Difference between revisions of "2018 AMC 10A Problems/Problem 10"
Line 34: | Line 34: | ||
Substitute this back into the original equation tog et that <math>\sqrt{49-x^2} = \frac{11}{2}</math>. The answer is <math>\boxed{\textbf{(A) }8}</math> | Substitute this back into the original equation tog et that <math>\sqrt{49-x^2} = \frac{11}{2}</math>. The answer is <math>\boxed{\textbf{(A) }8}</math> | ||
− | ==Solution 5(Jaideep's Difference of Roots Equals Integer Method)[JDRIM] | + | ==Solution 5(Jaideep's Difference of Roots Equals Integer Method)[JDRIM]== |
− | We are given that, | + | We are given that, <math>\sqrt(49-x^2) - \sqrt(25-x^2) = 3</math> |
− | + | We are asked to find, <math>\sqrt(49-x^2) + \sqrt(25-x^2)</math> | |
− | We are asked to find, | + | Notice that these two expressions are conjugates of one another. Therefore, we can find that by multiply these two conjugates by one another we should be able to find that: Difference of Squares Formula: <math>(a+b)(a-b)=a^2-b^2</math> |
− | |||
− | Notice that these two expressions are conjugates of one another. Therefore, we can find that by multiply these two conjugates by one another we should be able to find that: | ||
− | |||
<math>(\sqrt(49-x^2) - \sqrt(25-x^2))(\sqrt(49-x^2) + \sqrt(25-x^2)) = (49-x^2) - (25-x^2) </math> | <math>(\sqrt(49-x^2) - \sqrt(25-x^2))(\sqrt(49-x^2) + \sqrt(25-x^2)) = (49-x^2) - (25-x^2) </math> | ||
<math>\Rightarrow 49-x^2-25+x^2 = 24</math> | <math>\Rightarrow 49-x^2-25+x^2 = 24</math> |
Revision as of 22:31, 24 August 2024
Contents
[hide]Problem
Suppose that real number satisfies What is the value of ?
Solution 1
We let ; in other words, we want to find . We know that Thus, .
~Technodoggo
Solution 2
Let , and . Solving for the constants in terms of x, a , and b, we get , and . Subtracting the second equation from the first gives us . Difference of squares gives us . Since we want to find , and we know , we get , so
~idk12345678
Solution 3
We can substitute for , thus turning the equation into . Moving the to the other side and squaring gives us , solving for gives us 25/4. We substitute this value into the expression they asked us to evaluate giving 8.
~ SAMANTAP
Solution 4
Move to the right to get . Square both sides to get . Simplify to get , or Substitute this back into the original equation tog et that . The answer is
Solution 5(Jaideep's Difference of Roots Equals Integer Method)[JDRIM]
We are given that, We are asked to find, Notice that these two expressions are conjugates of one another. Therefore, we can find that by multiply these two conjugates by one another we should be able to find that: Difference of Squares Formula:
We are already given that the first expression equals 3, thus, our expression now becomes:
Thus, the answer is
~im_space_cadet
~Failure.net
Video Solution (HOW TO THINK CREATIVELY!)
~Education, the Study of Everything
Video Solutions
Video Solution 1
https://youtu.be/ba6w1OhXqOQ?t=1403
~ pi_is_3.14
Video Solution 2
https://youtu.be/zQG70XKAdeA ~ North America Math Contest Go Go Go
Video Solution 3
Video Solution 4
~savannahsolver
See Also
2018 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |