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k a July Highlights and 2025 AoPS Online Class Information
jwelsh   0
Jul 1, 2025
We are halfway through summer, so be sure to carve out some time to keep your skills sharp and explore challenging topics at AoPS Online and our AoPS Academies (including the Virtual Campus)!

[list][*]Over 60 summer classes are starting at the Virtual Campus on July 7th - check out the math and language arts options for middle through high school levels.
[*]At AoPS Online, we have accelerated sections where you can complete a course in half the time by meeting twice/week instead of once/week, starting on July 8th:
[list][*]MATHCOUNTS/AMC 8 Basics
[*]MATHCOUNTS/AMC 8 Advanced
[*]AMC Problem Series[/list]
[*]Plus, AoPS Online has a special seminar July 14 - 17 that is outside the standard fare: Paradoxes and Infinity
[*]We are expanding our in-person AoPS Academy locations - are you looking for a strong community of problem solvers, exemplary instruction, and math and language arts options? Look to see if we have a location near you and enroll in summer camps or academic year classes today! New locations include campuses in California, Georgia, New York, Illinois, and Oregon and more coming soon![/list]

MOP (Math Olympiad Summer Program) just ended and the IMO (International Mathematical Olympiad) is right around the corner! This year’s IMO will be held in Australia, July 10th - 20th. Congratulations to all the MOP students for reaching this incredible level and best of luck to all selected to represent their countries at this year’s IMO! Did you know that, in the last 10 years, 59 USA International Math Olympiad team members have medaled and have taken over 360 AoPS Online courses. Take advantage of our Worldwide Online Olympiad Training (WOOT) courses
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0 replies
jwelsh
Jul 1, 2025
0 replies
Challenge: Make as many positive integers from 2 zeros
Biglion   25
N 4 minutes ago by littleduckysteve
How many positive integers can you make from at most 2 zeros, any math operation and cocatination?
New Rule: The successor function can only be used at most 3 times per number
Starting from 0, 0=0
25 replies
Biglion
Jul 2, 2025
littleduckysteve
4 minutes ago
Last Three digit of Fibonacci
Kyj9981   0
5 minutes ago
Source: Hong Kong Preliminary Selection Contest 2020 #20

Consider the fibonacci sequence $1,1,2,3,5,8,13,\dots$. What are the last three digits (from left to right) of the $2020$th term?
0 replies
Kyj9981
5 minutes ago
0 replies
10 Problems
Sedro   9
N 7 minutes ago by fruitmonster97
Title says most of it. I've been meaning to post a problem set on HSM since at least a few months ago, but since I proposed the most recent problems I made to the 2025 SSMO, I had to wait for that happen. (Hence, most of these problems will probably be familiar if you participated in that contest, though numbers and wording may be changed.) The problems are very roughly arranged by difficulty. Enjoy!

Problem 1: An increasing sequence of positive integers $u_1, u_2, \dots, u_8$ has the property that the sum of its first $n$ terms is divisible by $n$ for every positive integer $n\le 8$. Let $S$ be the number of such sequences satisfying $u_1+u_2+\cdots + u_8 = 144$. Compute the remainder when $S$ is divided by $1000$.

Problem 2: Rhombus $PQRS$ has side length $3$. Point $X$ lies on segment $PR$ such that line $QX$ is perpendicular to line $PS$. Given that $QX=2$, the area of $PQRS$ can be expressed as $\tfrac{m}{n}$, where $m$ and $n$ are relatively prime positive integers. Compute $m+n$.

Problem 3: Positive integers $a$ and $b$ satisfy $a\mid b^2$, $b\mid a^3$, and $a^3b^2 \mid 2025^{36}$. If the number of possible ordered pairs $(a,b)$ is equal to $N$, compute the remainder when $N$ is divided by $1000$.

Problem 4: Let $ABC$ be a triangle. Point $P$ lies on side $BC$, point $Q$ lies on side $AB$, and point $R$ lies on side $AC$ such that $PQ=BQ$, $CR=PR$, and $\angle APB<90^\circ$. Let $H$ be the foot of the altitude from $A$ to $BC$. Given that $BP=3$, $CP=5$, and $[AQPR] = \tfrac{3}{7} \cdot [ABC]$, the value of $BH\cdot CH$ can be expressed as $\tfrac{m}{n}$, where $m$ and $n$ are relatively prime positive integers. Compute $m+n$.

Problem 5: Anna has a three-term arithmetic sequence of integers. She divides each term of her sequence by a positive integer $n>1$ and tells Bob that the three resulting remainders are $20$, $52$, and $R$, in some order. For how many values of $R$ is it possible for Bob to uniquely determine $n$?

