Buffon's Needle

by aoum, Mar 30, 2025, 9:23 PM

Buffon’s Needle: A Probability Approach to $\pi$

1. Introduction to Buffon's Needle Problem

Buffon’s Needle is a famous probability problem first posed by Georges-Louis Leclerc, Comte de Buffon, in the 18th century. It is one of the earliest problems in geometric probability and provides a way to estimate the value of $\pi$. The problem is as follows:

Suppose we drop a needle of length $\ell$ onto a floor covered in parallel lines spaced a distance $d$ apart. What is the probability that the needle will cross one of the lines?

https://upload.wikimedia.org/wikipedia/commons/thumb/5/58/Buffon_needle.svg/220px-Buffon_needle.svg.png

The $a$ needle lies across a line, while the $b$ needle does not.

This problem has significant applications in Monte Carlo methods and stochastic geometry.

2. Mathematical Formulation of Buffon’s Needle

Let:
  • $\ell$ be the length of the needle.
  • $d$ be the distance between the parallel lines ($d \geq \ell$).
  • $\theta$ be the acute angle between the needle and the vertical axis.
  • $x$ be the perpendicular distance from the center of the needle to the nearest line.

A crossing occurs if the endpoint of the needle extends past the nearest line, which happens when:

\[
x \leq \frac{\ell}{2} \sin \theta.
\]
Since $x$ is uniformly distributed over $[0, d/2]$, the probability of crossing a line is given by integrating over all possible needle orientations.

3. Computing the Probability

The probability $P$ that the needle crosses a line is given by:

\[
P = \frac{2}{\pi} \cdot \frac{\ell}{d}.
\]
Proof:

The probability density function of $x$ is uniform over $[0, d/2]$, so its probability distribution is:

\[
f(x) = \frac{2}{d}, \quad 0 \leq x \leq \frac{d}{2}.
\]
For a fixed $\theta$, the needle crosses a line when:

\[
x \leq \frac{\ell}{2} \sin \theta.
\]
The probability of this happening, given $\theta$, is:

\[
P(\text{cross} | \theta) = \frac{\ell}{d} \sin \theta.
\]
Since $\theta$ is uniformly distributed in $[0, \pi/2]$, we integrate over all possible angles:

\[
P = \int_0^{\pi/2} \frac{\ell}{d} \sin \theta \cdot \frac{2}{\pi} d\theta.
\]
Evaluating the integral:

\[
P = \frac{\ell}{d} \cdot \frac{2}{\pi} \int_0^{\pi/2} \sin \theta \, d\theta.
\]
Since $\int_0^{\pi/2} \sin \theta \, d\theta = 1$, we obtain:

\[
P = \frac{2}{\pi} \cdot \frac{\ell}{d}.
\]
4. Estimating $\pi$ Using Buffon's Needle

Rearranging the formula, we can estimate $\pi$:

\[
\pi \approx \frac{2\ell}{dP}.
\]
To estimate $\pi$, one can perform an experiment by dropping $N$ needles and counting the number of crossings, $C$. The empirical probability is $P \approx C/N$, giving the approximation:

\[
\pi \approx \frac{2\ell N}{dC}.
\]
This method is a Monte Carlo approach to approximating $\pi$.

5. Generalizations of Buffon's Needle
  • Randomly Oriented Needle on a Grid: If the floor has perpendicular grid lines spaced $d$ apart, the probability of intersection increases and leads to more accurate $\pi$ estimations.
  • Buffon's Noodle: A curved object is dropped onto a plane with parallel lines. The expected number of crossings depends on the total arc length of the noodle.
  • Higher-Dimensional Analogues: Buffon’s problem extends to three dimensions, where it relates to integral geometry.

6. Conclusion

Buffon’s Needle is an elegant probability problem connecting geometry, probability, and number theory. It provides an intuitive way to approximate $\pi$ and serves as an early example of stochastic methods used in modern simulations.

7. YouTube Video: Buffon's Needle


References

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  • Does anyone know how to make the body wider in CSS?

    by aoum, Today at 12:53 AM

  • Thanks! I'm happy to hear that! I'll try to modify the CSS so that the body is wider. How wide would you like it to be?

    by aoum, Today at 12:43 AM

  • This is such a cool blog! Just a suggestion, but I feel like it would look a bit better if the entries were wider. They're really skinny right now, which makes the posts seem a lot longer.

    by Catcumber, Yesterday at 11:16 PM

  • The first few posts for April are out!

    by aoum, Apr 1, 2025, 11:51 PM

  • Sure! I understand that it would be quite a bit to take in.

    by aoum, Apr 1, 2025, 11:08 PM

  • No, but it is a lot to take in. Also, could you do the Gamma Function next?

    by HacheB2031, Apr 1, 2025, 3:04 AM

  • Am I going too fast? Would you like me to slow down?

    by aoum, Mar 31, 2025, 11:34 PM

  • Seriously, how do you make these so fast???

    by HacheB2031, Mar 31, 2025, 6:45 AM

  • I am now able to make clickable images in my posts! :)

    by aoum, Mar 29, 2025, 10:42 PM

  • Am I doing enough? Are you all expecting more from me?

    by aoum, Mar 29, 2025, 12:31 AM

  • That's all right.

    by aoum, Mar 28, 2025, 10:46 PM

  • sorry i couldn't contribute, was working on my own blog and was sick, i'll try to contribute more

    by HacheB2031, Mar 28, 2025, 2:41 AM

  • Nice blog!
    I found it through blogroll.

    by yaxuan, Mar 26, 2025, 5:26 AM

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