Difference between revisions of "2018 AMC 10A Problems/Problem 10"
(→Solution) |
(→Solution) |
||
Line 14: | Line 14: | ||
Given that <math>(\sqrt {49-x^2} - \sqrt {25-x^2})</math> = 3, <math>(\sqrt {49-x^2} + \sqrt {25-x^2}) = \frac {24} {3} = \boxed{(A) 8}</math> | Given that <math>(\sqrt {49-x^2} - \sqrt {25-x^2})</math> = 3, <math>(\sqrt {49-x^2} + \sqrt {25-x^2}) = \frac {24} {3} = \boxed{(A) 8}</math> | ||
+ | |||
+ | Solution by PancakeMonster2004. | ||
== See Also == | == See Also == |
Revision as of 16:38, 8 February 2018
Suppose that real number satisfies
. What is the value of
?
Solution
Given that = 3,
Solution by PancakeMonster2004.
See Also
2018 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.