Difference between revisions of "2021 AMC 12A Problems/Problem 2"

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==Problem==
 
==Problem==
These problems will not be posted until the 2021 AMC12A is released on Thursday, February 4, 2021.
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Under what conditions is <math>\sqrt{a^2+b^2}=a+b</math> true, where <math>a</math> and <math>b</math> are real numbers?
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<math>\textbf{(A) }</math> It is never true.
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<math>\textbf{(B) }</math> It is true if and only if <math>ab=0</math>.
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<math>\textbf{(C) }</math> It is true if and only if <math>a+b\ge 0</math>.
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<math>\textbf{(D) }</math> It is true if and only if <math>ab=0</math> and <math>a+b\ge 0</math>.
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<math>\textbf{(E) }</math> It is always true.
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==Solution==
 
==Solution==
The solutions will be posted once the problems are posted.
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{{solution}}
==Note==
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See [[2021 AMC 12A Problems/Problem 1|problem 1]].
 
 
==See also==
 
==See also==
 
{{AMC12 box|year=2021|ab=A|num-b=1|num-a=3}}
 
{{AMC12 box|year=2021|ab=A|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 16:22, 11 February 2021

Problem

Under what conditions is $\sqrt{a^2+b^2}=a+b$ true, where $a$ and $b$ are real numbers?

$\textbf{(A) }$ It is never true.

$\textbf{(B) }$ It is true if and only if $ab=0$.

$\textbf{(C) }$ It is true if and only if $a+b\ge 0$.

$\textbf{(D) }$ It is true if and only if $ab=0$ and $a+b\ge 0$.

$\textbf{(E) }$ It is always true.

Solution

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See also

2021 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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