Problem 6: There is a unique ordered triple of positive reals $(x,y,z)$ satisfying the system of equations \begin{align*} x^2 + 9 &= (y-\sqrt{192})^2 + 4 \\ y^2 + 4 &= (z-\sqrt{192})^2 + 49 \\ z^2 + 49 &= (x-\sqrt{192})^2 + 9. \end{align*}The value of $100x+10y+z$ can be expressed as $p\sqrt{q}$, where $p$ and $q$ are positive integers such that $q$ is square-free. Compute $p+q$.

Problem 7: Let $S$ be the set of all monotonically increasing six-term sequences whose terms are all integers between $0$ and $6$ inclusive. We say a sequence $s=n_1, n_2, \dots, n_6$ in $S$ is symmetric if for every integer $1\le i \le 6$, the number of terms of $s$ that are at least $i$ is $n_{7-i}$. The probability that a randomly chosen element of $S$ is symmetric is $\tfrac{p}{q}$, where $p$ and $q$ are relatively prime positive integers. Compute $p+q$.

Problem 8: For a positive integer $n$, let $r(n)$ denote the value of the binary number obtained by reading the binary representation of $n$ from right to left. Find the smallest positive integer $k$ such that the equation $n+r(n)=2k$ has at least ten positive integer solutions $n$.

Problem 9: Let $p$ be a quadratic polynomial with a positive leading coefficient. There exists a positive real number $r$ such that $r < 1 < \tfrac{5}{2r} < 5$ and $p(p(x)) = x$ for $x \in \{ r,1,  \tfrac{5}{2r} , 5\}$. Compute $p(20)$.

Problem 10: Find the number of ordered triples of positive integers $(a,b,c)$ such that $a+b+c=995$ and $ab+bc+ca$ is a multiple of $995$.
9 replies
Sedro
Jul 10, 2025
fruitmonster97
7 minutes ago
[PMO26 Qualifying II.12] Equality
kae_3   5
N an hour ago by fruitmonster97
The real numbers $x,y$ are such that $x\neq y$ and \[\frac{x}{26-x^2}=\frac{y}{26-y^2}=\frac{xy}{26-(xy)^2}.\]What is $x^2+y^2$?

$\text{(a) }626\qquad\text{(b) }650\qquad\text{(c) }677\qquad\text{(d) }729$

Answer Confirmation
5 replies
kae_3
Feb 21, 2025
fruitmonster97
an hour ago
Trigonometry equation practice
ehz2701   8
N 2 hours ago by vanstraelen
There is a lack of trigonometric bash practice, and I want to see techniques to do these problems. So here are 10 kinds of problems that are usually out in the wild. How do you tackle these problems? (I had ChatGPT write a code for this.). Please give me some general techniques to solve these kinds of problems, especially set 2b. I’ll add more later.

Leaderboard

problem set 1a

problem set 2a

problem set 2b
answers 2b

General techniques so far:

Trick 1: one thing to keep in mind is

[center] $\frac{1}{2} = \cos 36 - \sin 18$. [/center]

Many of these seem to be reducible to this. The half can be written as $\cos 60 = \sin 30$, and $\cos 36 = \sin 54$, $\sin 18 = \cos 72$. This is proven in solution 1a-1. We will refer to this as Trick 1.
8 replies
ehz2701
Jul 12, 2025
vanstraelen
2 hours ago
Permutations of n-degree
red_dog   1
N 2 hours ago by alexheinis
Let $S_n$ be the set of permutations of n-degree and $\sigma\in S_n, \ n\ge 3$. Prove that if $\sigma\alpha=\alpha\sigma, \ \forall \alpha\in S_n$, then $\sigma=e$ (where $e$ is the identical permutation).
1 reply
red_dog
3 hours ago
alexheinis
2 hours ago
Subgroups
red_dog   1
N 2 hours ago by alexheinis
Let $G_1,G_2,\ldots,G_{2002}$ be subgroups of the group $(\mathbb{Q},+)$ and $\mathbb{Q}=G_1\cup G_2\cup\ldots\cup G_{2002}$. Prove that exists $i\in\{1,2,\ldots,2002\}$ such as $G_i=\mathbb{Q}$.
1 reply
red_dog
3 hours ago
alexheinis
2 hours ago
Modular Equality with Coprime Integers
pandev3   5
N 4 hours ago by pandev3
Let $(a)_n = a - n \left\lfloor \frac{a}{n} \right\rfloor$, which is equivalent to $a \mod n$ for any integer $a$.

