1994 AHSME Problems/Problem 11

Problem

Three cubes of volume $1$ , $8$ and $27$ are glued together at their faces. The smallest possible surface area of the resulting configuration is

$\textbf{(A)}\ 36 \qquad\textbf{(B)}\ 56 \qquad\textbf{(C)}\ 70 \qquad\textbf{(D)}\ 72 \qquad\textbf{(E)}\ 74$

1994 AHSME (Problems • Answer Key • Resources)
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