Difference between revisions of "2018 AMC 10A Problems/Problem 1"

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== Solution ==  
 
== Solution ==  
Working through the parenthesis with the negative powers results in B 11/7
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Working through the parentheses with the negative powers results in <math>\textbf{(B).}</math>
  
 
== See Also ==
 
== See Also ==
  
{{AMC10 box|year=2018|ab=A|num-b=1|num-a=2}}
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{{AMC10 box|year=2018|ab=A|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 18:37, 8 February 2018

What is the value of \[\left(\left((2+1)^{-1}+1\right)^{-1}+1\right)^{-1}+1?\]$\textbf{(A) } \frac58 \qquad \textbf{(B) }\frac{11}7 \qquad \textbf{(C) } \frac85 \qquad \textbf{(D) } \frac{18}{11} \qquad \textbf{(E) } \frac{15}8$

Solution

Working through the parentheses with the negative powers results in $\textbf{(B).}$

See Also

2018 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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