Difference between revisions of "2006 AMC 10A Problems/Problem 1"
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The answer is <math>(3\cdot 5)+(2\cdot 8) = 15+16=31 \Longrightarrow \mathrm{(A)}</math> | The answer is <math>(3\cdot 5)+(2\cdot 8) = 15+16=31 \Longrightarrow \mathrm{(A)}</math> | ||
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[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] |
Revision as of 01:37, 11 September 2007
Problem
Sandwiches at Joe's Fast Food cost $3 each and sodas cost $2 each. How many dollars will it cost to purchase 5 sandwiches and 8 sodas?
Solution
The answer is
See also
2006 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |