Difference between revisions of "2021 AMC 12A Problems/Problem 1"

 
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We evaluate the given expression to get that <cmath>2^{1+2+3}-(2^1+2^2+2^3)=2^6-(2^1+2^2+2^3)=64-2-4-8=50 \implies \boxed{\text{(B)}}</cmath>
 
We evaluate the given expression to get that <cmath>2^{1+2+3}-(2^1+2^2+2^3)=2^6-(2^1+2^2+2^3)=64-2-4-8=50 \implies \boxed{\text{(B)}}</cmath>
  
==Video Solution==
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==Video Solution (Quick and Easy)==
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https://youtu.be/zxf-CZ97gY0
 +
 
 +
~Education, the Study of Everything
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==Video Solution by Aaron He==
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https://www.youtube.com/watch?v=xTGDKBthWsw&t=8
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==Video Solution by Punxsutawney Phil==
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https://www.youtube.com/watch?v=MUHja8TpKGw
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==Video Solution by Hawk Math==
 
https://www.youtube.com/watch?v=P5al76DxyHY
 
https://www.youtube.com/watch?v=P5al76DxyHY
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== Video Solution by OmegaLearn (Using computation) ==
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https://youtu.be/90OIMAWAwNg
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~ pi_is_3.14
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==Video Solution by TheBeautyofMath==
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https://youtu.be/rEWS75W0Q54
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~IceMatrix
  
 
==See also==
 
==See also==
{{AMC12 box|year=2021|ab=A|before=First problem|num-a=2}}
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{{AMC12 box|year=2021|ab=A|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 22:28, 22 October 2022

Problem

What is the value of\[2^{1+2+3}-(2^1+2^2+2^3)?\]$\textbf{(A) }0 \qquad \textbf{(B) }50 \qquad \textbf{(C) }52 \qquad \textbf{(D) }54 \qquad \textbf{(E) }57$

Solution

We evaluate the given expression to get that \[2^{1+2+3}-(2^1+2^2+2^3)=2^6-(2^1+2^2+2^3)=64-2-4-8=50 \implies \boxed{\text{(B)}}\]

Video Solution (Quick and Easy)

https://youtu.be/zxf-CZ97gY0

~Education, the Study of Everything

Video Solution by Aaron He

https://www.youtube.com/watch?v=xTGDKBthWsw&t=8

Video Solution by Punxsutawney Phil

https://www.youtube.com/watch?v=MUHja8TpKGw

Video Solution by Hawk Math

https://www.youtube.com/watch?v=P5al76DxyHY

Video Solution by OmegaLearn (Using computation)

https://youtu.be/90OIMAWAwNg

~ pi_is_3.14

Video Solution by TheBeautyofMath

https://youtu.be/rEWS75W0Q54

~IceMatrix

See also

2021 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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