Difference between revisions of "2017 AMC 10B Problems/Problem 4"
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+ | Rearranging, we find <math>3x+y=-2x+6y</math>, or <math>5x=5y\implies x=y</math> | ||
+ | Substituting, we can convert the second equation into <math>\frac{x+3x}{3x-x}=\frac{4x}{2x}=\boxed{\qquad\textbf{(D)}2}</math> | ||
{{AMC10 box|year=2017|ab=B|num-b=3|num-a=5}} | {{AMC10 box|year=2017|ab=B|num-b=3|num-a=5}} | ||
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Revision as of 13:02, 16 February 2017
Problem
Supposed that and are nonzero real numbers such that . What is the value of ?
Solution
Rearranging, we find , or Substituting, we can convert the second equation into
2017 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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All AMC 10 Problems and Solutions |
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