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24th PMO, Qualifying Stage #7
elpianista227 1
N
an hour ago
by elpianista227
Suppose
are the roots of the polynomial
. Let
be the unique monic polynomial whose roots are
. Find
.





1 reply

27th Philippine Mathematical Olympiad Area Stage #5
Siopao_Enjoyer 1
N
an hour ago
by Siopao_Enjoyer
Find the sum of the cubes of the roots of the polynomial p(x)=x^3-x^2+2x-3.
1 reply
Help me please
dssdgeww 1
N
an hour ago
by whwlqkd
Prove that there exists a positive integer n with 2024 prime divisors such that n| 2^n + 1
1 reply
[PMO20 Qualifying I.13] Log raised to Log
LilKirb 1
N
3 hours ago
by LilKirb
Find the sum of the solutions to the logarithmic equation:
where
is the logarithm of
to the base
![\[ x^{\log{x}} = 10^{2 - 3\log{x} + 2(\log{x})^2}\]](http://latex.artofproblemsolving.com/b/f/b/bfb8185992867a8926b5c62198a799c935771d53.png)



1 reply
Algebraic Manipulation
Darealzolt 4
N
4 hours ago
by jasperE3
It is known that
that satisfies
![\[
a^3+b^3=1957
\]](//latex.artofproblemsolving.com/5/d/8/5d8d2a40734ec6b0a9149f9a4ae3a5828d5055f3.png)
Hence, find the value of

![\[
a^3+b^3=1957
\]](http://latex.artofproblemsolving.com/5/d/8/5d8d2a40734ec6b0a9149f9a4ae3a5828d5055f3.png)
![\[
(a+b)(a+1)(b+1)=2014
\]](http://latex.artofproblemsolving.com/3/0/0/300f2d16e669a1d8d9c54b357a6eaf7a8eb5d826.png)

4 replies
not obvious trig identity!
mathmax001 1
N
4 hours ago
by joeym2011
Problem ( trigonometry )
Let
and n a positive integer
, Show that : 
Here is my take in this video: https://youtu.be/DBPyHNqk0GI?si=9r-YDuwv794AGe1p
Let



Here is my take in this video: https://youtu.be/DBPyHNqk0GI?si=9r-YDuwv794AGe1p
1 reply
confused
greenplanet2050 3
N
Today at 12:19 AM
by mathprodigy2011
um something weird happened today
I was doing the 2002 aime ii and i tried #9
I used PIE with
so for like 1 same element i did
cause there are 10 ways to choose 1 element that will be repeated. Similarly for 2 same elements it would be 
So if
the answer would be
But this number turned out to be 
Later when looking at the solution, i found out that the correct number was
But I realized that
So I was really confused of why i got the right answer somehow in my calculations.
Can someone explain why this happened? Thanks! :)
I was doing the 2002 aime ii and i tried #9
I used PIE with

so for like 1 same element i did


So if

![$(2^{10}-1)-([A_1+A_3+A_5+A_7+A_9]-[A_2+A_4+A_6+A_8+A_{10}].$](http://latex.artofproblemsolving.com/7/3/1/73130cab8af6ffb5c2638548fdf6af3ecc70a6ed.png)

Later when looking at the solution, i found out that the correct number was


Can someone explain why this happened? Thanks! :)
3 replies
Easy one
irregular22104 2
N
Yesterday at 10:27 PM
by trangbui
Given two positive integers
written on the board. We apply the following rule: At each step, we will add all the numbers that are the sum of the two numbers on the board so that the sum does not appear on the board. For example, if the two initial numbers are
; then the numbers on the board after step 1 are
; after step 2 are 
1) With
;
, prove that the number 2024 cannot appear on the board.
2) With
;
, prove that the number 2024 can appear on the board.




1) With


2) With


2 replies
