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k a March Highlights and 2025 AoPS Online Class Information
jlacosta   0
Mar 2, 2025
March is the month for State MATHCOUNTS competitions! Kudos to everyone who participated in their local chapter competitions and best of luck to all going to State! Join us on March 11th for a Math Jam devoted to our favorite Chapter competition problems! Are you interested in training for MATHCOUNTS? Be sure to check out our AMC 8/MATHCOUNTS Basics and Advanced courses.

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Do you have plans this summer? There are so many options to fit your schedule and goals whether attending a summer camp or taking online classes, it can be a great break from the routine of the school year. Check out our summer courses at AoPS Online, or if you want a math or language arts class that doesn’t have homework, but is an enriching summer experience, our AoPS Virtual Campus summer camps may be just the ticket! We are expanding our locations for our AoPS Academies across the country with 15 locations so far and new campuses opening in Saratoga CA, Johns Creek GA, and the Upper West Side NY. Check out this page for summer camp information.

Be sure to mark your calendars for the following events:
[list][*]March 5th (Wednesday), 4:30pm PT/7:30pm ET, HCSSiM Math Jam 2025. Amber Verser, Assistant Director of the Hampshire College Summer Studies in Mathematics, will host an information session about HCSSiM, a summer program for high school students.
[*]March 6th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar on Math Competitions from elementary through high school. Join us for an enlightening session that demystifies the world of math competitions and helps you make informed decisions about your contest journey.
[*]March 11th (Tuesday), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS Chapter Discussion MATH JAM. AoPS instructors will discuss some of their favorite problems from the MATHCOUNTS Chapter Competition. All are welcome!
[*]March 13th (Thursday), 4:00pm PT/7:00pm ET, Free Webinar about Summer Camps at the Virtual Campus. Transform your summer into an unforgettable learning adventure! From elementary through high school, we offer dynamic summer camps featuring topics in mathematics, language arts, and competition preparation - all designed to fit your schedule and ignite your passion for learning.[/list]
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0 replies
jlacosta
Mar 2, 2025
0 replies
Sequence with condition on million consecutive terms
jbaca   13
N a few seconds ago by Haris1
Source: 2021 Iberoamerican Mathematical Olympiad, P3
Let $a_1,a_2,a_3, \ldots$ be a sequence of positive integers and let $b_1,b_2,b_3,\ldots$ be the sequence of real numbers given by
$$b_n = \dfrac{a_1a_2\cdots a_n}{a_1+a_2+\cdots + a_n},\ \mbox{for}\ n\geq 1$$Show that, if there exists at least one term among every million consecutive terms of the sequence $b_1,b_2,b_3,\ldots$ that is an integer, then there exists some $k$ such that $b_k > 2021^{2021}$.
13 replies
jbaca
Oct 20, 2021
Haris1
a few seconds ago
Symmetric inequality FTW
Kimchiks926   20
N 13 minutes ago by Marcus_Zhang
Source: Latvian TST for Baltic Way 2020 P1
Prove that for positive reals $a,b,c$ satisfying $a+b+c=3$ the following inequality holds:
$$ \frac{a}{1+2b^3}+\frac{b}{1+2c^3}+\frac{c}{1+2a^3} \ge 1 $$
20 replies
Kimchiks926
Oct 17, 2020
Marcus_Zhang
13 minutes ago
Interesting problem
V-217   0
15 minutes ago
On the side $(BC)$ of the triangle $ABC$ consider a mobile point $M$. Let $B'$ the orthogonal projection of $B$ on $AM$. If the mobile points $N\in (BB'$ and $P\in (AM$ are such that $ANPC$ is a paralellogram, find the locus of point $P$ when $M$ goes through $BC$.
0 replies
V-217
15 minutes ago
0 replies
Equilateral triangle fun
navi_09220114   6
N 30 minutes ago by wassupevery1
Source: Own. Malaysian IMO TST 2025 P8
Let $ABC$ be an equilateral triangle, and $P$ is a point on its incircle. Let $\omega_a$ be the circle tangent to $AB$ passing through $P$ and $A$. Similarly, let $\omega_b$ be the circle tangent to $BC$ passing through $P$ and $B$, and $\omega_c$ be the circle tangent to $CA$ passing through $P$ and $C$.