Let $a_1, a_2, a_3, a_4$ and $n$ be positive integers such that $a_i$ is coprime with $n$ for $i = 1, 2, 3, 4$.

It holds that $(k a_1)_n + (k a_2)_n + (k a_3)_n + (k a_4)_n = 2n$ for $k = 1, 2, \dots, n - 1$.

Prove that $(a_1)_n + (a_j)_n = n$ for some $j$ where $2 \leq j \leq 4$.
5 replies
pandev3
Nov 21, 2024
pandev3
4 hours ago
Concurrency of Lines Involving Altitudes and Circumcenters in a Triangle
JackMinhHieu   0
4 hours ago
Hi everyone,
I recently came across an interesting geometry problem that I'd like to share. It involves a triangle inscribed in a circle, altitudes, points on arcs, and a surprising concurrency involving circumcenters. Here's the problem:
Problem:
Let ABC be an acute triangle inscribed in a circle (O). Let the altitudes AD, BE, CF intersect at the orthocenter H.
Points M and N lie on the minor arcs AB and AC of circle (O), respectively, such that MN // AB.
Let I be the circumcenter of triangle NEC, and J be the circumcenter of triangle MFB.
Prove that the lines OD, BI, and CJ are concurrent.

I find the configuration quite elegant, and I'm looking for different ways to approach the problem — whether it's synthetic, coordinate, vector-based, or inversion.
Any ideas, hints, or full solutions are appreciated. Thank you!
0 replies
JackMinhHieu
4 hours ago
0 replies
question
duckShroom   8
N 5 hours ago by littleduckysteve
Hi everyone,

So I'll give you the short version:

- My school's math program is nearly nonexistent

- The highest freshman course is a 2 year long course combining geometry, alg 2, and precalc. (Most people are struggling and drop out, which is because of the horrible orginaization and the fact they moved middle school back a year so the highest middle school course is alg 1)

- In the first year, we essentially skipped geometry and they'll most likely butcher precalc too

- I'm either the best or second best math student in my year and the year above me, and the school knows. Even so, they won't let me skip the 2nd year of the course I'm in to do AP Calc BC

- I know bits and pieces of precalc from comp stuff, but I need to learn standardized precalc on a deep level out of school without spending money. I know alg 2 well (besides some trig stuff) and geo, well, I haven't actually formally learnt it but I basically know it from the school's 'teachings', khan, and comp stuff.

- I also am reading a calc textbook to learn overall concepts and some basic derivates and all. (https://calculusmadeeasy.org/)

So basically, I need a good free online precalc course or textbook. Thanks for listening to my half rant and half question post thing. All help will be appreciated!

P.S: pm me if you want to be in a AIME study forum
8 replies
duckShroom
Jan 7, 2025
littleduckysteve
5 hours ago
2018 preRMO p22, k=sum of no in partition of {1, 2, ..., 20}, good integer
parmenides51   8
N 5 hours ago by cortex_classes
A positive integer $k$ is said to be good if there exists a partition of $ \{1, 2, 3,..., 20\}$ into disjoint proper subsets such that the sum of the numbers in each subset of the partition is $k$. How many good numbers are there?
8 replies
parmenides51
Aug 8, 2019
cortex_classes
5 hours ago
2018 preRMO p20, product of whose digits equals n^2 -15n -27
parmenides51   11
N 5 hours ago by cortex_classes
Determine the sum of all possible positive integers $n, $ the product of whose digits equals $n^2 -15n -27$.
11 replies
parmenides51
Aug 8, 2019
cortex_classes
5 hours ago
Infinite 6's
BlackPanther007   23
N 5 hours ago by cortex_classes
Let $N=6+66+666+....+666..66$, where there are hundred $6's$ in the last term in the sum. How many times does the digit $7$ occur in the number $N$
23 replies
BlackPanther007
Aug 19, 2018
cortex_classes
5 hours ago
Question about Notation
Quaratinium   4
N 5 hours ago by aidan0626
How are we suppose to know if something like $f^5(x)$ wants the 5th derivative, raise the function to the 5th power, or plug the thing back in the function five times?
4 replies
Quaratinium
Jun 28, 2018
aidan0626
5 hours ago
Very Easy Combinatorics Problem
zeta1   4
N Apr 20, 2025 by ap246
Ali and Veli goes to hunting. The probability that each will successfully hit a duck is $1/2$ on any given shot. During the hunt, Ali shoots $12$ times, and Veli shoots $13$ times. What is the probability that Veli hits more ducks than Ali?

