Difference between revisions of "2021 AMC 12A Problems/Problem 19"
Icematrix2 (talk | contribs) (Created page with "==Problem== These problems will not be posted until the 2021 AMC12A is released on Thursday, February 4, 2021. ==Solution== The solutions will be posted once the problems are...") |
|||
| Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
| − | + | How many solutions does the equation <math>\sin \left( \frac{\pi}2 \cos x\right)=\cos \left( \frac{\pi}2 \sin x\right)</math> have in the closed interval <math>[0,\pi]</math>? | |
| + | |||
| + | <math>\textbf{(A) }0 \qquad \textbf{(B) }1 \qquad \textbf{(C) }2 \qquad \textbf{(D) }3\qquad \textbf{(E) }4</math> | ||
| + | |||
==Solution== | ==Solution== | ||
| − | + | {{solution}} | |
| − | + | ||
| − | |||
==See also== | ==See also== | ||
{{AMC12 box|year=2021|ab=A|num-b=18|num-a=20}} | {{AMC12 box|year=2021|ab=A|num-b=18|num-a=20}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:27, 11 February 2021
Problem
How many solutions does the equation 
have in the closed interval ![$[0,\pi]$](http://latex.artofproblemsolving.com/e/c/e/ece27ba559bd93cdf2416aa0f88fc8d7d85e5791.png)
?
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 2021 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 18 |
Followed by Problem 20 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
