1999 AIME Problems/Problem 6
Problem
A transformation of the first quadrant of the coordinate plane maps each point to the point The vertices of quadrilateral are and Let be the area of the region enclosed by the image of quadrilateral Find the greatest integer that does not exceed
Solution
First we see that lines passing through and have equations and , respectively. Looking at the points above, we see the equations for and are and , or, after manipulation and , respectively, which are still linear functions. Basically the square of the image points gives back the original points and we could plug them back into the original equation to get the equation of the image lines.
Now take a look at and , which have the equations and . The image equations hence are and , respectively, which are the equations for circles.
To find the area between the circles (actually, parts of the circles), we need to figure out the angle of the arc. This could be done by . So the requested areas are the area of the enclosed part of the smaller circle subtracted from the area enclosed by the part of the larger circle = . Hence the answer is .
See also
1999 AIME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
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