Difference between revisions of "2018 AMC 10A Problems/Problem 2"
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<math>\textbf{(D) }</math> Liliane has <math>75\%</math> more soda than Alice. | <math>\textbf{(D) }</math> Liliane has <math>75\%</math> more soda than Alice. | ||
| − | <math>\textbf{(E) }</math> Liliane has | + | <math>\textbf{(E) }</math> Liliane has <math>100\%</math> more than Alice. |
== Solution 1 == | == Solution 1 == | ||
Revision as of 21:23, 8 January 2024
Contents
Problem
Liliane has 
more soda than Jacqueline, and Alice has 
more soda than Jacqueline. What is the relationship between the amounts of soda that Liliane and Alice have?
Liliane has 
more soda than Alice.
Liliane has more soda than Alice.
Liliane has 
more soda than Alice.
Liliane has 
more soda than Alice.
Liliane has 
more than Alice.
Solution 1
Let's assume that Jacqueline has 
gallon(s) of soda. Then Alice has 
gallons and Liliane has 
gallons. Doing division, we find out that 
, which means that Liliane has more soda. Therefore, the answer is 
.
Solution 2
WLOG, lets use 
gallons instead of . When you work it out, you get 
gallons and 
gallons. We have 
is of . Thus, we reach .
~Ezraft
Solution 3
If Jacqueline has 
gallons of soda, Alice has 
gallons, and Liliane has 
gallons. Thus, the answer is -> Liliane has more soda. Our answer is .
~lakecomo224
Video Solution (HOW TO THINK CREATIVELY!)
Education, the Study of Everything
Video Solutions
~savannahsolver
See Also
| 2018 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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