Stay ahead of learning milestones! Enroll in a class over the summer!

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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

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[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Apr 2, 2025
0 replies
A stronger result of KhuongTrang
Nguyenhuyen_AG   0
40 minutes ago
Let $a, \ b, \ c$ are non-negative real numbers such that $ab+bc+ca=2.$ Prove that
\[\sqrt{a^2+6ab}+\sqrt{b^2+6bc}+\sqrt{c^2+6ca} \ge 5\sqrt{1 + \frac{153abc}{50(a+b+c)}}.\]hide
0 replies
Nguyenhuyen_AG
40 minutes ago
0 replies
Don't bite me for this straightforward sequence
Assassino9931   5
N an hour ago by MathLuis
Source: Bulgaria National Olympiad 2025, Day 1, Problem 1
Determine all infinite sequences $a_1, a_2, \ldots$ of real numbers such that
\[ a_{m^2 + m + n} = a_{m}^2 + a_m + a_n\]for all positive integers $m$ and $n$.
5 replies
Assassino9931
Yesterday at 1:47 PM
MathLuis
an hour ago
Cyclic Points
IstekOlympiadTeam   38
N 2 hours ago by eg4334
Source: EGMO 2017 Day1 P1
Let $ABCD$ be a convex quadrilateral with $\angle DAB=\angle BCD=90^{\circ}$ and $\angle ABC> \angle CDA$. Let $Q$ and $R$ be points on segments $BC$ and $CD$, respectively, such that line $QR$ intersects lines $AB$ and $AD$ at points $P$ and $S$, respectively. It is given that $PQ=RS$.Let the midpoint of $BD$ be $M$ and the midpoint of $QR$ be $N$.Prove that the points $M,N,A$ and $C$ lie on a circle.
38 replies
IstekOlympiadTeam
Apr 8, 2017
eg4334
2 hours ago
2025 Caucasus MO Seniors P3
BR1F1SZ   1
N 2 hours ago by iliya8788
Source: Caucasus MO
A circle is drawn on the board, and $2n$ points are marked on it, dividing it into $2n$ equal arcs. Petya and Vasya are playing the following game. Petya chooses a positive integer $d \leqslant n$ and announces this number to Vasya. To win the game, Vasya needs to color all marked points using $n$ colors, such that each color is assigned to exactly two points, and for each pair of same-colored points, one of the arcs between them contains exactly $(d - 1)$ marked points. Find all $n$ for which Petya will be able to prevent Vasya from winning.
1 reply
BR1F1SZ
Mar 26, 2025
iliya8788
2 hours ago
No more topics!
2011/12 BrMO
AMC13   7
N Apr 12, 2016 by AMC13
Source: 2011/12 British Mathematical Olympiad Round 1
Consider a circle $S$. The point $P$ lies outside $S$ and a line is drawn through $P$, cutting $S$ at distinct points $X$ and $Y$ . Circles $S_1$ and $S_2$ are drawn through $P$ which are tangent to $S$ at $X$ and $Y$ respectively.Prove that the difference of the radii of $S_1$ and $S_2$ is independent of the positions of $P$,$ X$ and $Y$ .
7 replies
AMC13
Apr 11, 2016
AMC13
Apr 12, 2016
2011/12 BrMO
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G H BBookmark kLocked kLocked NReply
Source: 2011/12 British Mathematical Olympiad Round 1
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AMC13
423 posts
#1 • 2 Y
Y by Adventure10, Mango247
Consider a circle $S$. The point $P$ lies outside $S$ and a line is drawn through $P$, cutting $S$ at distinct points $X$ and $Y$ . Circles $S_1$ and $S_2$ are drawn through $P$ which are tangent to $S$ at $X$ and $Y$ respectively.Prove that the difference of the radii of $S_1$ and $S_2$ is independent of the positions of $P$,$ X$ and $Y$ .
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AMC13
423 posts
#2 • 2 Y
Y by Adventure10, Mango247
anyone with a solution???
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SohamSchwarz119
758 posts
#3 • 4 Y
Y by AMC13, CmIMaTh, dgmath97, Adventure10
Construction: $PO_{2},OO_{2},PO_{1}$ and $O_{1}X$ are joined.

Proof: As the two circles $S$ and $S_{2}$ are tangent to each other, $O,Y,O_{2}$ are collinear.

Now, $\angle XYO=\angle XPO_{1}= \angle YXO \implies OO_{2} \parallel PO_{1}$

Also, $\angle O_{2}PY= \angle OXY \implies OO_{1} \parallel PO_{2}$

Therefore $OO_{1}PO_{2}$ is a parallelogram.

Thus, we have $O_{1}X-O_{2}P=O_{1}X-OO_{1}=OX=r$ which is independent of the positions of $P,X,Y$ (proved)
Attachments:
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AMC13
423 posts
#4 • 2 Y
Y by Adventure10, Mango247
please tell the reasons for this 2 claims.... :help:

1.$\angle XYO=\angle XPO_{1}= \angle YXO$

2.$\angle O_{2}PY= \angle OXY $
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SohamSchwarz119
758 posts
#5 • 2 Y
Y by CmIMaTh, Adventure10
AMC13 wrote:
please tell the reasons for this 2 claims.... :help:

1.$\angle XYO=\angle XPO_{1}= \angle YXO$

2.$\angle O_{2}PY= \angle OXY $

The first claim is due to the fact that $OX=OY$ and $O_{1}X=O_{1}P$ which are both radii.

The second claim is due to $OX=OY$(radii). so, $\angle YXO=\angle XYO$ and similarly $O_{2}Y=O_{2}P$ (radii) and so $\angle O_{2}PY= \angle O_{2}YP$

But $\angle O_{2}YP=\angle XYO$(vertically opposite)
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AMC13
423 posts
#6 • 2 Y
Y by Adventure10, Mango247
Thanx I found out the reason just now and was about to delete my post but u posted.

Also while writing this proof in an olympiad is this claim enough or do we need to show why is it show?
SohamSchwarz119 wrote:
Proof: As the two circles $S$ and $S_{2}$ are tangent to each other, $O,Y,O_{2}$ are collinear.
This post has been edited 1 time. Last edited by AMC13, Apr 12, 2016, 3:40 AM
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SohamSchwarz119
758 posts
#7 • 2 Y
Y by AMC13, Adventure10
It is enough for Olympiads, I presume
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AMC13
423 posts
#8 • 1 Y
Y by Adventure10
SohamSchwarz119 wrote:
It is enough for Olympiads, I presume

Thanx for helping. :-D

U may also help me out with the other questions I have posted.
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