Difference between revisions of "2017 AMC 10B Problems/Problem 6"
m (→Video Solution 2) |
|||
(One intermediate revision by one other user not shown) | |||
Line 13: | Line 13: | ||
~savannahsolver | ~savannahsolver | ||
− | ==Video Solution | + | ==Video Solution by TheBeautyofMath== |
https://youtu.be/XRfOULUmWbY | https://youtu.be/XRfOULUmWbY | ||
~IceMatrix | ~IceMatrix | ||
+ | |||
+ | ==See Also== | ||
{{AMC10 box|year=2017|ab=B|num-b=5|num-a=7}} | {{AMC10 box|year=2017|ab=B|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 19:04, 1 May 2021
Problem
What is the largest number of solid blocks that can fit in a box?
Solution
We find that the volume of the larger block is , and the volume of the smaller block is . Dividing the two, we see that only a maximum of four by by blocks can fit inside the by by block. Drawing it out, we see that such a configuration is indeed possible. Therefore, the answer is .
Video Solution
~savannahsolver
Video Solution by TheBeautyofMath
~IceMatrix
See Also
2017 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.