad
LoRD2022   2
N Today at 12:09 AM by alexheinis
Find all polynomials with integer coefficients such that, $a^2+b^2-c^2|P(a)+P(b)-P(c)$ for all $a,b,c \in mathbb{Z}$.
2 replies
LoRD2022
Yesterday at 8:54 PM
alexheinis
Today at 12:09 AM
Introduction & Intermediate C&P study guide!
HamstPan38825   25
N Yesterday at 11:47 PM by Andyluo
This took me quite a while to make, but enjoy!

Introduction to C&P (suitable for AMC 8, AMC 10/12)
Chapter 1 - This is like the "introduction", which is pretty easy and is not very important.
Chapter 2 - VERY important! Study this chapter closely, as it contains techniques that will be used again and again in harder problems.
Chapter 3 - Another quite important chapter, though not as important as chapter 2. This chapter covers some of the most confusing parts in C&P and even I can't distinguish that well in that chapter.
Chapter 4 - Interesting but very basic. Not that important, really.
Chapter 5 - Another interesting chapter, which should be studied in greater detail than Chapter 4. The distinguishability section is most important here.
Chapter 6 - Not much, but attempt the problems and read the examples since many of them are very interesting.
Chapter 7 - Pretty important chapter, make sure you read all the sections but not very interesting.
Chapter 8 - Another one of the VERY important sections - make sure read this section closely and do all the problems, since I still compare apples to oranges sometimes.
Chapter 9 - Interesting, but not very important. More important is the concept to "Think About It!"
Chapter 10 - The only topic in the entire C&P series that covers Geometric Probability, this chapter doesn't go into enough detail. Read it closely to get the basics, but I'd recommend doing more practice on Geometric Probability (I'll be making a handout!)
Chapter 11 - This chapter is not really important, reference the section in Intermediate C&P for a deeper understanding of Expected value.
Chapter 12 - Pretty important chapter, study it closely as it gives you the tools to prove combinatorial identities and Pascal's triangle is quite useful.
Chapter 13 - Just get the Hockey Stick Identity - not very useful chapter. Distributions will also be covered in Intermediate C&P.
Chapter 14 - A bit important, but not very - The binomial theorem is easy to master, but if you need more practice read the section in IA.
Chapter 15 - Similar to chapter 6, read all the examples and attempt all the problems here.

AMC 10/12 Chapters: 2, 3, 5, 6, 7, 8, 10, 12, 15

Intermediate C&P Suitable for late AMC 12, AIME + olympiads
Chapter 1 - Review this section thoroughly though there are no exercises here.
Chapter 2 - If you've learned set theory before, this chapter should be a review, but nonetheless skim over this chapter.
Chapter 3 - ANOTHER IMPORTANT CHAPTER! PIE is very important and might be a bit complicated, so study this chapter closely.
Chapter 4 - This chapter is also quite important - Make sure you master both parts of this chapter.
Chapter 5 - A good chapter, but it's a bit too short for my liking. Read extra handouts on the Pigeonhole Principle.
Chapter 6 - Another great chapter - attempt all the problems in this chapter!
Chapter 7 - Yet another very important chapter - distributions tend to pop up all over the place. Attempt all the problems here.
Chapter 8 - This isn't really a chapter - if you've mastered Mathematical Induction, you can just skip this but I recommend doing the problems.
Chapter 9 - This is really just the introduction to Chapter 10, but nonetheless do some of the problems to get a firm recursion basis.
Chapter 10 - Another VERY IMPORTANT CHAPTER! The recursion section is more important than the Catalan Number section unless you're preparing for olympiads.
Chapter 11 - Past this chapter, the concepts start to get quite advanced. This is an interesting chapter and is quite important, so do many of the problems here.
Chapter 12 - A great chapter! This chapter is quite general, but try to learn how to prove combinatorial identities on your own.
Chapter 13 - A quite complex chapter, not that important unless you're preparing for olympiads.
Chapter 14 - A hard but great chapter! GFs are hacks to many common counting problems.
Chapter 15 - Just skip this chapter unless you're doing the Putnam or olympiads, since it's basically nonexistent in the AMC/AIMEs.
Chapter 16 - Many of the problems here are very hard, but do as much as you can here! Try to attempt every single problem though they are very hard.

AMC 12 chapters: 1, 3, 4, 5, 6, 7, 9, 10
AIME chapters: 1, 3, 4, 5, 6, 7, 9, 10, 11
Olympiad chapters: 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15 [basically almost all of them rip]
25 replies
HamstPan38825
Dec 7, 2020
Andyluo
Yesterday at 11:47 PM
Number theory national Olympiad
LoRD2022   0
Yesterday at 9:09 PM
Find all polynomials with integer coefficients such that, $a^2+b^2-c^2|P(a)+P(b)-P(c)$ for all $a,b,c \in \mathbb{Z}$.
0 replies
LoRD2022
Yesterday at 9:09 PM
0 replies
a+b+c=3 ine
jokehim   4
N Mar 21, 2025 by lbh_qys
Problem. Given non-negative real numbers $a,b,c$ satisfying $a+b+c=3.$ Prove that $$\color{black}{\frac{a\left(b+c\right)}{bc+3}+\frac{b\left(c+a\right)}{ca+3}+\frac{c\left(a+b\right)}{ab+3}\le \frac{3}{2}.}$$Proposed by Phan Ngoc Chau
4 replies
jokehim
Mar 18, 2025
lbh_qys
Mar 21, 2025
a+b+c=3 ine
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jokehim
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Problem. Given non-negative real numbers $a,b,c$ satisfying $a+b+c=3.$ Prove that $$\color{black}{\frac{a\left(b+c\right)}{bc+3}+\frac{b\left(c+a\right)}{ca+3}+\frac{c\left(a+b\right)}{ab+3}\le \frac{3}{2}.}$$Proposed by Phan Ngoc Chau
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Cool12345678
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Since $(2,0,0)$ majorizes $(1,1,0)$ and given the condition $a+b+c=3$, by Muirhead, we rewrite $$\sum_{cyc} \frac{a\left(b+c\right)}{bc+3}\leq\sum_{cyc} \frac{a\left(3-a\right)}{a^2+3}$$
Now, let $f(x)=\frac{x\left(3-x\right)}{x^2+3}$. Then, setting $y=\frac{x\left(3-x\right)}{x^2+3}$, we get $$ x^2y + 3y = 3x-x^2 \implies x^2(y + 1) + 3y-3x = 0.$$Using the discriminant of a quadratic, we get $$9-4(y+1)(3y)\geq0 \implies y\leq \frac{1}{2}$$Therefore, the maximum value of $f(x)$ is $\frac{1}{2}$ so for all $a,b,c$ we have $$\frac{a\left(3-a\right)}{a^2+3}\leq \frac{1}{2}$$Hence, $$\sum_{cyc} \frac{a\left(3-a\right)}{a^2+3}\leq \frac{3}{2}$$as desired.
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no_room_for_error
319 posts
#3
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Cool12345678 wrote:
Since $(2,0,0)$ majorizes $(1,1,0)$ and given the condition $a+b+c=3$, by Muirhead, we rewrite $$\sum_{cyc} \frac{a\left(b+c\right)}{bc+3}\leq\sum_{cyc} \frac{a\left(3-a\right)}{a^2+3}$$

You can try $(a,b,c)=(0,1,2).$
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jokehim
1020 posts
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Any ideas?
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lbh_qys
425 posts
#5
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Let
\[
q = ab+bc+ca,\quad r = abc.
\]Adding 1 to each fraction, we obtain
\[
\sum \frac{q+3}{bc+3} \le \frac{9}{2},
\]that is,
\[
\sum \frac{1}{bc+3} \le \frac{9}{2q+6}.
\]Upon combining the terms on the left-hand side, the numerator is
\[
\sum (ab+3)(ac+3)=3r+6q+27,
\]and the denominator is
\[
\prod (ab+3)=r^2+9r+9q+27.
\]Hence, it is equivalent to proving that
\[
\frac{3r+6q+27}{r^2+9r+9q+27}\le \frac{9}{2q+6}.
\]This simplifies to
\[
4q^2+3q\le 3r^2+(21-2q)r+27.
\]In fact, since \(q\le 3\) and by Schur’s inequality \(3r\ge 4q-9\), it follows that
\[
3r^2+(21-2q)r+27\ge (4q-9)r+(21-2q)r+27=(2q+12)r+27\ge 3(q+3)r+27\ge (q+3)(4q-9)+27=4q^2+3q.
\]Thus, the original inequality holds, with equality when \((a,b,c)=(1,1,1)\) or \((a,b,c)=(3/2,3/2,0)\) and their permutations.
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