1994 AHSME Problems/Problem 20
Problem
Suppose is a geometric sequence with common ratio and . If is an arithmetic sequence, then is
Solution
Let . Since are an arithmetic sequence, there is a common difference and we have . Dividing through by , we get or, rearranging, . Since we are given , the answer is
See Also
1994 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
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