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A Characterization of Rectangles
buratinogigle   1
N 20 minutes ago by lbh_qys
Source: VN Math Olympiad For High School Students P8 - 2025
Prove that if a convex quadrilateral $ABCD$ satisfies the equation
\[
(AB + CD)^2 + (AD + BC)^2 = (AC + BD)^2,
\]then $ABCD$ must be a rectangle.
1 reply
buratinogigle
Today at 1:35 AM
lbh_qys
20 minutes ago
A Segment Bisection Problem
buratinogigle   1
N an hour ago by Giabach298
Source: VN Math Olympiad For High School Students P9 - 2025
In triangle $ABC$, let the incircle $\omega$ touch sides $BC, CA, AB$ at $D, E, F$, respectively. Let $P$ lie on the line through $D$ perpendicular to $BC$. Let $Q, R$ be the intersections of $PC, PB$ with $EF$, respectively. Let $K, L$ be the projections of $R, Q$ onto line $BC$. Let $M, N$ be the second intersections of $DQ, DR$ with the incircle $\omega$. Let $S$ be the intersection of $KM$ and $LN$. Prove that the line $DS$ bisects segment $QR$.
1 reply
buratinogigle
Today at 1:36 AM
Giabach298
an hour ago
2017 PAMO Shortlsit: Power of a prime is a sum of cubes
DylanN   3
N an hour ago by AshAuktober
Source: 2017 Pan-African Shortlist - N2
For which prime numbers $p$ can we find three positive integers $n$, $x$ and $y$ such that $p^n = x^3 + y^3$?
3 replies
DylanN
May 5, 2019
AshAuktober
an hour ago
Hard number theory
Hip1zzzil   14
N an hour ago by bonmath
Source: FKMO 2025 P6
Positive integers $a, b$ satisfy both of the following conditions.
For a positive integer $m$, if $m^2 \mid ab$, then $m = 1$.
There exist integers $x, y, z, w$ that satisfies the equation $ax^2 + by^2 = z^2 + w^2$ and $z^2 + w^2 > 0$.
Prove that there exist integers $x, y, z, w$ that satisfies the equation $ax^2 + by^2 + n = z^2 + w^2$, for each integer $n$.
14 replies
Hip1zzzil
Mar 30, 2025
bonmath
an hour ago
Constant Angle Sum
i3435   6
N an hour ago by bin_sherlo
Source: AMASCIWLOFRIAA1PD (mock oly geo contest) P3
Let $ABC$ be a triangle with circumcircle $\Omega$, $A$-angle bisector $l_A$, and $A$-median $m_A$. Suppose that $l_A$ meets $\overline{BC}$ at $D$ and meets $\Omega$ again at $M$. A line $l$ parallel to $\overline{BC}$ meets $l_A$, $m_A$ at $G$, $N$ respectively, so that $G$ is between $A$ and $D$. The circle with diameter $\overline{AG}$ meets $\Omega$ again at $J$.

As $l$ varies, show that $\angle AMN + \angle DJG$ is constant.

MP8148
6 replies
i3435
May 11, 2021
bin_sherlo
an hour ago
NEPAL TST 2025 DAY 2
Tony_stark0094   8
N 2 hours ago by cursed_tangent1434
Consider an acute triangle $\Delta ABC$. Let $D$ and $E$ be the feet of the altitudes from $A$ to $BC$ and from $B$ to $AC$ respectively.

Define $D_1$ and $D_2$ as the reflections of $D$ across lines $AB$ and $AC$, respectively. Let $\Gamma$ be the circumcircle of $\Delta AD_1D_2$. Denote by $P$ the second intersection of line $D_1B$ with $\Gamma$, and by $Q$ the intersection of ray $EB$ with $\Gamma$.

If $O$ is the circumcenter of $\Delta ABC$, prove that $O$, $D$, and $Q$ are collinear if and only if quadrilateral $BCQP$ can be inscribed within a circle.

$\textbf{Proposed by Kritesh Dhakal, Nepal.}$
8 replies
Tony_stark0094
Apr 12, 2025
cursed_tangent1434
2 hours ago
Interesting inequalities
sqing   4
N 2 hours ago by sqing
Source: Own
Let $ a,b,c\geq  0 $ and $  ab+bc+ca+abc=4$ . Prove that
$$k(a+b+c) -ab-bc\geq 4\sqrt{k(k+1)}-(k+4)$$Where $ k\geq \frac{16}{9}. $
$$ \frac{16}{9}(a+b+c) -ab-bc\geq  \frac{28}{9}$$
4 replies
sqing
4 hours ago
sqing
2 hours ago
NEPAL TST DAY 2 PROBLEM 2
Tony_stark0094   6
N 2 hours ago by cursed_tangent1434
Kritesh manages traffic on a $45 \times 45$ grid consisting of 2025 unit squares. Within each unit square is a car, facing either up, down, left, or right. If the square in front of a car in the direction it is facing is empty, it can choose to move forward. Each car wishes to exit the $45 \times 45$ grid.