Prove that the circles $\omega_a$, $\omega_b$, $\omega_c$ has a common tangent line.

Proposed by Ivan Chan Kai Chin
6 replies
navi_09220114
6 hours ago
wassupevery1
30 minutes ago
Inequalities from SXTX
sqing   11
N 3 hours ago by byron-aj-tom
T702. Let $ a,b,c>0 $ and $ a+2b+3c=\sqrt{13}. $ Prove that $$ \sqrt{a^2+1} +2\sqrt{b^2+1} +3\sqrt{c^2+1} \geq 7$$S
T703. Let $ a,b $ be real numbers such that $ a+b\neq 0. $. Find the minimum of $ a^2+b^2+(\frac{1-ab}{a+b} )^2.$
T704. Let $ a,b,c>0 $ and $ a+b+c=3. $ Prove that $$ \frac{a^2+7}{(c+a)(a+b)} + \frac{b^2+7}{(a+b)(b+c)} +\frac{c^2+7}{(b+c)(c+a)}  \geq 6$$S
11 replies
sqing
Feb 18, 2025
byron-aj-tom
3 hours ago
Number Theory
Foxellar   3
N 3 hours ago by rchokler
Evaluate the following expression:

\[
19^{17^{15^{13^{11^{9^{7^{5^3}}}}}}} \mod 100
\]
3 replies
Foxellar
Today at 11:43 AM
rchokler
3 hours ago
Expected Vakue of coins around table
ehz2701   1
N 3 hours ago by ap246
There are $n$ people around in a circle, who at $t=0\text{ sec}$ each have one penny. After each second every person gives deals penny they have to the left or right, or keeps that penny with equal probability. What is the expected value of seconds such that one person has all $n$ pennies? (Express answer in terms of $n$).

I think the answer is $3^{n-1}$ but I’m not sure. Purely guessing.

For $n=3$ the answer is $9$ because from any arrangement there is exactly $1$ way to get to any of the other arrangements (consider the problem from the coin’s perspective as they switch humans. Label the humans $0,1,2$. Therefore the initial arrangement is $0,1,2$. Every time we add or subtract $1$ or leave alone each of the numbers. We can only obtain, say, $2, 2, 2$ (where every coin is in the second person’s hand), in one way: that is $-1, +1, 0$. This is true for every possible arrangement of coins from any possible arrangement of coins. Hence the probability of landing on $1, 1, 1$ or $2, 2, 2$ or $3, 3, 3$ is $\frac{1}{9}$ and the answer is $9$.
1 reply
ehz2701
Today at 2:49 AM
ap246
3 hours ago
Imo 2026
Musashi123   3
N 4 hours ago by giangtruong13
Find x,y,z positive interger such that
x+y+z=xy +yz +xz
3 replies
Musashi123
Today at 9:45 AM
giangtruong13
4 hours ago
Discord Server
mathprodigy2011   8
N 5 hours ago by Demetri
Theres a server where we are all like discussing problems+helping each other practice. Hopefully you guys can join.

https://discord.gg/6hN3w4eK
8 replies
mathprodigy2011
Yesterday at 11:00 PM
Demetri
5 hours ago
number theory
eric201291   2
N 5 hours ago by eric201291
Find all the x, y integers, that x^2+108=y^3.
2 replies
eric201291
Yesterday at 10:45 PM
eric201291
5 hours ago
a^{2000}+b^{2000}=a^{1998}+b^{1998} (Greece Junior 1999 p1)
parmenides51   2
N Today at 12:20 PM by ali123456
Show that if $a,b$ are positive real numbers such that $a^{2000}+b^{2000}=a^{1998}+b^{1998}$ then $a^2+b^2 \le 2$.
2 replies
parmenides51
Mar 17, 2020
ali123456
Today at 12:20 PM
High School Math
Foxellar   1
N Today at 11:07 AM by Sivin
\[
\textbf{Problem:}
\]
Let \( r_1, r_2, \dots, r_{20} \) be the roots of the polynomial

