Difference between revisions of "2006 AMC 10A Problems/Problem 1"

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The answer is <math>(3\cdot 5)+(2\cdot 8) = 15+16=31 \Longrightarrow \mathrm{(A)}</math>
 
The answer is <math>(3\cdot 5)+(2\cdot 8) = 15+16=31 \Longrightarrow \mathrm{(A)}</math>
  
== See Also ==
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== See also ==
*[[2006 AMC 10A Problems]]
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{{AMC10 box|year=2006|ab=A|before=First Question|num-a=2}}
 
 
*[[2006 AMC 10A Problems/Problem 2|Next Problem]]
 
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]

Revision as of 02:37, 11 September 2007

Problem

Sandwiches at Joe's Fast Food cost $3 each and sodas cost $2 each. How many dollars will it cost to purchase 5 sandwiches and 8 sodas?

$\mathrm{(A) \ } 31\qquad \mathrm{(B) \ } 32\qquad \mathrm{(C) \ } 33\qquad \mathrm{(D) \ } 34\qquad \mathrm{(E) \ } 35$

Solution

The answer is $(3\cdot 5)+(2\cdot 8) = 15+16=31 \Longrightarrow \mathrm{(A)}$

See also

2006 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
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All AMC 10 Problems and Solutions