Difference between revisions of "1994 AHSME Problems/Problem 8"
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--Solution by [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=200685 TheMaskedMagician] | --Solution by [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=200685 TheMaskedMagician] | ||
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+ | ==See Also== | ||
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+ | {{AHSME box|year=1994|num-b=7|num-a=9}} | ||
+ | {{MAA Notice}} |
Latest revision as of 16:27, 9 January 2021
Problem
In the polygon shown, each side is perpendicular to its adjacent sides, and all 28 of the sides are congruent. The perimeter of the polygon is . The area of the region bounded by the polygon is
Solution
Since the perimeter is and all of the sides are congruent, the length of each side is . We break the figure into squares as shown below.
We see that there are a total of squares with side length . Therefore, the total area is
--Solution by TheMaskedMagician
See Also
1994 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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