Difference between revisions of "2006 AMC 10A Problems/Problem 6"
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Simplifying the LHS gives <math>49x^2=14x</math>, which then simplifies to <math>7x=2</math>. | Simplifying the LHS gives <math>49x^2=14x</math>, which then simplifies to <math>7x=2</math>. | ||
− | Thus, <math>x=\frac{2}{7} | + | Thus, <math>x=\boxed{\textbf{(B) }\frac{2}{7}}</math>. |
== See also == | == See also == |
Latest revision as of 18:07, 16 December 2021
Problem
What non-zero real value for satisfies ?
Solution
Taking the seventh root of both sides, we get .
Simplifying the LHS gives , which then simplifies to .
Thus, .
See also
2006 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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