Kritesh realizes that it may not always be possible for all the cars to leave the grid. Therefore, before the process begins, he will remove $k$ cars from the $45 \times 45$ grid in such a way that it becomes possible for all the remaining cars to eventually exit the grid.

What is the minimum value of $k$ that guarantees that Kritesh's job is possible?

$\textbf{Proposed by Shining Sun. USA}$
6 replies
Tony_stark0094
Apr 12, 2025
cursed_tangent1434
2 hours ago
NEPAL TST DAY-2 PROBLEM 1
Tony_stark0094   9
N 2 hours ago by cursed_tangent1434
Let the sequence $\{a_n\}_{n \geq 1}$ be defined by
\[
a_1 = 1, \quad a_{n+1} = a_n + \frac{1}{\sqrt[2024]{a_n}} \quad \text{for } n \geq 1, \, n \in \mathbb{N}
\]Prove that
\[
a_n^{2025} >n^{2024}
\]for all positive integers $n \geq 2$.

$\textbf{Proposed by Prajit Adhikari, Nepal.}$
9 replies
Tony_stark0094
Apr 12, 2025
cursed_tangent1434
2 hours ago
Inspired by Omerking
sqing   1
N 2 hours ago by lbh_qys
Source: Own
Let $ a,b,c>0 $ and $  ab+bc+ca\geq \dfrac{1}{3}. $ Prove that
$$  ka+ b+kc\geq \sqrt{\frac{4k-1}{3}}$$Where $ k\geq 1.$$$  4a+ b+4c\geq \sqrt{5}$$
1 reply
sqing
3 hours ago
lbh_qys
2 hours ago
Weird Inequality Problem
Omerking   4
N 3 hours ago by sqing
Following inequality is given:
$$3\geq ab+bc+ca\geq \dfrac{1}{3}$$Find the range of values that can be taken by :
$1)a+b+c$
$2)abc$

Where $a,b,c$ are positive reals.
4 replies
Omerking
Yesterday at 8:56 AM
sqing
3 hours ago
The locus of P with supplementary angles condition
WakeUp   3
N Apr 4, 2025 by Nari_Tom
Source: Baltic Way 2001
Given a rhombus $ABCD$, find the locus of the points $P$ lying inside the rhombus and satisfying $\angle APD+\angle BPC=180^{\circ}$.
3 replies
WakeUp
Nov 17, 2010
Nari_Tom
Apr 4, 2025
The locus of P with supplementary angles condition
G H J
Source: Baltic Way 2001
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WakeUp
1347 posts
#1 • 2 Y
Y by Adventure10, Mango247
Given a rhombus $ABCD$, find the locus of the points $P$ lying inside the rhombus and satisfying $\angle APD+\angle BPC=180^{\circ}$.
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yetti
2643 posts
#2 • 2 Y
Y by Adventure10, Mango247
Let $ABCD$ be just a parallelogram and $\angle APD + \angle CPB = 180^\circ$ $\Longrightarrow$ circumcircles $(O_1), (O_3)$ of $\triangle APD, \triangle CPB$ are congruent. Translating $\triangle APD$ by $\overrightarrow{AB}$ into a $\triangle CP'B$ creates a cyclic quadrilateral $PBP'C$ and parallelogram $PABP'$ $\Longrightarrow$ circumcircles $(O_2), (O_3)$ of $\triangle BPA, \triangle CPB$ are also congruent. It follows that $\angle PCD = \angle  DAP,$ which means that isogonal conjugate $P^*$ of $P$ WRT $\triangle ACD$ is on perpendicular bisector of $AC.$ As a result, the locus of $P$ is a rectangular circum-hyperbola of the parallelogram $ABCD,$ centered at its diagonal intersection $E.$ If $ABCD$ is a rhombus, this hyperbola degenerates to its diagonals $AC, BD.$
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isaacmeng
113 posts
#3
Y by
What if P is not necessarily in the plane ABCD?
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Nari_Tom
106 posts
#4
Y by
There is a theorem states that if $P$ is a point lies in the plane of $ABCD$ and $\angle APD+\angle CPD=180^{\circ}$, then there exists a isogonal conjugate of $P$. Since $ABCD$ is a rhombus we can easily conclude that $P$ lies on $AC$ or $BD$.
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