$ 
\textbf{(A)}\ \dfrac 12
\qquad\textbf{(B)}\ \dfrac{13}{25}
\qquad\textbf{(C)}\ \dfrac{13}{24}
\qquad\textbf{(D)}\ \dfrac{7}{13}
\qquad\textbf{(E)}\ \dfrac{3}{4}
$
4 replies
zeta1
Apr 20, 2025
ap246
Apr 20, 2025
Very Easy Combinatorics Problem
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zeta1
5 posts
#1
Y by
Ali and Veli goes to hunting. The probability that each will successfully hit a duck is $1/2$ on any given shot. During the hunt, Ali shoots $12$ times, and Veli shoots $13$ times. What is the probability that Veli hits more ducks than Ali?

$ 
\textbf{(A)}\ \dfrac 12
\qquad\textbf{(B)}\ \dfrac{13}{25}
\qquad\textbf{(C)}\ \dfrac{13}{24}
\qquad\textbf{(D)}\ \dfrac{7}{13}
\qquad\textbf{(E)}\ \dfrac{3}{4}
$
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expiredcraker
1 post
#2 • 1 Y
Y by zeta1
zeta1 wrote:
Ali and Veli goes to hunting. The probability that each will successfully hit a duck is $1/2$ on any given shot. During the hunt, Ali shoots $12$ times, and Veli shoots $13$ times. What is the probability that Veli hits more ducks than Ali?

$ 
\textbf{(A)}\ \dfrac 12
\qquad\textbf{(B)}\ \dfrac{13}{25}
\qquad\textbf{(C)}\ \dfrac{13}{24}
\qquad\textbf{(D)}\ \dfrac{7}{13}
\qquad\textbf{(E)}\ \dfrac{3}{4}
$
This post has been edited 1 time. Last edited by expiredcraker, Apr 21, 2025, 1:44 AM
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Bummer12345
188 posts
#3 • 1 Y
Y by zeta1
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franklin2013
357 posts
#4 • 1 Y
Y by zeta1
Doing a little casework to get a handle on this question:
Case 1: Ali hits $0$ ducks
The probability of this happening is
$$\binom{12}{0}\left(\frac{1}{2}\right)^{12}.$$Now, we find the probability that Veli shoots at least $1$ duck. The probability of this happening is
$$\sum^{13}_{i=1}\left(\frac{1}{2}\right)^{13}\binom{13}{i}.$$Therefore, the probability that Veli hits more ducks than Ali when Ali hits $0$ ducks is:
$$\binom{12}{0}\left(\frac{1}{2}\right)^{12}\left(\sum^{13}_{i=1}\left(\frac{1}{2}\right)^{13}\binom{13}{i}\right)$$Full answer:
We can generalize our answer from Case 1 to find the full answer. The probability that Veli hits more ducks than Ali is
$$\sum^{12}_{i=0}\left(\binom{12}{i}\left(\frac{1}{2}\right)^{12}\left(\sum^{13}_{j=i+1}\left(\frac{1}{2}\right)^{13}\binom{13}{j}\right)\right)=\sum^{12}_{i=0}\left(\binom{12}{i}\left(\frac{1}{2}\right)^{12}\left(\sum^{13}_{j=0}\left(\frac{1}{2}\right)^{13}\binom{13}{j}-\sum^{i}_{j=0}\left(\frac{1}{2}\right)^{13}\binom{13}{j}\right)\right).$$
I'll finish the solution later but the final answer is $\boxed{\textrm{(A)}}$
This post has been edited 1 time. Last edited by franklin2013, Apr 20, 2025, 2:29 PM
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ap246
1796 posts
#5 • 1 Y
Y by zeta1
Let $a$ and $v$ be the number of ducks Ali and Veli have hit after both have taken 12 shots, respectively. Let $P(\checkmark)$ be the probability Veli wins overall. We see that: $$P(\checkmark) = P(\checkmark\vert a > v)P(a>v) + P(\checkmark\vert a = v)P(a=v) + P(\checkmark\vert a<v)P(a<v)$$We know all of the conditional probabilities already. If Ali is ahead on Veli's 13th shot, Veli cannot beat Ali, so $P(\checkmark\vert a > v) = 0$. If they are tied going into the 13th shot, Veli has a $\frac12$ chance of winning, so $P(\checkmark\vert a = v) = \frac12$. If Veli is already ahead going into the 13th shot, she wins no matter what, so $P(\checkmark\vert a<v) = 1$. If we then let $P(v>a) = P(a>v) = p$, then $P(a=v) = 1-2p$. Therefore, our final answer is $p + \frac12(1-2p) = \frac12 \implies \boxed{\textrm{(A)}}$
This post has been edited 2 times. Last edited by ap246, Apr 20, 2025, 3:32 PM
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