\[
P(x) = x^{20} - 7x^3 + 1.
\]
Find the value of

\[
S = \frac{1}{r_1^2 + 1} + \frac{1}{r_2^2 + 1} + \dots + \frac{1}{r_{20}^2 + 1}
\]
in the form \( \frac{m}{n} \), where \( m \) and \( n \) are coprime positive integers. Determine the value of \( m + 2n \).
1 reply
Foxellar
Today at 10:14 AM
Sivin
Today at 11:07 AM
An inequality
jokehim   3
N Today at 10:58 AM by Indpsolver
Let $a,b,c \in \mathbb{R}: a+b+c=3$ then prove $$\color{black}{\frac{a^2}{a^{2}-2a+3}+\frac{b^2}{b^{2}-2b+3}+\frac{c^2}{c^{2}-2c+3}\ge \frac{3}{2}.}$$
3 replies
jokehim
Yesterday at 3:05 PM
Indpsolver
Today at 10:58 AM
Tam giác nội tiếp
chunchun.math.2010   1
N Today at 4:57 AM by giratina3
Bài 1:Cho tam giác abc nội tiếp đường tròn (o), đường cao ad (d ∈ bc). qua a kẻ đường song song với bc cắt (o) tại t. chứng minh rằng dt đi qua trọng tâm của tam giác abc.
Bài 2: Cho tứ giác ngoại tiếp abcd. p là một điểm bất kì trên cd. j, k, l lần lượt là tâm đường tròn nội tiếp của các tam giác apb, apd, bpc. chứng minh rằng ∠ajk + ∠bjl = 180°.
1 reply
chunchun.math.2010
Today at 2:29 AM
giratina3
Today at 4:57 AM
Numbers from 1 to 15 with rare properties
hectorleo123   1
N Thursday at 9:24 PM by EmersonSoriano
Source: 2015 Peru Cono Sur TST P2
Let $a, b, c$ and $d$ be elements of the set $\{ 1, 2, 3,\ldots , 2014, 2015 \}$ such that $a < b < c < d$, $a + b$ is a divisor of $c + d$, and $a + c$ is a divisor of $b + d$. Determine the largest value that $a$ can take.
1 reply
hectorleo123
Jul 10, 2023
EmersonSoriano
Thursday at 9:24 PM
Numbers from 1 to 15 with rare properties
G H J
G H BBookmark kLocked kLocked NReply
Source: 2015 Peru Cono Sur TST P2
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hectorleo123
338 posts
#1
Y by
Let $a, b, c$ and $d$ be elements of the set $\{ 1, 2, 3,\ldots , 2014, 2015 \}$ such that $a < b < c < d$, $a + b$ is a divisor of $c + d$, and $a + c$ is a divisor of $b + d$. Determine the largest value that $a$ can take.
This post has been edited 1 time. Last edited by hectorleo123, Jul 10, 2023, 10:20 PM
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EmersonSoriano
13 posts
#2
Y by
Since $a+b \mid c+d$ and $a+c \mid b+d$, it follows that $a+b$ and $a+c$ divide $a+b+c+d$. It is clear that $a+b+c+d$ cannot be less than or equal to $2(a+c)$ and so $a+b<a+c$, so
$$
a+b\leq \frac{a+b+c+d}{4} \quad \text{and} \quad a+c\leq \frac{a+b+c+d}{3},
$$from which we obtain that $8a+5b\leq 3d$. Then,
$$
13a+5=8a+5(a+1)\leq 8a+5b\leq 3d\leq 3\cdot 2015,
$$deducing that $a\leq 464$. To ensure that $464$ is the maximum possible value for $a$, it is sufficient to show the following example:
$$
a=464, \quad b=466, \quad c=776, \quad \text{and} \quad d=2014.
$$
This post has been edited 3 times. Last edited by EmersonSoriano, Thursday at 9:32 PM
Reason: "I changed a letter."
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